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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the area of these quadrilaterals:: 4.5 cm 10 cm |
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| 2. |
ns that name the given number are given. Fepukalent ractions2 46 S714 21n zs |
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Answer» Please post a clear picture! |
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| 3. |
) ABcp i o poralidoqon . aa s Kicded ok ®odD b So kholt AP: PR = 312 o~d CR:OD =%\ =%था कल इनकी. न कि R, फेज prove Aok ARz "’_3 M |
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Answer» ΔAPR ∼ ΔCQR (AA) ⇒AP/CQ=PR/QR=AR/CR ⇒AP/CQ=AR /CR & AP= 3/5 AB ⇒3AB/5CQ=AR/CR& CQ= 4/5 CD = 4/5 AB ⇒AR/CR= 3/4 ⇒CR/AR= 4/3 CR+AR/AR= 4 +1/3 ⇒AC/AR= 7/3 ⇒AR = 3/7 AC Hence proved Like my answer if you find it useful! |
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| 4. |
After gaining 15 kg , Nisha weights 60 kg. What was her previous weight |
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Answer» let nisha's previous weight be x x+15 =60so , 60-15=x x= 45kgs |
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| 5. |
1. A person standing on the bank of a river observes that the angle subtended by a tree on theopposite bank is 60°. When he retreats 20m from the bank, he finds the angle to be 300. Find theheight of the tree and the breadth of the river. |
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| 6. |
9. A wallpaper, 312 m long and 25 cm wide is required tocover the walls of a room. Length of the room is 7 m andits breadth is twice its height. Determine the height of theroom. |
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| 7. |
If 272/381-1/2 3x, the value of x isв.ОC. ID. 2 |
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Answer» Like my answer if you find it useful! your answers is. superb 1 |
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| 8. |
17 A person standing on the bank of a river observes that the angle subtended by a treeon the opposite bank is 60% when he retires 20m from the bank, he finds the angle tobe 300. Find the height of the tree and the breadth of the river. |
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| 9. |
101 और 999 के बीच की सभी सम संख्याओं का |
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Answer» A = 110 {first number to be divided by 2 and 5}difference d =10an=990 {last no to be divided by 2 and 5}an = a + {n - 1}d990 = 110 + 10n -10880 + 10 = 10n890 = 10nn = 89 |
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| 10. |
13. Kanchan scored 473 marks out of 550 and Rohanscored 553 marks out of 700. Whose performanceis better? |
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| 11. |
16.Rationalise the denominator of7+312 |
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Answer» solve full way |
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| 12. |
The diagonals of a rhornbus are 7.5 cm and 12 cm. Findits area. |
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| 13. |
How many terms divisible by 2 or 5 between 101 to 999 |
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Answer» no. divisible by 2&5 must be divisible by 10Form an AP of natural number present between 101 & 999 AP = 110, 120, 130,............, 990from the AP we concludeda = 110d = 10nth term of the AP = 990a+(n-1)d=990110+(n-1)10=990(n-1)10=990-110(n-1)= 880/10n-1=88n=88+1n=89natural number present between 101 & 109 = 89 |
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| 14. |
321 312 26463 |
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Answer» Product of extreme = product of mean Let the fourth no. be x then 121*x = 12*64 x = 12*64/121 x = 6.3 Like my answer if you find it useful! |
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| 15. |
2 less than 3 digit largest number is ...... |
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Answer» 3 digits largest number = 9992 less than 999= 997 2 less than 3digit largest number is 997 3 digit largest number = 999less 2 999- 2_______ 997 the answer is 999-2=997 997 is the correct answer |
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| 16. |
21312x 714 |
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| 17. |
all7 312 r |
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| 18. |
Convert into centimetres.a) 312 mm |
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Answer» 31. 2cm is the right answer 1 mm = 0.1cm312 mm = 31.2 cm thank you for giving me the answer |
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| 19. |
Convert into centimetresa) 312 mm |
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Answer» 1 mm = 0.1 cm312 mm = 31.2 cm |
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| 20. |
The value of 324 +381 - 3192 , is(1) 33(3) 3(4) of these(2) 13 |
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Answer» 2*2*3*2= 243*3*3*3= 812*2*2*2*2*2*3now2(3)^1/3+3(3)^1/3-2*2*(3)^1/3 |
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| 21. |
Q.34 The jatio of three numbers is 2:3:4. Sum of theirQ,34 The atio of threecubes is 33957 then the largest number is-(A) 28(C) 32(B) 21(D) 14 |
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Answer» Let the numbers be 2x, 3x and 4xsum of cubes = 33957⇒(2x)³ + (3x)³ + (4x)³ = 33957⇒8x³ + 27x³ + 64x³ = 33957⇒99x³ = 33957⇒x³ = 33957/99 = 343⇒x =∛343 = 7 Numbers are:2x = 2×7 = 143x = 3×7 = 214x = 4×7 = 28 |
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| 22. |
(-381) + (-229) |
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Answer» your questions answer is 610 |
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| 23. |
10 7 1Find the decimal expansins of and n381 |
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Answer» solve this question 7043 7781 |
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| 24. |
2,दो संख्याओं a और 18 का ल. स. 36 तथा म. स. 2 है, तो a का मान है। |
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Answer» a=4 is right answer 18 × a = 36 × 2 a = 36 × 2/18 = 4 |
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| 25. |
EXAMPLE: यदि दो संख्याओं का ल. स. 40 तथा म. स. 2 हो एवं पहलीसंख्या 10 हो, तो दूसरी संख्या ज्ञात करें। |
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Answer» दूसरी संख्या =ल०स०×म०स०/पहली संख्या=40×2/1080/10=8 ans yadi do sakhyaao ka l.c.m. 40 tatha h.c.f. 2ho ev pahali sankhya 10 ho to dusri sankhya 8ho ga दुसरी संख्या ल,से *म से पहली संख्या40*2/1080/108answer |
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| 26. |
Convert into centimea) 312 mm |
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Answer» 1 mm = 0.1 cmthen 312 mm = 31.2 cm |
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| 27. |
Find natural numbers between 101 and 999 which aredivisible by both 2 and 5. |
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| 28. |
Find the number of natural numbers between 101 and 999 which are divisible by both 2and 5. |
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| 29. |
(iii)Find the number of natural numbers between 101 and 999 which are divisible by both 2 and 5. |
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| 30. |
Thudigit largest number is?a) 999(b) 11110) 888Id 1000 |
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Answer» 999(a) is write answer |
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| 31. |
20Maths WORK SHEEchapter & IntegeSimplify -63+145 9of+46+ |
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Answer» -47 is the right answer -47/45 = 3/5 + 4/9 [-6/5] + [-8/9] = 3/5 + 4/9 –6/5 –8/9 = 27+20 —6/5 —8/9___________________ 45 = 47—94 _________ 45 = —57 _______answer.. 45 |
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| 32. |
. From a pack of 52cards two are drawn one by one withoutreplacement Find the probability that both of them are kings. |
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| 33. |
without replacement, find the pcobabliltyFind the probability thato beth the tickets drawn have prime numbersn none of the ticket drawn has prime number.16. A bag contains 20 tickets mumbered from 1 to 20. Two tickets are drawn simultaneoualyll shuffled pack of 52 cards one after the |
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Answer» iska part (ii) |
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| 34. |
Three cards are drawn successively without replacement from 52cards. What is the probability that first two cards are kings and thirdcard drawn is an ace? |
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| 35. |
4.Draw an angle of 50° with the help of a protractor. Draw a ray bisecting this angle. |
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| 36. |
4. Draw an angle of 50° with the help of a protractor. Draw a ray bisecting thisan |
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| 37. |
F. Fill in the symbol <> or=.1) 314448 2) 3184) 901 910 5) 4563816543) 500 5186) 949949 |
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Answer» 1) <2) <3) <4) <5) <6) = |
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| 38. |
Multiply:i. 3V28 by 277(ii)318 by 312bilida |
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Answer» (1) 3root(28) * 2root(7)= 3*2*root(7) * 2*root(7)= 12*7= 84 (2) 3root(8) * 3root(2)= 3*2root(2) * 3root(2)= 18*2= 36 |
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| 39. |
नगोठाशूखक (मएयों |6x+15)-c& 3x farm =t 3F;_. .-.:.< :.. _ ०५ |
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Answer» (6x + 15) / 3x = 2 + 5/x PLEASE HIT THE LIKE BUTTON |
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| 40. |
Oo |
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Answer» Addition:3+4+8=7+8=15 thanks |
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| 41. |
64 x^{4}-81 y^{4} के मुणनखण्ड कीजि |
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| 42. |
7.इनमें से कौन बहुपद मानक रूप में है?(a)3x + 2x2 + V2x4-5x6 (b)3 +t - t+t (c)x' - x +5x1+7 (d)3x +5x2-6x-7 |
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Answer» d (3x²+5x²-6x-7) bahupad h option (d) bahupad h |
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| 43. |
81*x^4 - 256*y^4 |
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| 44. |
(ii) Write the predecessor of each number. One has been done for you.318530- 245-709- 1011000999 |
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Answer» a) 318 is the correct answer a. Predecessor of -245 = 246b. Predecessor of 530 = 529c. Predecessor of -709 = 710d. Predecessor of 1000 = 999e. Predecessor of -101 = -102f. Predecessor of 999 = 998 a)318-245,, b) 529 , 530 c) 710- 709 d) 1000-999 e) -101-102; f) 999-998 in predecessor we have to minus 1b=529c=708d=999e=100f=998 |
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| 45. |
19. Simplify: 4/81 - 8 1343 + 15 232 + 1225 |
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Answer» -8 is the correct answer of the given question |
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| 46. |
3. In dividing a number by 585, a student employed the method of shรถrt division. iithe number successively by 5, 9 and 13 (factors of 585) and got the remainders 4, 8, 12respectively. If he had divided the number by 585, the remainder would have been |
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Answer» Let's take a look at your question. The question states that when the number is divided by 5 the remainder is 4.Let the number be x and q be the quotient, then x=5p+4−−−(i)x=5p+4−−−(i) The successive division by 9 result into the remainder 8. p=9q+8−−−(ii)p=9q+8−−−(ii) Similarly, the successive division by 13 result into the remainder 12. q=13r+12−−−(iii)q=13r+12−−−(iii) Now substitute value of q in eq(ii) p=9q+8p=9q+8 p=9(13r+12)+8p=9(13r+12)+8 p=117r+108+8p=117r+108+8 p=117r+116p=117r+116 Now replace this value of p in eq(i) x=5p+4x=5p+4 x=5(117r+116)+4x=5(117r+116)+4 x=585r+580+4x=585r+580+4 x=585r+584x=585r+584 Which represents that 585 is the divisor, r is the quotient and 584 is the remainder.Therefore, when the number is divided by 585, the remainder is 584. |
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| 47. |
Chapter3wsh fatrer grav feftrichoose the correct option-318b.m> nam < ncm = n |
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Answer» If m= nतब यह एक बर्ग आव्यूह होगा |
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| 48. |
The rationalising factor of\sqrt[5]{a^{2} b^{3} c^{4}}\begin{array}{ll}{\sqrt[5]{a^{3} b^{2} c}} & {\text { (B) } \sqrt[4]{a^{3} b^{2} c}} \\ {\sqrt[3]{a^{3} b^{2} c}} & {\text { (D) } \sqrt{a^{3} b^{2} c}}\end{array} |
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Answer» A) as multiplying and dividing by root over(a³b²c²) will eliminate root over 5 in numerator |
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| 49. |
three cards are drawn successively without replacement from a pack of 52 well shuffled cards.what is the probability that first two cards are queens and the third card drawn is a king? |
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| 50. |
The diagonals of a Rhombusare 7.5 cm and 12 cm. Find its area. |
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