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) ABcp i o poralidoqon . aa s Kicded ok ®odD b So kholt AP: PR = 312 o~d CR:OD =%\ =%था कल इनकी. न कि R, फेज prove Aok ARz "’_3 M

Answer»

ΔAPR ∼ ΔCQR (AA)

⇒AP/CQ=PR/QR=AR/CR

⇒AP/CQ=AR /CR & AP= 3/5 AB

⇒3AB/5CQ=AR/CR& CQ= 4/5 CD = 4/5 AB

⇒AR/CR= 3/4

⇒CR/AR= 4/3

CR+AR/AR= 4 +1/3

⇒AC/AR= 7/3

⇒AR = 3/7 AC

Hence proved

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