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) ABcp i o poralidoqon . aa s Kicded ok ®odD b So kholt AP: PR = 312 o~d CR:OD =%\ =%था कल इनकी. न कि R, फेज prove Aok ARz "’_3 M |
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Answer» ΔAPR ∼ ΔCQR (AA) ⇒AP/CQ=PR/QR=AR/CR ⇒AP/CQ=AR /CR & AP= 3/5 AB ⇒3AB/5CQ=AR/CR& CQ= 4/5 CD = 4/5 AB ⇒AR/CR= 3/4 ⇒CR/AR= 4/3 CR+AR/AR= 4 +1/3 ⇒AC/AR= 7/3 ⇒AR = 3/7 AC Hence proved Like my answer if you find it useful! |
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