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101 और 999 के बीच की सभी सम संख्याओं का |
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Answer» A = 110 {first number to be divided by 2 and 5}difference d =10an=990 {last no to be divided by 2 and 5}an = a + {n - 1}d990 = 110 + 10n -10880 + 10 = 10n890 = 10nn = 89 |
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