How many terms divisible by 2 or 5 between 101 to 999

1.	How many terms divisible by 2 or 5 between 101 to 999
Answer» no. divisible by 2&5 must be divisible by 10Form an AP of natural number present between 101 & 999 AP = 110, 120, 130,............, 990from the AP we concludeda = 110d = 10nth term of the AP = 990a+(n-1)d=990110+(n-1)10=990(n-1)10=990-110(n-1)= 880/10n-1=88n=88+1n=89natural number present between 101 & 109 = 89

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no. divisible by 2&5 must be divisible by 10Form an AP of natural number present between 101 & 999

AP = 110, 120, 130,............, 990from the AP we concludeda = 110d = 10nth term of the AP = 990a+(n-1)d=990110+(n-1)10=990(n-1)10=990-110(n-1)= 880/10n-1=88n=88+1n=89natural number present between 101 & 109 = 89

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How many terms divisible by 2 or 5 between 101 to 999

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