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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
ivide 7.6 cm line segment into the ratio 4:5 |
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Answer» let X be the common multiplehence4x+5x=7.69x=7.6x=7.6/9hence1 part is 4x=4*7.6/9=3.377cm2 part is 5x=5*7.6/9=4.223cm |
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| 2. |
8) If x + 2y = 10 and xy =3 then x = |
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Answer» X+2y = 10.X = 3y. => 3y+2y = 10=> 5y = 10=> y = 2. X = 3y = 6. Please hit the like button if this helped you. |
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| 3. |
solve xy 3, 3x 2y 4 0 by determinant method, find D |
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| 4. |
17. A sum of money invested at 8% per annum amounts to? 12122 in 2 years . What willamount to in 2 years 8 months at 9% per annum?ARA invears? |
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| 5. |
Show that any positive odd integer is of the form 6q+1, or 6q+ 3, or 6q +5, where q issome integer. |
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| 6. |
9) Find using algebraic identity 3x + |
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| 7. |
10) Find using algebraic identity(2a |
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| 8. |
16. If x(4--/15), find the value of | χ + |
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| 9. |
7) Find using algebraic identity (m+ 1)2? |
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| 10. |
3. Using algebraic identity, find the coefficients of r, T aa2, and constant term withoutactual expansion.(ii) (2a +3 (2-5)(2 -6)2 |
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| 11. |
Question Numbers 1 to 6 carry 1 mark each.1. Evaluate, using an algebraic identity the product 103 x 97.2. Find the mean of 15, 25, 35, 45 and 55. |
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| 12. |
lf 4-3/5=a+b 15. find the values4 +3/5 |
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Answer» hit like if you find it useful |
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| 13. |
7x-2y = 5xy+ Ty = 157xy |
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| 14. |
5.Solve the following 1.5 x 0.3(tv) 4.3 x 3.4(vii) 1.07 x 0.02(x) 70.01 x 1.1m)(v)(viii)0.1 x 47.5 (in)0.5 x 0.05 (vi)10.05 x 1.05 (ix)0.2 x 210.811.2 x 0.10101.01 x 0.01 |
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Answer» 0.45 . 4.75 . 42.16 . 14.62 . 0.025 . 1.12 . 0.0214 . 10.5525 . 1.0101 . 77.011 1)0.452) 4.753) 42.164) 14.625) 0.0256) 1.127) 0.02148) 10.55259) 1.010110) 77.011 3(i)1.5 x 0.3=0.45, (ii)0.1 × 47.5=4.75, (iii)0.2 × 210.8=42.16, (iv)4.3× 3.4=14.62, ( v)0.5 × 0.05=0.025, (vi)10.2 × 0.10=1.02, (vii)1.07 × 0.02=0.0214, (viii)10.05 × 1.05=10.5525 (ix)101.01 × 0.01=1.0101, (x)70.01 × 11= 770.11. 0.45 4.75 42.16 14.62 0.025 0.112 0.0214 10.5525 1.010 77.011 1) 0.45, 2) 4.75 ,3) 42.16 ,4) 14.62 ,5) 0.025 ,6) 1.12 ,7) 0.0214 ,8) 10.5525, 9) 1.0101 ,10) 77.011 |
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| 15. |
y').14. If x+y=12 and xy = 14, find the value o15. If x - y = 7 and xy - 9. find the value of x |
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| 16. |
15-Diivide 2402 yz+ xyz+ xy) by 8xyz |
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| 17. |
15. If26 and xy 3, find the value of: (a)x + y |
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| 18. |
present ageRajesh's father is 3 times as old aof their ages is 62. Find their agess Rajesh was two years ago. Today, the sumbas lo 12 vears her mother will be |
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| 19. |
\begin{array}{r}{\frac{\cos (90-\theta) \sec (90-\theta) \tan \theta}{\csc (90-\theta) \sin (90-\theta) \cot (90-\theta)}+\frac{\tan (90-\theta)}{\cot \theta}} \\ {=2}\end{array} |
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| 20. |
A spring of force constant 4 kg/em is compressed 4 cm from its naturawith the help of block of weight 0.5 kg. Calculate what speed the springpush back. (Neglecting friction of the surface). [Answer: 0.112 m/s)ed 4 em from its natural lengthwill |
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Answer» ke=1/2kx^2 equations kinetic energies1/2mv^2=1/2kx^2V=x√k/mv=0.04√0.04/05v=0.112m/s |
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| 21. |
.Solve for x the following equations:(i) sec (90° A) x sin A tan (90° + A) cos (90 + A).ii)x cot (90° + θ) + tan (90° + θ) sin θ + cosec (90° + θ)0. |
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| 22. |
The length of a rectangle is 17cm more than its breadth. Its perimeter is 234cm. Findthe dimensions of the rectangle. |
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| 23. |
if sum of two sides of a triangle is 17cm and it's perimeter is 30cm,then what is the length of third side |
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Answer» perimeter= sum of three side of trianglelet the third side be xthen 17+x=30x=30-17=13cm |
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| 24. |
15, If x sin (90°-9) cot (90°-0) = cos (90°-9), then x = |
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Answer» x sin(90° - θ) cot(90° - θ) = cos(90° - θ) x cosθ tanθ = sinθ x = sinθ/(cosθ × tanθ) x = tanθ/tanθ x = 1 |
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| 25. |
\frac { \cot \theta \tan \left( 90 ^ { \circ } - \theta \right) - \sec \left( 90 ^ { \circ } - \theta \right) \csc \theta } { \sin \theta \cos \left( 90 ^ { \circ } - \theta \right) + \cos \theta \sin \left( 90 ^ { \circ } - \theta \right) } |
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Answer» tan(90-t) = cott sec(90-t) = cosect sin(90-t) = cost cos(90-t) = sint (cott*tan(90-t) - sec(90-t)*cosect)/(sint*cos(90-t) + cost*sin(90-t)) = (cott*cott - cosect*cosect) / (sint*sint + cost*cost) = 1/1 = 1 |
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| 26. |
Which term of AP ě,13117, 21 ...-it48 moe-than 4ott tenm |
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Answer» Like if you find it useful |
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| 27. |
(iv) x2-4x-32The lengths of the sides of a triangle are integers, and its area is(iii) p2-10q + 2121 and the perimeter is 48. Find the shortest side.Find the values o |
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Answer» Sum of other 2 sides = 27.=> If one side = x, other = 27 - x.Using Heron's formula,=> A^2 = 24*3*(24-x)*(x-3)RHS must be a perfect square=> A^2 = 6^2 * 2 * (24-x)(x-3) is a perfect square=> x = 10, Other side = 17=> shortest side = 10 cm.Other sides are 17cm and 21 cm, |
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| 28. |
Q.1) Find the value of v (5A) 1/25 (3) 55 (p] 02(D) 02 |
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Answer» root(5^(-2))=root(1/25)=1/5=0.2 |
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| 29. |
How many envelope can be made out of sheet of paper 1m25cm by 85cm if each envelope require a piece of paper of size 17cm by 5cm? |
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| 30. |
9. By what number should we multiply to 3-? so that the product may be equal to 3 ?t he equal to 4-29 |
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Answer» Let number that should be multiply be x Then,3^-7 * x = 3 x = 3/3^-7 x = 3^[1 + 7] = 3^8 x = 6561 Therefore the number to be multiplied = 3^8 = 6561 |
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| 31. |
3/Tft = 2k _ l and y-k is a solution of the equation 3x-5y-9-0, find the value ofk |
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Answer» 3x-5y-9=03(2k-1)-5k-9=06k-3-5k-9=0k-12=0k=12 |
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| 32. |
The number of linear functions which map1-1, ll®) [0,2] areI.1] to [0,2] are |
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| 33. |
11. How many linear chain isomers are possible forthe alkene CHa) 1b)3c) 5 |
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Answer» In organic chemistry, an alkene is an unsaturated hydrocarbon that contains at least one carbon–carbon double bond. So it has not isomers. But for instance The six carbons and 12 hydrogens found in the formula C6H12 can be arranged to form a surprising25different structural isomers. |
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| 34. |
How many linear equations are satisfied by x 2 and y --3(a) Only oneMany(b) Two(c) Three(d) Infinitely |
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| 35. |
what no should (t) be multiply.So that product may equal to :(-2) |
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| 36. |
By what number should we multiplyso that the product may be 24? |
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| 37. |
12 by what number shouldbe multiplied so that the product may be egyalton12 |
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| 38. |
(c) 6+ (d) + (-20)By what number should we multiply -so that the product may be |
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| 39. |
A man saved Rs. 16.500 in 10 years.In each year after the first he savedRs. 100 more than he did in thepreceding year? How much did he savein the first yer? |
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Answer» thanks |
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| 40. |
12. By what number shouldbe multiplied so that the product may be equal to (-7)(1) |
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| 41. |
115. By what number shouldbe multiplied so that the product may be equal to 21 21 |
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| 42. |
on her seooter, How many litres of petrol does she useor riding 400 km?ania can jog 3.5 km in one hour. At the same rateow many kilometres can she jog in 3 hours? |
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Answer» In three hours = 3*3.5 km = 10.5 km |
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| 43. |
2. By what number should we multiply (2-5) so that the product may be equal to (2-')? |
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Answer» the no.should be least so just wait for some days but the answer is 5 the no. should be least so just wait for some days but the answer is 5 |
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| 44. |
6 By whatt number should 5-1 be multiplied so that the product may be equal to (-7) |
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| 45. |
gas.6. Balance the following chemical equations.(a) HNO,+Ca(OH), CaNOJ,+ H,o(b) NaOH+HSO, Na SO, +H,O(c) NaCI + AgNO, AgCl + NaNO,(d) BaC,+H,SO,BaSO,+ HCI |
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Answer» a) 2HNO3+Ca(OH)2= Ca(NO3)2+2H2O |
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| 46. |
x ^ { 3 } + 13 x ^ { 2 } + 32 x + 20 |
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| 47. |
x^{3}+13 x^{2}+32 x+20 |
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| 48. |
the missing length and reduce1212Enter |
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Answer» 10/x= 12/9by cross multiplicationx= 30/4 it said 15 on top but what's on the bottom? |
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| 49. |
of 900 at the initial point ofa given ray and justifyt an angle of 450 at the initial point of a given ray and justiftt the angles of the following measurements:(ii) 222 |
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| 50. |
15. How(a) Oneow many rays can be drawnawn with a given point as the initial point(b) Twoc) An unlimited number(d) A limited number |
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