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15, If x sin (90°-9) cot (90°-0) = cos (90°-9), then x = |
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Answer» x sin(90° - θ) cot(90° - θ) = cos(90° - θ) x cosθ tanθ = sinθ x = sinθ/(cosθ × tanθ) x = tanθ/tanθ x = 1 |
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