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(iv) x2-4x-32The lengths of the sides of a triangle are integers, and its area is(iii) p2-10q + 2121 and the perimeter is 48. Find the shortest side.Find the values o |
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Answer» Sum of other 2 sides = 27.=> If one side = x, other = 27 - x.Using Heron's formula,=> A^2 = 24*3*(24-x)*(x-3)RHS must be a perfect square=> A^2 = 6^2 * 2 * (24-x)(x-3) is a perfect square=> x = 10, Other side = 17=> shortest side = 10 cm.Other sides are 17cm and 21 cm, |
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