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A spring of force constant 4 kg/em is compressed 4 cm from its naturawith the help of block of weight 0.5 kg. Calculate what speed the springpush back. (Neglecting friction of the surface). [Answer: 0.112 m/s)ed 4 em from its natural lengthwill

Answer»

ke=1/2kx^2 equations kinetic energies1/2mv^2=1/2kx^2V=x√k/mv=0.04√0.04/05v=0.112m/s



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