Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Date2.2Page

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x²+x+5=0 ->1

To find x we have to factorise equ 1

Discriminant = b²-4ac a=1;b=1;c=5.

Discriminant = 1-(4×1×5)

Discriminant = -19

x1= (-b + √discriminant)/2×a

x1= (-1+19i)/2.

x2= (-b - √discriminant)/2×a

x2= (-1 - 19i)/2.

Hencex1= (-1+19i)/2. and x2= (-1 - 19i)/2.

2.

What is the length of a cuboid with width 13 cm, height 10 cm, and volume1690 cm?

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13x10=130:; 1690/130=13

Given,Width = 13 cmHeight = 10 cmVolume = 1690 cm³Now,find length:Length = Volume / Area=> 1690 / 130 = 13.°. Length = 13 cm

3.

PageDate2 S농-

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y = 25 ( vertically opposite angle)x+ 25 = 180 ( straight line) x = 180 - 25 = 155so z= 155 ( vertically opposite angle)

thx sir

4.

PageDate2

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(a² + b²) ( -a² + b²)

(b² + a²) ( b² - a²)

(b²)² - (a²)²

b⁴ - a⁴

5.

PAGE NO:DATE:212

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1

2

3

6.

The number of coins 1.5 cm in diameter and 0.2 cm thick to be meltedto form a right circular cylinder of height 10 cm and diameter 4.5 cm is'

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7.

나ld-u, 22_c.in e tehfinal

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Thank u so much

8.

find the number of coin of diameter 1.5 and 0.2 CM thick to be melted to form of right circular cylinder of height 10 cm and diameter 4.5 CM

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9.

. Solve the equation :(i) log10 (x + 1) + log10 (x - 1)= log 10 11 + 2 log103(CSE)

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plzz answer anyone i will be helpfull too u plzzzz

10.

4. Simplify :2 . e 36४208 .452 270 0 (8l)4_ 25)7 - (5)_M e — कि दी कलदर (1) 16X 2n+__4 X 8n (” 16 9 दी . 2

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11.

1. If (0 2)* 2 and log10 2 03010, then what 4is the value of x to the nearest tenth?(a) -10.0(b) 0-5(c) -0-4(d)02

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(0.2)^x = 2

taking log to both the sides

xlog(0.2) = log2

=> xlog(2/10) = log2=> x[log2-log10] = log2=> x[0.30-1] = 0.30=> x = -0.30/0.70 => x = -3/7 = -0.42 = -0.4

option C

12.

1. If (0-2) 2 and log10 2 03010,theis the value of x to the nearest tenth?(a) 10.0(b) -05(e)04(d) 02

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(0.2)^x= 2

taking log on both the sides xlog(0.2) = log2=> x[log(2/10)] = log(2)=> x[ log2-1] = log(2)=> x = log2/log2-1 = 0.30/0.30-1 = -0.30/0.70 ≈ -0.43

option c

13.

C in Fig. 6.56, Ps is the bisector ofZQPR of△PQR. Prove that QS-mSR PR

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Like if it is useful

14.

4.Solve: 16x-15 =65

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16x - 15 = 6516x = 65 + 1516x = 80 x = 80/16 x = 5

15.

(1) In the figure, seg Ps i side QR.If PQ- a, PR b, QS c and RS-dthen prove that(a + b) (a-b) = (c + d) (c-d).

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16.

46.Inthegivenfigure(not drawn to scale), ind the valueof (b + d) (a +c).50°al1150

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thanku

17.

(I) In the figure, seg PS i side QR.if PQ a, PR b, QS c and RS- dthen prove that(a+b(a -b) (c+d)(c d).

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18.

4*u^2 %2B 8*u

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19.

-09-0zagil.sal.322. A और B साथ मिलकर एक काम को 40 दिनों में कर सकते हैं।उनकी काम करने की दर का अनुपात 8:5हैं। A उसी काम को• अकेला कितने दिनों में पूरा करेगा?IANCERPIAN INDIA

Answer»

the correct answer is 104 days

the correct answer is 104 days

20.

\frac { 1 } { 4 } \cdot \frac { 1 } { 2 } , \frac { 3 } { 4 } , 1 , \frac { 5 } { 4 } \dots \ldots \text { is } \frac { 25 } { 4 } ?

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a=1/4d=1/2-1/4=1/425/4=a+(n-1)d25/4=1/4+(n-1)1/46*4=n-1n-1=24n=25so 25th term

21.

\frac{7}{8} \div \frac{5}{4}+\frac{3}{5} \times \frac{1}{4}-\frac{3}{10}

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22.

\frac { 2 } { 5 } \times \frac { 4 } { 9 } \div \frac { 4 } { 7 } + \frac { 3 } { 5 } - \frac { 2 } { 5 }

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23.

CHAPTER - SQUARE AND SQUARE ROOTSQ.1 If m is the cube root of n , then(b) vm(a) m3(d) Ým(c)

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24.

10. Find quadratic equation such that its roots are square of sum of the roots andsquare of difference of the roots of equation 2x^2 + 2(p + q) x +p^2+q^2 = 0

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25.

४ 6370 - 4218 + 845 2 5की. डे _'..“.

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26.

विवार को 845 व्यक्ति चिड़ियाघर गए। सोमवार को केवल 169 व्यक्ति गए। चिडियाघरकी सैर करने वाले व्यक्तियों की संख्या में सोमवार को कितने प्रतिशत कमी हुई?

Answer»

monday=845-169=676Monday=(676/845)*100=80%

60.76 loss is the correct answer me

Monday=845-169=676 (676/845)*100 =80%

80% correct answer for this question

80% is correct answer

Answer:Monday=845-169676 (676/845)*100=80%

80% the correct answer of the given question

27.

(4)15x2-16x + 1-0

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15x² - 16x +1=0=> 15x² -15x -x +1=0=> 15x ( X -1) -1(x-1)=0=> (15x -1)(x-1)=0=> X = 1/15, 1.

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28.

foctorize the following.(1)16x^2+24yx+9y^2

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16x²+24xy+9y²=(4x)²+(2×4×3)xy +(3y)²

Thus it is of form a²a+2ab+b²

Where a=4x; b=3y

Thus a²+2ab+b²=(a+b)²now (4x)²+(2×4×3)xy +(3y)²=(4x+3y)²

16x^2+24xy+9y^2(4x)^2+2*4x*3y+(3y)^2(4x+3y)^2

29.

nuit be addad to4x4+x1So that theu 8

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p( x )= 4x⁴+ 2x³- 2x²+x -1

g(x )= x²+2x-3

x²+2x-3)4x⁴+2x³-2x²+x-1(4x²-6x+22

4x⁴+8x³-12x²______________________-6x³+10x²+x

-6x³-12x²+18x___________________

22x²-17x-1

____________________-61x+65

The remainder = -61x +65

Now we have to add 61x -65 to p(x)

So that the resulting polynomial is

divisible by g( x )

thanks

30.

\frac { 5 } { 4 } + ( \frac { - 11 } { 4 } )

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31.

\frac 5 4 %2B ( \frac - 11 4 )

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5/4 + (-11/4)=(5-11)/4= -6/4 = -3/2

answer is -6 upon 4 because base is same and plus and minus make minus so it is correct

32.

roclice set 7.5Yield al Selabean pecMuind the meanamedSayabean 1s. 875

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Mean = Summation of yield / Summation of acre= (10+7+5+3+9+6+9+6)/8= 55/8= 6.875

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33.

CHAPTER - SQUARE AND SQUARE ROOTSQ.1 If m is the cube root of n, then(a) m3 (b) Vm(b) vm(0)(d) Vm(a) m3

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answer: (a)coz 3√n. = mhence m^3 = n

option d is correct for this question

then n = m^3 correct ans

option a is correct answer

34.

€91 (W) LSO ()uशिव फिर 03% 5.

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35.

\frac{5}{4}+\left(\frac{-11}{4}\right)

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5/4 - 11/4

= -6/4 = -3/2 is the answer

36.

शा LL ( (४)पड 2० ०0६ 14% ८0:70Dl e 1किफिरि धुंध पुर भर 128 k DBk T

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37.

4x4 +42 16x-4If x +4, then find the value of

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38.

Seltmi danesd A lso par mmh in a bank& smanths unde

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THE total principle amount for 8 months is 150*8 = 1200Rs = P , R= 8% , T = 8 months = 8/12 years

now interest gained = P*R*T/100 = 1200*0.08*2/3 = 64rs so, total maturity value is 1200+64 = 1264rs

39.

C.B.S.E. 2015)2 in the adjoining figure, O is the centre of a circle of radius 5 cmT is a point such that OT = 13 cm and OT intersects circle at E.!AB is a tangent to the circle at E, find the length of AB, wheTP and TQ are two tangents to the circle(CBSE, 20

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40.

find the value of log10 0.001

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c=-3 is the correct answer of the given question

41.

an soşcales,es, .tiangs AGC, AC AC.LA 80に.

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42.

Find the degree of each term for the following polynomial and also find the degree ofthe polynomial

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43.

Find the zeroes of the following polynomial:5V5x2+30x +85

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44.

Find the zeroes of the following polynomial:5v5x2+30x+8v5

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45.

3) Write the following polynomial in standarm3 +4 +3m.

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In standard form the terms of the polynomial should be in decreasing order of their exponents.So, in standard form the following polynomial is:-m³+3m+4

46.

(-11)/4 %2B 5/4

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47.

ही. 2B Dl *O9x=((z-) .

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x² - 2x = (-2) ( 3 - x)

x² - 2x = -6 + 2x

x² - 4x + 6 = 0

So, given is has degree 2 so it is quadratic equation

48.

x³ +4x²+ 5x +7

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49.

Find the value of p for which the points (5, 1), (1, p) and (4, -2) arecollinear.

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x₁ = -5 x₂ = 1x₃ = 4

y₁ = 1y₂ = py₃ = -2

For the points to be collinear :-

x₁(y₂ -y₃) + x₂(y₃ - y₂) + x₃(y₁ - y₂) = 0

-5{ p -(-2)} + 1 ( - 2 - 1) + 4( 1 - p) = 0

-5(p+2) + 1(-3) + 4( 1 - p) = 0

-5p - 10 - 3 + 4 - 4p = 0

-9p - 9 = 0

-9p = 9

p = 9/-9

p = -1

50.

ik by (2 |k DL u l_E

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π/3

=180/3

=60°