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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
t7. Find a and b, such that 12, a + b, 2a, b are in A.pAa 35 ara in |
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Answer» Very bad answer is right but method is wrong |
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| 2. |
4) the amount of money in the account every yearwhen Z10000 Pol deposited at compound in tuest bt8% per annum. |
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Answer» Given,Principal amount P = 10000, Rate of Interest R = 8%, Time period n = 1 year, Amount = A For compound interestA = P(1 + R/100)^nA = 10000(1 + 8/100)^1A = 10000(108/100)A = 108*100 = 10800 Therefore,Amount in account after one year = Rs 10800 |
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| 3. |
5. In a parallelogram ABCD, E and F are themid-points of sides AB and CD respectively(see Fig. 8.31). Show that the line segments AFand EC trisect the diagonal BD.E.Fig. 8.31 |
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| 4. |
Find the sum of the first 22 terms of the AP: 8, 3,-2, |
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| 5. |
Find the sum of the first 22 terms of the AP : 8, 3,-2,.. |
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| 6. |
tofind the value of n272h = go |
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Answer» ans= the value of x us 2 9/2 is correct answer. |
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| 7. |
2) ४िको।b+८०।।blecc ।। - 4 45 ८,atbl |
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| 8. |
A man can row 8 km in one hour in still water. The speed of the water current is 2and it takes 3 hours for him to go from point P to go to point Q and return to P. Find thedistance PQ |
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| 9. |
4,inaparallelogram ABCD, E and F are the mid-points ofsides AB and CD respectively.Show that the line segments AF and EC trisect the diagonal BD. |
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| 10. |
30. In a parallelogram ABCD, E and F the mid points of sides AB and CD respectively Show that theline segments AF and EC trisect the diagonal BD.CD |
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Answer» Given ABCD is a parallelogramHence AB || CD⇒ AE || FCAlso AB = CD (Opposite sides of parallelogram ABCD)⇒AE = FC (Since E and F are midpoints of AB and CD)In quadrilateral AECF, one pair of opposite sides are equal and parallel. ∴ AECF is a parallelogram.⇒ AF || EC (Since opposite sides of a parallelogram are parallel) In ΔDPC, F is the midpoint of DC and FQ || CPHence Q is the midpoint of DQ by converse of midpoint theorem.⇒ DQ = PQ → (1)Similarly, in ΔAQB, E is the midpoint of AB and EP || AQHence P is the midpoint of DQ by converse of midpoint theorem.⇒ BP = PQ→ (2)From equations (1) and (2), we getBP = PQ = DQHence, the line segments AF and EC trisect the diagonal BD of parallelogram ABCD. |
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| 11. |
4 4f B+ cotBes le +eolcestr =34‘9/&-' ही जे 33 हू कह |
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Answer» A + B = 180-Ctake tan of both sides(tan A + tan B)/(1-tan A tan B) = - tan Cor tan A + tan B + tan C = tan A tan B tan C dividing both sides by Tan A tan B tan C We get 1/tan B 1/ tan C + 1/tan A 1/ tan C + 1/ tan A 1/tan B = 1or cot B cot C+ cot A cot C + cot A cot B = 1 |
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| 12. |
complete the following Dimultaneegraphically 24-06y=3u 2h 4.51y| 0.75|(2, 4) $25,0-45) (4.5, 0) |
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| 13. |
2) In which quadrant does the point (-4,-3) le(a) first(b) second(cthird (o fourth |
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Answer» (-4, -3) lies in third quadrant as both are negative. |
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| 14. |
PART A (5 X 2 = 10 MARKS)For what value of a the equation x' + ax - 8x? - 1 = 0 has a root 1. |
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| 15. |
PART A (5 X 2 = 10 MARKS)For what value of a the equation x' + ax - 8x-1=0 has a root 1 |
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Answer» a = 8 is the right answer |
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| 16. |
O, B, D and C are the vertices of a thombus and A, B, D and C lie on the circle with centre (4)O, as shown in the figure. FindBOC, 40BC, 4 BAC and 4 BDC.0 |
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Answer» 1 |
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| 17. |
4B) Solye the following questions : (Any Two)its base isThe curved surface area of a cylinder is 1980 cm2 and the radius of15 cm. Find the height of the cylinder. (T7LE Measure the |
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Answer» Curved surface area of cylinder=2πrh 1980=2(22/7)(15)h 1980*7/2*22*15=h height=21cm |
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| 18. |
n a parallelogram ABCD, E and F are themid-pol n831). Show that the line segments AFand EC trisect the diagonal BD.oints of sides AB and CD respectively |
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| 19. |
Use Euclid's division algorithm tothe H.C.E al 135 and 225.find |
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Answer» 225=135x1+90135=90x1+4590=45x2+0:HCF(225 and135)=45 225=135*1+90 135=90*1+4590=45*2+0so, HCF=45 HCF=35 is correct answer for me HCF 45 right answer hoga The H.C.F is45. ok bhai HCF=45 is the correct answer h Given numbers, =135&225Euclid's division algorithm , =a=bq+rAs per formula = 225=135×1+90135=90×1+4590=45×2+0Here, we get remainder as "0"therefore, HCF of 225&135 through euclid's division algorithm is=45. |
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| 20. |
a parallelogram ABCD, E and F are themid-points of sides AB and CD respectivelyee Fig.8.31). Show that the line segments AFand EC trisect the diagonal BD. |
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Answer» Parallelogram : A quadrilateral inwhich both pairs of opposite sides are parallel is called a parallelogram. Aquadrilateral is a parallelogram if i)Itsopposite sides are equal ii)its opposite angles are equal iii)diagonals bisect each other iv)a pair of opposite sides is equal and parallel. Converseof mid point theorem: Theline drawn through the midpoint of one side of a triangle, parallel to anotherside bisect the third side. ========================================================= Given, ABCD is a parallelogram. E and F are the mid-points of sides AB and CDrespectively. To show: line segmentsAF and EC trisect the diagonal BD. Proof, ABCD is a parallelogram Therefore, AB || CD also, AE || FC Now, AB = CD (Opposite sides of parallelogram ABCD) 1/2 AB = 1/2 CD AE = FC (E and F aremidpoints of side AB and CD) Since a pair of opposite sides of aquadrilateral AECF is equal and parallel. so,AECF is aparallelogram Then, AF||EC, AP||EQ & FP||CQ (Since opposite sides of aparallelogram are parallel) Now, In ΔDQC, F is mid point of side DC & FP || CQ (as AF || EC). So,P is themid-point of DQ (by Converse of mid-point theorem) DP = PQ — (i) Similarly, In APB, E is mid point of side AB and EQ || AP (as AF || EC). So,Qis the mid-point of PB (by Converse of mid-point theorem) PQ = QB —(ii) From equations (i) and (ii), DP = PQ = BQ Hence, the line segments AF and EC trisect the diagonal BD. tqsm |
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| 21. |
ORİLATERALSparallelogram ABCD, E and F are thed-points of sides AB and CD respectivelysee Fig. 8.31). Show that the line segments AFInand EC trisect the diagonal BD |
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| 22. |
Find the circumference of e1. Take π.7(i) diameter = 49 cm |
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Answer» circumference=2πr or πdgiven d=49cmcircumference=π×49=(22/7)×49=22×7=154cm |
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| 23. |
In a parallelogram ABCD, E and F are themid-points of sides AB and CD respectively(see Fig. 8.31). Show that the line segments AFand EC trisect the diagonal BD. |
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| 24. |
5. In a parallelogram ABCD, E and F are themid-points of sides AB and CD respectively(see Fig, 8.31). Show that the line segments AFand EC trisect the diagonal BD |
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| 25. |
In a parallelogram ABCD, E and F are themid-points of sides AB and CD respectively(see Fig. 8.31). Show that the line segments AFand EC trisect the diagonal BD.Fig. 8.31 |
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| 26. |
14.Find the reciprocal of multiplication universe of -315.Prove that: (X"-, χ |
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Answer» 13. multiplicative inverse of -3 is -1/3 👍 |
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| 27. |
1 Find the value of cot(3)-n5 |
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Answer» wrong |
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| 28. |
Eind a le b4-3 JS |
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| 29. |
) 12. 16b 1s. 30e) 15. 65. 8Find the HCF by long division meshodal 44Solve the following |
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Answer» Please post clear image |
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| 30. |
Js. Find the area of circle whose radius isa. 7 cmb. 3.5 cmc. 49 cm2 1 |
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Answer» Can you give answer of 49cm |
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| 31. |
. Solve: 16x-15-65 |
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Answer» 16x - 15 = 6516x = 65 + 1516x = 80x = 80/16x = 5 |
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| 32. |
11. The perimeter of rectangle is 13 cm and its width is22 cm. Find its length. |
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Answer» Perimeter = 2( length+ breadth)13= 2(l+11/4)6.5*4= (4l+11)26-11= 4l15/4= length3.5 cm |
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| 33. |
the premier of rectangle is 13 cm and its width is 11/4 find its length |
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Answer» Perimeter = 2( length+breadth)13/2= length+ breadth13/2-11/4= length52-22/8= length = 30/8cm= length |
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| 34. |
the cost of carpeting a room 13 m by 9 m with a carpet of width 75 cm at the rate of? 105 per metre |
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| 35. |
73 of[45-46 Ă 7t(23-4 of5M |
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Answer» 73 of [45 - {6*7+(23- 4 of 5)}]so, using bodmas, 73 of [45 - {42 + (23-20)}]= 73 of [45 - {42 + 3}]= 73 of [45 - 45]= 73 of 0= 73 * 0= 0 |
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| 36. |
Date2 |
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Answer» -2/5 = -0.41/2= 0.5 there rational between them are-0.3, -0.2, -0.1, 0, 0.1, 0.2, 0.3,0.4 give the big solution pleale! |
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| 37. |
Date22. |
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| 38. |
Date2. |
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Answer» 8 8 8 what. |
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| 39. |
11:13 AM€+91 99938 732331 minute ago39Redmi1. Add the following rational numbers :5717(a)and(b) and- 12 - 152346 |
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Answer» क्या zindagi hai ik din se koi bhi nahi hai kya tu bhi kitna jiddi he yarr bado ki respect kiya. please like my answer -5/46is the answer of this question (a) -53/60 (b) -5/46 |
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| 40. |
24. The denominator of a fraction is two more than its numerator. If the sum of the fraction and its reciprocal34151Sfind the fraction |
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Answer» thnk uh... how uh get 29/10 |
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| 41. |
Find an equivalent fraction of 15/65 with a denominator of 13. |
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Answer» 15/65 = (5×3)/(5×13) = 3/13 |
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| 42. |
(a) 92 053 - 13(0) 1208457b) 94829(e) 81 162-81(c) 23 138 - 4672 000 - 96 |
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Answer» 92053÷13=708111948÷29=41223138÷46=50312084÷57=21281162÷81=100272000÷96=750 |
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| 43. |
DATE2.5b |
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Answer» 56×56 = 56² = 3136( square of a number) |
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| 44. |
Page:Date /ĺżliv2-2 uha |
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Answer» plz see this above have calculation mistake |
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| 45. |
the cost of carpeting a room 13 m by 9 m with a carpet of width 75 cm at the rate of5 per metre. |
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| 46. |
Do all vibrating objects produce sound? Explain. |
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Answer» If the amplitudes of thevibrationsare large enough and if natural frequency is within the human frequency range, then thevibrating objectwillproduce soundwaves that are audible. All objectshave a natural frequency or set of frequencies at which theyvibrate. |
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| 47. |
2 \operatorname { log } _ { 10 } x = 1 + \operatorname { log } _ { 10 } ( x + ( \frac { 11 } { 10 } ) ) |
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Answer» 1=log10 102log10 x =log10 10 + log10 (x+11/10)log10 x^2=log10 (10x+11)by taking antilogx^2=10x+11x^2-10x-11=0(x-11)(x+1)=0so x=-1,11 |
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| 48. |
(A)NCERиС-JS |
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Answer» 5/√3-√5*√3+√5/√3+√5=5(√3+√5)/3-5=-5(√3+√5)/2 |
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| 49. |
Find an equivalent fraction of 15/65 with a denominator of 13 |
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| 50. |
(13/15)*((10/23)*(46/65)) |
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Answer» 4/5 is the answer of this question sorry 4/15 is the answer of this question 4/5 is the right answer 4/5 is the correct answer of the given question |
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