| 1. |
a parallelogram ABCD, E and F are themid-points of sides AB and CD respectivelyee Fig.8.31). Show that the line segments AFand EC trisect the diagonal BD. |
|
Answer» Parallelogram : A quadrilateral inwhich both pairs of opposite sides are parallel is called a parallelogram. Aquadrilateral is a parallelogram if i)Itsopposite sides are equal ii)its opposite angles are equal iii)diagonals bisect each other iv)a pair of opposite sides is equal and parallel. Converseof mid point theorem: Theline drawn through the midpoint of one side of a triangle, parallel to anotherside bisect the third side. ========================================================= Given, ABCD is a parallelogram. E and F are the mid-points of sides AB and CDrespectively. To show: line segmentsAF and EC trisect the diagonal BD. Proof, ABCD is a parallelogram Therefore, AB || CD also, AE || FC Now, AB = CD (Opposite sides of parallelogram ABCD) 1/2 AB = 1/2 CD AE = FC (E and F aremidpoints of side AB and CD) Since a pair of opposite sides of aquadrilateral AECF is equal and parallel. so,AECF is aparallelogram Then, AF||EC, AP||EQ & FP||CQ (Since opposite sides of aparallelogram are parallel) Now, In ΔDQC, F is mid point of side DC & FP || CQ (as AF || EC). So,P is themid-point of DQ (by Converse of mid-point theorem) DP = PQ — (i) Similarly, In APB, E is mid point of side AB and EQ || AP (as AF || EC). So,Qis the mid-point of PB (by Converse of mid-point theorem) PQ = QB —(ii) From equations (i) and (ii), DP = PQ = BQ Hence, the line segments AF and EC trisect the diagonal BD. tqsm |
|