2 \operatorname { log } _ { 10 } x = 1 + \operatorname { log } _ { 10 – InterviewSolution

1.	2 \operatorname { log } _ { 10 } x = 1 + \operatorname { log } _ { 10 } ( x + ( \frac { 11 } { 10 } ) )
Answer» 1=log10 102log10 x =log10 10 + log10 (x+11/10)log10 x^2=log10 (10x+11)by taking antilogx^2=10x+11x^2-10x-11=0(x-11)(x+1)=0so x=-1,11

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