1. If (0 2)* 2 and log10 2 03010, then what 4is the value of x to the – InterviewSolution

1.

1. If (0 2)* 2 and log10 2 03010, then what 4is the value of x to the nearest tenth?(a) -10.0(b) 0-5(c) -0-4(d)02

Answer»

(0.2)^x = 2

taking log to both the sides

xlog(0.2) = log2

=> xlog(2/10) = log2=> x[log2-log10] = log2=> x[0.30-1] = 0.30=> x = -0.30/0.70 => x = -3/7 = -0.42 = -0.4

option C

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