1. If (0-2) 2 and log10 2 03010,theis the value of x to the nearest te – InterviewSolution

1.

1. If (0-2) 2 and log10 2 03010,theis the value of x to the nearest tenth?(a) 10.0(b) -05(e)04(d) 02

Answer»

(0.2)^x= 2

taking log on both the sides xlog(0.2) = log2=> x[log(2/10)] = log(2)=> x[ log2-1] = log(2)=> x = log2/log2-1 = 0.30/0.30-1 = -0.30/0.70 ≈ -0.43

option c

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