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if may 1 is Tuesday1 week ie May 8th will be Tuesday and six days then it will be Sunday

sir again tell me

The focus is (-1,1).

Directrix is x-y+3=0 and e =1/2.

Let P(x₁,y₁) be any point on the ellipse, then SP² = e²PM² where PM is perpendicular distance from x-y+3=0

(x₁+1)² + (y₁-1)² = 1/4 [(x₁-y₁+3)/√(1+1)]²

8(x₁+1)² +8 (y₁-1)² = (x₁-y₁+3)²

7x₁²+2x₁y₁+7y₁²+10x₁-10y₁+7=0

Locus of (x₁,y₁) i.e., the equation of the required ellipse is

7x²+2xy+7y+10x-10y+7=0

and

question is not clear enough

Option (1) 4x+3 is correct answer.

1) 4x + 3 is the correct answer

2) 4x is the correct answer

4x + 3 is correct answer

Discriminant = bxb - 4aca = 3sqroot(2), b = - sqroot(3), c = - sqroot(18)

Discriminant = 3 - 4x(3sqroot(2))(-sqroot(18))= 3 + 4x9x2= 3 + 72= 75

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pls give me a correct answer for this question

(x-2)/(x-1) is the correct answer of the given question

Let theta = x

LHS:sin^2 x - sin^2 x. cos^2 x/cos^4 x

= sin^2 x(1 - cos^2 x)/ cos^4 x

= sin^2 x. sin^2 x/cos^4 x

= sin^4 x/cos^4 x

= tan^4 x

= RHS

Hence proved

Sol:Given LM || NQ

⇒ ∠1 = ∠4 [Alternate interior angles cut by transversal MN]

Again, LN || PQ⇒ ∠2 = ∠3 [Alternate interior angles cut by transversal MN]∴ ΔLMN ~ ΔNPQ [AA criterion of similarity]Area of ΔLMN / Area of ΔNPQ = MN2/ NP2But MP = 1/3 MN⇒ NP = 2/3 MNArea of ΔLMN / Area of ΔNPQ = MN2/ NP2= MN2/ (2/3 MN)2= (3/2)2= 9/4.

Consider x^2/a^2+y^2/b^2=1the distance from the vertex to the focus is 2therefore, a-ae=2but e=2/3 and thus a=6

We also knowb^2=a^2(1-e^2)b^2=6^2(1-2^3/3^2)b^2=20Thus if the centre is at the origin, the ellipse would be x^2/36+y^2/20=1But your ellipse is shifted to the left by 3 and up by 1 therefore, your ellipse's equation is(x+3)^2/36+(y-1)^2/20=1

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2x+2y = 2.....(i)2y - x = 1.....(ii)

(i) - (ii) => 3x = 1=> x= 1/3.

y = 1 - x=> y = 2/3

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3x²-8x+2k+1 a=3, b=-8 ,c=2k+1suppose the zeroes of the equation are α and β . by the given condition α=7βas we know , α+β=-b/a7β+β=-(-8)/38β=8/3β=8/3×1/8=1/3αβ=c/a7β×β=2k+1/37×1/3×1/3=2k+1/37/9=2k+1/321/9=2k+121/9-1=2k12/9=2k4/3=2k4/6=k2/3=k

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Here x²+2 and x⁴+2 are always ✓ . also √x²-16 should also be ≥ 0, because there can't be any negetive term inside root ,

so, x²-16≥ 0 => x²≥ 16 ... or x = (-∞,4] U [4,∞)

now, to make the expression ≤0x²-9 < 0

=> x²<9 => x belongs to (-3,3)

but taking intersection of both the terms we get only two solutions as -4 and 4 .. because at -4 and 4 , it will become = 0

so, sum of solution is -4+4 = 0

unable to understand

+ / \ × × / \ / \ 5 6 2 3

Given equationx + 2y = 6y = (6 - x)/2

For x = 2,y = (6 - 2)/2 = 4/2y = 2

Therefore, one solution is (2, 2)

one solution is (1,5/2)

by hit and trial we can se that x=4 will give as

log(4²)16 +log(2*4)64 = 1+2 = 3

so , 1 solution is X = 4. and other answer is 1/√2.so, option A,B,C and D are correct.

Actually all the answers are correct.

One solution is x = 2 and y = 0

2 ( 2 - 1) + 3 ( 0 + 5)

2 × 1 + 3 × 5

2 + 15

17

= RHS

E(X) + (XY) = E(XY)=5 + 6 = 11

x^3+y^3= 9+4= 13

1)number of possible outcomes= 13+3=16probability of getting a spade or ace=16/52=4/132)number of possible outcomes=2probability of getting a black king=2/52=1/263)number of possible outcomes=52-4-4=44probability of getting neither a king nor queen=44/52=11/134)number of possible outcomes=4+4=8probability of getting either a king or a queen=8/52=2/13

3×2+2×3=12 and 2×3=6,find the value of 9×2+4×3=30

Circumference of circle =2πr18π=2rπ18=2rr=18/2r=9CMarea of circle is πr^2π×(9)^2π×8181πcm^2

Given : (2,2) is solution of

3x + 4y - 2p = 0

Therefore, put x = 2 and y = 2

3 × 2 + 4 × 2 - 2p = 0

6 + 8 = 2p

2p = 14

p = 7

if X=2 y=1then 3x+4y=3(2)+4(1)=6+4=10hence a=10

It is given that on dividing 2053 by the required number there is a remainder of 5 .this mean that 2053 - 5 = 2048 is exactly divisible by required number . similarly,967- 7 = 960the required number is the largest number satisfying the above property .therefore ,it isthe HCF of 2048 & 960HCF of 2048 & 960 is 64hence required number is 64

(4x+5y)^2=16x^2+24y^2+40xy(23)^2=16x^2+25y^2+40(6)529-240=16x^2+25y^2289=16x^2+25y^2

Answer is 289

why u take 24

1 Litre is 1000mL os1/5 th of 1000mlis 200ml

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