Saved Bookmarks
| 1. |
12. The equation log,a 16+og2x 64 3 has(A) one irrational solution(C) two real solutions(B) no prime solution(D) one integral solution |
|
Answer» by hit and trial we can se that x=4 will give as log(4²)16 +log(2*4)64 = 1+2 = 3 so , 1 solution is X = 4. and other answer is 1/√2.so, option A,B,C and D are correct. Actually all the answers are correct. |
|