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f 4x + 5y23 and xy6, find the value of 16x2 + 25% |
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Answer» (4x+5y)^2=16x^2+24y^2+40xy(23)^2=16x^2+25y^2+40(6)529-240=16x^2+25y^2289=16x^2+25y^2 Answer is 289 why u take 24 |
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