+2)(x2 -16Find the sum of all the real solutions of the inequality2-9)

1.	+2)(x2 -16Find the sum of all the real solutions of the inequality2-9)x+2)(X
Answer» Here x²+2 and x⁴+2 are always ✓ . also √x²-16 should also be ≥ 0, because there can't be any negetive term inside root , so, x²-16≥ 0 => x²≥ 16 ... or x = (-∞,4] U [4,∞) now, to make the expression ≤0x²-9 < 0 => x²<9 => x belongs to (-3,3) but taking intersection of both the terms we get only two solutions as -4 and 4 .. because at -4 and 4 , it will become = 0 so, sum of solution is -4+4 = 0 unable to understand

+2)(x2 -16Find the sum of all the real solutions of the inequality2-9)x+2)(X

Answer»

Here x²+2 and x⁴+2 are always ✓ . also √x²-16 should also be ≥ 0, because there can't be any negetive term inside root ,

so, x²-16≥ 0 => x²≥ 16 ... or x = (-∞,4] U [4,∞)

now, to make the expression ≤0x²-9 < 0

=> x²<9 => x belongs to (-3,3)

but taking intersection of both the terms we get only two solutions as -4 and 4 .. because at -4 and 4 , it will become = 0

so, sum of solution is -4+4 = 0

unable to understand