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It will be2(x+4).d/dx(x+4)= 2(x+4).1

No. of pen sells=45therefore profit = 45×1=45rs.

loss on x pencil = x ×.40=0.40x rs.

a/q. = 0.40x-45rs=50.40x = 50rsx=50/0.40=125

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no I can't this is much clear

(1/3)^-2 * 3^2 ÷ 3^-3

= (3)^2 * 3^[2 - (-3)]

= 3^[2 + 2 + 3]

= 3^7

Cuboid length = 33 cm, breadth = 18 cm, height = 8 cm

Volume of cuboid Vc = length*breadth*heightVc = 33*18*8 = 4752 cm^3

Coin diameter = 6 cm, thickness = .2 cmVolume of coin Vcn = pi*r*r*hVcn = (22/7)*6/2*6/2*.2 = 198/35

Let number of coins can be made = n

Then, n*Vcn = Vcn*198/35 = 4752n = 4752*35/198 = 24*35n = 840

Therefore 840 solid coins can be made

Volume is lbh=20*10.5*8=1680cm^3

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(3^2)^3 ÷ (3)^2= (3)^6 ÷ (3)^2= (3)^[6-2]= (3)^4= 3*3*3*3= 81 ans

(1/3^2)^3=(1/9)^3=(1/729)

Vol. of wooden plank= l×b×h........ ... b= 3m.........., h= 75 cm=0.75m...... So, l×b×h= 33.75.............. l×3×0.75=33.75.......... l = 33.75/3×0.75......=45/3=15....... So length= 15m................ Now TSA of wooden plank = 2(lb+bh+hl)........= 2( 15×3+3×0.75+0.75×15).........=2( 45+2.25+11.25).........= 2( 58.5)...= 117m^2...

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So 115 = (100+15) percentage = 600now we have to tell the100 percentage

so if 115 percentage = 6001 percentage = 600/115now 100 percentage= 600/115*100521.73

A merchant has 120 kg of rice. He sells a part of it at a profit of 10% and the rest at a profit of 25%

so, x kg of rice sold at 10% profit(120 - x) kg of rice sold at 25% profit

so, total profit is 15% profit

15% of 120 = 10% of x + 25% of (120 - x)15*120 = 10x + 25(120-x)1800 = 10x + 3000 - 25x1800-3000 = -15x-1200 = -15xx = 1200/15x = 80

x = 80 kg of rice at 10% profit120-x = 120-80 = 40 kg

Bothaerobic and anaerobic respirationinvolvechemical reactions which take place in the cell to produce energy, which is needed for active processes.Aerobic respirationtakes place in the mitochondria and requires oxygen and glucose, and produces carbon dioxide, water, and energy. The chemical equation isC6H12O6+ 6O2→ 6CO2+ 6H2O (glucose + oxygen -> carbon dioxide + water).Anaerobic respirationalso produces energy and uses glucose, but it produces less energy and does not require oxygen. This is useful in tissues which have a high energy demand such as in working muscles, in which there isnot enough oxygen to produce all the energy needed by using aerobic respiration alone. Anaerobic respirationtakes place in the cell cytoplasm and produces lactic acid. The chemical equation isC6H12O6 -> 2C3H6O3 (Glucose -> Lactic acid). The lactic acid then needs to be oxidised later to carbon dioxide and water afterwardsto prevent it building up. This process requires oxygen and therefore following anaerobic respiration there is oxygen debt in the cell, as oxygen is needed to break down the lactic acid produced.

total number of cards = 52Number if ace = There are 4 Ace Cards in a deck.

Number of diamond = There are 13 cards

Let event 'A' be drawing a ‘Diamond’, then probability of getting a ‘Diamond', P(A) = 13/52

Let event 'B' be drawing an 'Ace’, then probability of getting an ‘Ace’, P(B) = 4/52

Probability of getting Ace of Diamond, P(A and B)= 1/52

Probability of getting a ‘Diamond' or an ‘Ace’ if one card is drawn at random,P(A or B) = P(A) + P(B) — P (A and B) = 13/52 + 4/52 — 1/52 = 4/13

6.zinc = 100-45-25 % = 30%

= 3kg x 30/100 = 0.9 kg

Nancy reads 45 pages out of 200.Kavya read 4/15 pages so its 4/15*200=53(approx)So Nanvy had read least pages

the answer is 45% I think

pie<x<3pie/2 so third quadrantsin2x=-4/5so cos2x=-3/5so tan2x=4/3

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The production of oxygen from per chlorate is as follows:

2KClO3(s) -> 2KCl (s) + 3O2(g)

so, here 2 moles of per chlorate is used to produce 3 moles of oxygen gas.

So, 1 mole of oxygen gas will need = 2/3 moles of per chlorate.

Now we know that 1 mole of oxygen gas at STP = 22.4 L

So, 112 L oxygen gas = 112/22.4 =5 Moles of oxygen gas.

So, 5 moles (112L) of oxygen gas will be produced by = 5 x 2/3 moles of per chlorate = 3.33 moles

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suppose Shabnam has x chocolatesshe gives 15% to Joseph which is 30so 0.15x=30 so x=30/0.15=200so she have previously 200 chocolates.

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4.5 g of alloy contains 3.5 gmso 1 gm of an alloy will contain 3.5/4.5 gm of copper=7/9gm of copperso 18.9 gm of alloy will contain (7/9)*18.9 gm of copper=14.7gm of copper.

Total cards=26Number of vowels=5Number of consonants=26-5=21Probability=21/26

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