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Reciprocal of (4/5)^2n-1

= (5/4)^-(2n-1)

= (5/4)^1-2n

sorry the answer is 9/20

9/20 is the correct answee

9/20 is the correct answer of the given question

5020/100=502/50=251/25=10 1/2514560/100=1456/50=728/25=29 3/253150/1000=315/100=63/20=3 3/2045/100=9/20

thnx for the answer

Let the number be xGiven,((x*5)+10)/8=x-15x+10=8(x-1)5x+10=8x-810+8=8x-5x=3x

3x=18x=6

So number is 6

39, 57, 69, 93 are composite number47, 83,103 are not composite number

Let the unit digit is ‘x’ and the 10th digit is ‘y’

The number is 10y +x

Reversed number is 10x+y

Given 11x + 11y = 66

x + y = 6 [dividing by 11]…….(1)

Also x - y = 2…….......... (2)

Add eq(1) and eq(2) we get2x = 8x = 8/2 = 4

Put value of x in eq(1)4 + y = 6y = 6 - 4 = 2

The number is 10y + x10*2 + 4 = 24

[check 24+42=66, 4-2=2]

if ABC is right angled at A then it must follow pythagoras theoremgiven AB=2n+1AC=2n(n+1)BC=2n (n+1)+1to prove AB^2 +AC^2 =BC^2LHS={2n+1}^2 +{2n (n+1)}^2=(4n^2 +1 +4n )+{4n^2 (n^2 +2n+1)}=4n^4 +8n^3 +8n^2+4n+1RHS={2n(n+1)+1}^2={4n^4 +8n^3 +4n^2 +1+4n^2 +4n}=4n^4 +8n^3 +8n^2 +4n+1we got LHS=RHS pythagoras theorem is satisfied so ABC is right angled at A

Let one no. Be xThen according to above condition.317*x=504347X=1591

the answer is 1591 please choose best I want points for meet tuotor

let the required number be x.X×317=5,04,347 X =5,04,347/317 X =1591so the other number is 1591.

1591 is the right answer

product of two no.=504347317×other no.=504347other no.=504347/317other no.=1591. ans.

product of two no.=504347317×second no.=504347second no.=504347/317second no.=1591. ans.

504347 = 317* aa = 504347/317 =1591

product of two number=504347317×other no=504347other number=504347/317other number=1591please accept it as the best

Use the general term in the expansion of (x + y)ⁿ is T_{r+1} = nCr.x^(n-r)y^r , then we have to find require coefficients by taking the suitable value of r .

proof:For, (1 + x)²ⁿ , the general term is T_{r+1} = 2nCr.x^r

for coefficient of xⁿ , put r = n T_{n+1} = 2nCn.x^nso, coefficient of xⁿ = 2nCn______(1)

For , (1+x)^(2n-1) , the General term is T_{r+1} = (2n-1)Cr.x^r for coefficient of xⁿ , put r = nT_{n+1} = (2n-1)Cn.x^nso, coefficient of xⁿ = (2n-1)Cn= (2n-1)!/n!×(2n-1-n)! = (2n-1)!/n! × (n-1)!

multiplying and dividing by 2n

= (2n)(2n-1)!/(2n)n!(n-1)!= (2n)!/2n!{n(n-1)!}= (2n)!/2n!n!= 1/2 {2nCn}__________(2)

from equations (1) and (2),

coefficient of xⁿ in (1 + x)^(2n-1) = 1/2 × coefficient of xⁿ in (1 + x)²ⁿ

2 × coefficient of xⁿ in (1 + x)^(2n-1) = coefficient of xⁿ in (1 + x)²ⁿ

Proof by induction on n:

Step 1: prove that the equation is valid when n = 1 When n = 1, we have (2(1) - 1) = 12, so the statement holds for n = 1.

Step 2: Assume that the equation is true for n, and prove that the equation is true for n + 1.

Assume: 1 + 3 + 5 + ... + (2n - 1) = n2

Prove: 1 + 3 + 5 +...+ (2(n + 1) - 1) = (n + 1)2 Proof: 1 + 3 + 5 +... + (2(n + 1) - 1)

= 1 + 3 + 5 + ... + (2n - 1) + (2n + 2 - 1)

= n2+ (2n + 2 - 1) (by assumption)

= n2+ 2n + 1

= (n + 1)2

So, by induction, for every positive integer n,

1 + 3 + 5 + ... + (2n - 1) = n2.

Let the third no. is n

Then,(8/7)*(15/4)*n = 15/2n = (15/2)*(7/8)*(4/15)n = 7/4

Third no. is 7/4

thank you!!😊😁

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sum of n terms=n(n+2)=n/2(2a+(n-1)d)now sum of 1 term=1/2(2a)=3 so a=3and sum of two terms=2(4)=8=2/2(6+d)6+d=8 so d=2so series is 3,5,7,9,...

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39, 57, 69, 93 are composite numbers47, 103 are not composite numbers

x - ( 380 + x/20 ) = 76

x - 380 - x/20 = 76

19x/20 = 76 + 380

19x/20 = 456

x = (456×20)/19

x = 480

Let the price of each egg =x rupees Total numbers of eggs before price increase 24/x=total eggs Now price of each egg is increased by x 120/100=6x/5 due to 2 eggs available less. S According to question How many eggs he can buy if expenditure 24rupees? 24/x-24/6x/5=2eggs, 24/x-24*5/6x=2ggs. Solving this eqn you get x=2 rupees per egg Now the price of each egg is 2*6/5 Per dozon price=12*12/5=28.8rupees Short method Exp=price*quantity or consumption Price inversely proportional to quantity When exp is same then 20per=6/5 Original price=5 ,new= 6 when exp same quantity ratio is opposite to price 5 :6 6:5 ,gap of 6,5 is 1 =2 eggs ,5*2=10eggs ,10eggs =24r 24*12/10=28.8

New price/present price

=20×24100×21220×24100×212

= 28.80

Rs.28.80 : - is correct hence option 4

Rs 28.80 is correct answer

correct answer is28.8

Suppose numbers are x and ynowx-y=50x/y=7/22x=7yx=7y/27y/2-y=505y=100y=20x=70

hope you will understand

Let tens digit no.be X and unit digit no.be YA/qx+y=9and 9 (10×x+y)=2 (10×y+x)90x+9y=20y+2x88x-11y=0from 1st11x+11y=9988x-11y=0......99x=99x=1and y=8 hence the no.is 18

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x=13 is the correct answer

13

thanks

Let’s say x is the unit digit and y is the tenth digit.

y+x = 9 -> y=9-x

10x+y = 10y+x+27

10x+9-x = 10(9-x)+x+27

10x+9-x = 90–10x+x+27

18x = 108

x = 6

so y = 3

let’s check

63 - 39 =27

27 = 27 (correct)

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opposite number so x + 8 = -(x+6) x + 8 = -x - 6 2x = -14 so x = -7 so both the numbers are -7+8 = 1 or -7+6 = -1

Thanks..

3rd term of the GP = 24 = ar2

6th Term of the GP = 192 = ar5

Hence,

6th term / 3rd term = ar5/ ar2= 192 / 24

r3= (192) / (24)

r3= (2*2*2*2*2*2*3) / (2*2*2*3) = (23)

Hence,r = 2

Since, ar2=24

a(2)2= 24

a = 24/4 = 6

Hence first term,a = 6, andr = 2.

Hence, the 10th term = ar10-1= ar9

10th term = (6)(2)9= 6(2)8(2) = 6(4)4(2) = 6(16)2(2) = (6)(256)(2) = 3072,

Hence the 10th term = 3072.

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thanks

108, 118, 128,...................998so from 100-200 we get 10 and from 200 -300 we get 10 likewise we will get 9 times from 100-998 so there are 90 digits

60.75 is second and third is 30.375

thank u