This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The exponent of x occurring in the 7th term of the expansion\left(\frac{3 x}{2}-\frac{8}{7 x}\right)^{9} |
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| 2. |
What is the index of the power of x occurring in the 5th term of the expansion of \left(3 x-\frac{2}{x^{2}}\right)^{9} |
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| 3. |
If the heights of 5 persons are 140 cms150 cms, 152 cms, 158 cms and 161 cmrespectively, find the mean height. |
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| 4. |
Which trapezoid, cut along the dashedline produces two Irapezoids? |
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Answer» option. d is the correct answer of the given question... D) is the right answer |
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| 5. |
aь та+a + b = 0 4G" bx - ау = 2ab = 0 |
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Answer» (bx/a) - (ay/b) + a + b = 0 and (bx) - (ay) + 2ab = 0Elimination method.⇒ (b^2x - a^2y + a^2b +ab^2) / ab = 0 and (bx) - (ay) + 2ab = 0⇒ (b^2x - a^2y + a^2b +ab^2) = 0 ---------→(1)⇒ (bx) - (ay) + 2ab = 0 ---------→(2)Multiply equation (2) by b(b2x) - (aby) + 2ab^2= 0 ---------→(3)Substract (3) from (1)⇒ - a^2y + aby + a^2b +ab^2-2ab^2= 0⇒ y(ab – a^2) = ab^2-a^2b⇒ ya(b – a) = ab(b-a)⇒ y = bsub y =b in equ (2)we get (bx) - (ab) + 2ab = 0⇒ b(x + a) =0⇒ x+a = 0⇒ x = -a. and y =b. subsitution method :⇒ (b^2x - a^2y + a^2b +ab^2) = 0 ---------→(1)⇒ (bx) - (ay) + 2ab = 0 ---------→(2)From (2) x = (ay – 2ab) / b.Sub x in equ (1)⇒ (b^2((ay – 2ab) / b ) - a^2y + a^2b +ab^2) = 0⇒ (aby – 2ab^2- a^2y + a^2b +ab^2) = 0⇒ y(ab – a2) = ab^2-a^2b⇒ ya(b – a) = ab(b-a)⇒ y = bsub y =b in equ (2)we get (bx) - (ab) + 2ab = 0⇒ b(x + a) = 0⇒ x+a = 0⇒ x = -a. |
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| 6. |
12 1 WW.W. R D.T.P-43 5ol मांग की ? |
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Answer» World wide weband Desk-Top Publishing সম্পূর্ণ ফর্ম |
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| 7. |
LEind theečś´ation oefuhtendie ularthe point C3.1) and 3, s)b see tea oftos oline tining |
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| 8. |
5. Find the difference between the place values of two sevens occurring in 7875value of 3 in 5396 and 5 in 7052 |
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Answer» difference between the place value of two sevens is 6930 |
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| 9. |
42. Tit Pruul UITWU MIUILIS 15 IJTITUU. AR VA ULAR23. If 36 flats cost * 68251500, what is the cost of each such flat? |
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| 10. |
अतः समान्तर श्रेढ़ी का 29 वाँ पद 64 होगा।उदाहरण-8. क्या समान्तर श्रेढ़ी 3, 7, 11, ...... का एक पद 184 है?हलः दी गई समान्तर श्रेढ़ी 3, 7, 11,..... है। यहाँ प्रथम पद a= 3, एवं सार्वअन्तपीका ताँट 184 है |
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Answer» let nth term= 184a= 3 , d= 7-3=4tn= 184a+(n-1)d= 1843+(n-1)×4=1843+4n-4= 1844n= 184+1= 185n= 185/4= bot a whole numberso 184 is not a term . |
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| 11. |
Section-B.Write the main characteristics of central part (core) of the carth. |
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Answer» The inner core is in the centre and is the hottestpart of the Earth. It is solid and made up of iron and nickel with temperatures of up to 5,500°C. |
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| 12. |
EXERCISE 16(B)1. The heights of 5 boys in a group are:152 cm, 170 cm, 156 cm, 164 cm and 158 cm. Find the mean height. |
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| 13. |
(b) 3) ÷ 184 |
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| 14. |
Subtract.184fromthe sum of 38 |
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| 15. |
I.184 for 2 years at 5% pa. |
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Answer» P=184T=2R=5%SI=PTR/100 = 184x2x5/100=18.4 Amount is 184+18.4=202.4 |
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| 16. |
ili) 54^2vi) 53×47ix) 81×79xii) 9.7 × 9.82 |
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| 17. |
b) A person standing between the two vertical cliffs produces a sound. Two successive echoesare heard at 4 s and 6 s. Calculate the distance between the cliffs.(speed of sound 320ms) |
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Answer» Like if you find it useful plz do this |
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| 18. |
12-43%-4G RB/sQ.2QuChosMonnika's father was 38 years of age when she was born while her mother was 36 years oldwhen her brother four years younger to her was born. What is the difference between theages of her parents?Ans |
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| 19. |
wo poles of equal heights are standing opposite each other on either side of fhich is 80 m wide. From a point between them on the road, the angles of eleaetop of the poles are 60° and 30, respectively. Find the height of the polsstances of the point from the poles.IVtower stands vertically |
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Answer» thnx |
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| 20. |
11. Simplify its lowest form:6x2 +9x3x2-12 x |
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| 21. |
in an equlateraAABC, D is a point on side BC Ich that ED-1BC, prove that .1(AD)2 = 7 (Al)2 |
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| 22. |
write the following rational numbers in the lowest form91(iv)180364 |
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Answer» option second is right answer i) 2/10 = 1/5; ii) -36/180 = -6×6/6×30 = -6/30 = 1/-5; iii) 91/364 = 7 x 13/7x 52 = 13/52 = 1/4 |
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| 23. |
23. Simplify the expression and find the values of rational numbers a and b5+2V6= a +bv65-26 |
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| 24. |
Convert the following rational numbers in the decimal form and state the kind of itsdecimal expression:17(1)4910002011(10)22 |
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Answer» Ans(1)8.5Ans(2)7.4Ans(3)0.049Ans(4)5.6666Ans(5)4.28888Ans(6)0.4545...Ans(7)3.44444Ans(8)2.8Ans(9)2.57142..Ans(10)15.13333 hkgdfohidufohugigusugifkf 1) 17/2=8.5; 2) 37/5=7.4; 3)49/1000=0 .0049; 4)17/3=5.66 , 5)4(2/7)=30/7=4.288 6)5/11=0.45454545 7)31/9=3.4444444 8)84/30=2.8 9)18/7=2. 5714 10)227/15=15.1333 |
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| 25. |
(a)(c)180184(b) 170(d) 195 |
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| 26. |
-10+(-170)-(-180)+(-16) |
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Answer» -10-170+180-16-10-170-16+180-180-16+180-16 -10-170+180-16=-180+180-16=180-196=-16 -10-170+180-16-180+180-16=0-16=-16 |
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| 27. |
p \% \text { of } P \text { is } 36 , \text { then } P |
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Answer» x/100 (x) = 36 x² = 3600 x = 60 |
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| 28. |
\begin{array} { l } { \text { Mr. Ajay is } 36 \text { years old. His taxable income } } \\ { \text { is } 2,40,000 \text { . Will he have to pay income tax } } \\ { \text { or not? } } \end{array} |
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Answer» Yes he has pay income tax Yes, Mr. Ajay will be charged tax for his income, because it visible a part of Tax Treatment ofLong Term Capital Gain arising from Transfer of Capital Assets under Income Tax Act, 1961. I dont no give me answer |
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| 29. |
Prove that three times the sum of the squares of the sides of a triangle is equal to four times the sumof the squares of the medians of the triangles. |
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| 30. |
20. A certain number of two digits is three times the sum of its digitsad1o i ecight times the sumand if 45 be added to it the digits will be reversed: find the number |
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Answer» 27 |
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| 31. |
\left. \begin array l \text Which of the following is \\ \text (A) \sqrt 10 \\ \text (C) \sqrt 35 \\ \text (C) \sqrt 35 \end array \right. |
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Answer» Option D√121= 11Therefore, it is rational no. as it can be expressed in form of p/q |
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| 32. |
18. wo intersecting lines form angles of 123and 57. What is the measure of the othertwo angles? |
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| 33. |
ms, wo sordons can be ichEXERCISE 2Which one of the following options is true, and why?y = 3x +5 hasa unique solution, only two solutions. |
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Answer» Infinite many solutions many solutions because it is in 2 variables |
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| 34. |
4^{\log _{2} 2 x}=36, \text { then find } x |
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| 35. |
\begin{array} { l } { \text { Write the follow } } \\ { \text { has: } } \\ { \text { (1) } \frac { - 36 } { 100 } } \end{array} |
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Answer» decimal form is36/100 = 0.36 |
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| 36. |
35 * 36 |
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Answer» the correct answer is 1260 |
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| 37. |
7) Multiply and reduce to lowest form and convert into a mixed fraction:7x5 (i) 11 x |
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Answer» 7*3/5=21/5 and 11*4/7=44/7 convert them into mixed fraction |
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| 38. |
The lowest form of the rational expression5x6isISx+ 3x -3x-3ssions th |
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Answer» x^2+5x+6 / x^2-x -6=x^2+3x+2x+6 / x^2-3x+2x-6= x ( x+3 ) +2( x+3) / x( x -3 ) + 2(x -3)= (x+2) (x+3) / ( x+2) (x -3)= (x +3) / ( x -3) |
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| 39. |
of telTIRS4. Find the sum of 35 terms of an arithmeticprogression whose second term is 2 and 7term is 22. |
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| 40. |
35.Find the sum of:576 and 176() 5080 and - 80(iii) - 515, 15 and 115(iv) -460, 60 and 56036.Simplify:(i) (-5) + (-16) +20 + (-26)(ii) 48 + (-75)(iii) 2069 +(-79) + 29+ (-49)(iv) -10 + (-170)- (-180) + (-16)(v) (-18) + (-50) - (-20) + (-60) - (+10)37.Write opposite of the following:(i) Gaining a weight of 10 kg(ii) Going west(iii) A deposit of Rs. 1000(iv) -4038.Indicate the following by '+' or 'sign:(i) A gain of Rs. 400(ii) 200 m below sea level(iii) Decrease of 10(iv) 10"C above zero(v) A deposit of Rs. 500)Write the next two natural numbers just after30010.40.Write the smallest and greatest whole number and natural number.Note: Revise Ch-1, 2 & 3 (For Pre-Mid Test) |
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Answer» 36)i)-3-16-26+20=-15, ii) 48-75=-27, (iii)1170, (iv)-376 , (v)-115 38)+400, ii)-200, iii)-10 , iv)+10 v)200 |
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| 41. |
Find the sum of first 51 terms of that arithmetic progression whose second term 14and third term is 18.0.8 |
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Answer» A2 = 14 and a3 = 18Common difference = a3 - a2 = 18 - 14 = 4 = dNow a2 = a+d=14 a+4=14a = 10Now, sum of 51 terms={51(2a+(50)d)}/2={51(20+200)}/2={51×220}/2=51×110=5610Therefore sum of 51 terms is 5610 |
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| 42. |
The mean of first five composite numbers isa)7.5The AM ofn observation is- lfth17.b) 7.4c) 7.3d) 718. |
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| 43. |
EXERCISConvert into fraction in the lowest form(a) 0.2(b) 0.4 |
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Answer» 1) 0.2= 2/102) 0.4= 4/10please like the solution 👍 ✔️ |
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| 44. |
of theof2. Fill in the blanks:(0 The product of two numbers does not change even if we changenumbernot change even if we change the( The product of three numbers dothe numbers(ii) The product of a number and 1 is the(iv) The product of any number and is |
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Answer» what is your question A rational number is such that when you multiply it by 5 1. position 2. position 3.the number itself4. zero 1. place2. place3. number itself4. 0 |
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| 45. |
The.sum ofthree times.x.and 1Lis.32 |
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| 46. |
a(n3 Y(112+3° + 52 ++ (2n-1)2 =1.4 4.7 7.10(3n-2)(33.55.7.7.9(2n +1)(21(n+1) (n+5) is a multiple of |
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Answer» please crop question properly and then send |
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| 47. |
3. The product of two numbers is 338. Find theproduct of HCF and LCM of the numbers. |
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Answer» 338 is the correct answer of the given question 5678+3456=9134 ok 338 is the right answer 338 is the right answer we know,product of two no.=H.c.f × L.c.m338=L.c.m×H.c.fHence,product of HCF and LCM=338 Sol. LCM X HCF = Product if two no. s900X HCF =8100HCF = 8100 -------- 900 = 9 Hence, the HCF of two no. s is 9 |
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| 48. |
multiple of 3 or 7?2) The sum of twoWo numbers is 60. The greater number is 8 more than thrice the smaller60. Thenumber. Find the numbers. |
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Answer» Let one number be x and other be yx+y=60Let x is greater than y 3y+8=x 3y+8+y=604y=60-8=52y=52/4=13 x=60-13=47 |
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| 49. |
321 Find the zeros of the polynomialAn° +5/2n-3. |
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Answer» I think so too but I don't know.... |
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| 50. |
1 +3 +5 +. +(2n-1) n2 |
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