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aь та+a + b = 0 4G" bx - ау = 2ab = 0 |
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Answer» (bx/a) - (ay/b) + a + b = 0 and (bx) - (ay) + 2ab = 0Elimination method.⇒ (b^2x - a^2y + a^2b +ab^2) / ab = 0 and (bx) - (ay) + 2ab = 0⇒ (b^2x - a^2y + a^2b +ab^2) = 0 ---------→(1)⇒ (bx) - (ay) + 2ab = 0 ---------→(2)Multiply equation (2) by b(b2x) - (aby) + 2ab^2= 0 ---------→(3)Substract (3) from (1)⇒ - a^2y + aby + a^2b +ab^2-2ab^2= 0⇒ y(ab – a^2) = ab^2-a^2b⇒ ya(b – a) = ab(b-a)⇒ y = bsub y =b in equ (2)we get (bx) - (ab) + 2ab = 0⇒ b(x + a) =0⇒ x+a = 0⇒ x = -a. and y =b. subsitution method :⇒ (b^2x - a^2y + a^2b +ab^2) = 0 ---------→(1)⇒ (bx) - (ay) + 2ab = 0 ---------→(2)From (2) x = (ay – 2ab) / b.Sub x in equ (1)⇒ (b^2((ay – 2ab) / b ) - a^2y + a^2b +ab^2) = 0⇒ (aby – 2ab^2- a^2y + a^2b +ab^2) = 0⇒ y(ab – a2) = ab^2-a^2b⇒ ya(b – a) = ab(b-a)⇒ y = bsub y =b in equ (2)we get (bx) - (ab) + 2ab = 0⇒ b(x + a) = 0⇒ x+a = 0⇒ x = -a. |
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