Find the sum of first 51 terms of that arithmetic progression whose se – InterviewSolution

1.	Find the sum of first 51 terms of that arithmetic progression whose second term 14and third term is 18.0.8
Answer» A2 = 14 and a3 = 18Common difference = a3 - a2 = 18 - 14 = 4 = dNow a2 = a+d=14 a+4=14a = 10Now, sum of 51 terms={51(2a+(50)d)}/2={51(20+200)}/2={51×220}/2=51×110=5610Therefore sum of 51 terms is 5610

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