1.

In a G.P., the 3rd term is 24 and the 6th term is 192. Find the 10th term

Answer»

3rd term of the GP = 24 = ar2

6th Term of the GP = 192 = ar5

Hence,

6th term / 3rd term = ar5/ ar2= 192 / 24

r3= (192) / (24)

r3= (2*2*2*2*2*2*3) / (2*2*2*3) = (23)

Hence,r = 2

Since, ar2=24

a(2)2= 24

a = 24/4 = 6

Hence first term,a = 6, andr = 2.

Hence, the 10th term = ar10-1= ar9

10th term = (6)(2)9= 6(2)8(2) = 6(4)4(2) = 6(16)2(2) = (6)(256)(2) = 3072,

Hence the 10th term = 3072.

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