This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
easure the angles, and say which of the following angles are congruent. |
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Answer» By inspection we geta) and d) are congurent. can u plz give explaination a)and d) is congruent because you can see that there all angles,sides are equal as we that congruent means equal |
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| 2. |
] In the following figure, Which of the following anglestogether make supplementary angles?30°70°600200-) |
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Answer» angle AOD and angle BOD are making supplementary angles togetheras 90+90= 180 degree thank you |
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| 3. |
MISCELLANEOUS EXERCISE 1(1) Express the following angles into radians(2) Express the following angles in degrees,(1) 50°37 30" (ii-1040 30"minutes and seconds.( (11.0133) i) (94.3366)° |
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| 4. |
x^{2}+24 x+9=0 |
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| 5. |
x^{2}+10 x+24=0 |
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Answer» the value of x will be -4,-6 the value of x will be -4,-6 |
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| 6. |
any 1150eu in the foll"Qures? Write the name of adjacent angles also:(ii)AΤhof the following angles form adjaceywing angles form adjacent angles and linear pair?F e (ii)(ii)oBeGoure write the name of: |
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Answer» like nd accept my answer best i will try to explain it on video conference with good quality definitely |
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| 7. |
UNDERSTANDING ELEMENTAReach one of the following angles as right, straight, acute, obtuse or reflex :uring Angles |
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Answer» a) acute angleb) obtuse anglec) straight angled) right anglee) obtuse anglef) acute angle right is (c)acute are (a) (f)obtuse are (b) reflex is(d)straight is (e) C is the correct answer |
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| 8. |
What kind of angles are the following angles?Example: 45° acute anglea, 90°-e. 180°-b. 145°-f. 270°C. 10°-g. 360°- |
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Answer» a) right b) obtuse c) acute d) 0 angle e) line f) reflex g) Full circle right obtuse acute 0 angle line reflex complete angle |
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| 9. |
s.P.a) Rs 345016.Rs 3430 and, Discount-2%. Find the MPb) Rs 3475c) Rs 3450d) Rs 3500 |
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Answer» SP = Rs 3430Discount % = 2%Let MP be xSo we get equation,x - 2% of x = 3430x - (2/100) × x = 3430x - x/50 = 343049x/50 = 3430x = (3430×50)/49x = 3500So, MP is Rs 3500option (d) is correct |
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| 10. |
8. If EP- 5x+ 15, PG-31, and EG- 116, find the value of x. The drawing is not to scale.0 x 24x- 7016 |
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Answer» From the figure , EF = 5x+15 = 116-31 = 85 => 5x +15 = 85 => 5x = 85-15 = 70=> x = 70/5 = 14. |
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| 11. |
10. In the figure given, two squares of sides 8 m and 5 m are shown. Find5 cm8 cmthe area of the shaded portion. |
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| 12. |
In a stationarymany packs ofshop Qk9 of sugar is available. How500 grams each can be made ..1 |
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Answer» 4 packets can be made 4 packet can be made 4 packet can be made 4 packets can be made 4 packets of sugar can be made of sugar 4 packet can be made |
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| 13. |
A joker's cap is in the form of a right circular cone' of base radius 7 cm and height24 cm. Find the area of the sheet required to make 10 such caps. |
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| 14. |
an180 miong and 5 m wide is to be paved with pridks aeng andhe cost of Sricks that ase required,at the rate of Rs c |
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| 15. |
2. A toy is made in the form of hemisphere surmounted by a right cone whose circular base isjoined with the plane surface of the hemisphere. The radius of the base of the cone is37 em. and its volume isof the hemisphere. Calculate the height of the cone and the2 |
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Answer» Radius of cone and hemisphere = 7 cm Height of cone be h cm Now, volume of hemisphere = (2/3)πr³ Volume of cone = (1/3)πr²h A/q (1/3)πr²h = (3/2)×[(2/3)πr³]⇒h = 3r = 3×7 = 21 cm Now, surface areaSlant height, l =√[(21)² +(7)²] = 7√10 cm = 22.13 Total surface area = (curvedsurface area of cone + hemisphere) = (πrl + 2πr²) =[(22/7)×7×22.13) + 2(22/7)×(7)²] = 486.86 +308 =794.86 cm² |
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| 16. |
Hence, the total area of lThere is a rectangular field of length 94 m and breadth32m. Three roads each of width 2 m pass through theSeld such that two roads are parallel to the breadth andthe third is parallel to the length. Find the area of the amfeldep0) covered by the three roads.() not covered by the roads.Total |
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| 17. |
3.) A rectangular field has 80 m length and 48 m breadth. Three roads, each of width 2 mpass through the field such that two roads are parallel to the breadth and the third roadparallel to the length. Find the area covered by the three roads |
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Answer» please give me simple ans...... |
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| 18. |
2.A rectangular field is 112 m long and 100 m wide.Two roads, each 3 m wide are to be constructed atthe centre of this field; one is parallel to the lengthof the field and the other is parallel to the breadthof the field.(i) Find the area of the two roads.(ii) Find the area of the part of the field, not coveredby the roads.(ii) Find the cost of constructing the roads at Rs 17per m. |
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| 19. |
a0 Per m. A 115-m-long and 64-m-broad lawn has two roads at right angles, one 2 m wide.12parallel to its length, and the other 2.5 m wide, running parallel to ts breadcost of gravelling the roads at 60 per m2.13. A rectangular field is 50 m by 40 m. It has two roads through its centre, running parallel toits sides. The width of the longer and the shorter roads are 2 m and 2.5-m-respectively.Find the area of the roads and the area of the remaining portion of the field |
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Answer» thank you so much more than just |
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| 20. |
a rectangular field is 30m long 22m wide. let has two cross roads one parallel to its length and other parallel to its breadth find the area of cross roads if each is 1.5m wide |
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Answer» From the figure cross roads are in rectangle shape area of rectangle = l×bar( first road) =30×22=660m squarear(second road )=l×b=22×1.5=33but the two roads intersect at a point so we have to subtract that area 660+33=693693-(1.5×1.5)693-2.25691 |
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| 21. |
I wo cross roads, each of width 5m, ran a right anoles through the centre of rechangfalar park oflength 70 m and breadth 45 m and parallel to its sides Find the area of the roads. Also find thecost of constructing the road at late of 105 per mFind the areas of the shaded portion10 cm E8 cm B |
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| 22. |
PERIMETER AND AREATwo cross roads, each of width 10 m, cut at right angles through the centre of arectangular park of length 700 m and breadth 300 m and parallel to its sides. Find thearea of the roads. Also find the area of the park excluding cross roads. Give theanswer in hectares.6. |
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| 23. |
PERIMETER AND AREAcross roads, each of width 10 m, cut at right angles through the centre of angular park of length 700 m and breadth 300 m and parallel to its sides.Find thearea of the roads. Also find the area of the park excluding cross roads. Give thanswer in hectares.Through a rectangular field of length 90 m and breadth 60 m, two roads a |
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Answer» very nice |
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| 24. |
-=Y| o1iySs£ )¥¥€NGo17N? (ZTQ vJ 0) |
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Answer» Please hit the like button if this helped you |
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| 25. |
man hought a hose and eamiage b k. 303ana th2/on the whoke. Find tive cost 4 thie ase |
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| 26. |
Find thie cost2 A joker's cap is in the form of a right circular cone of base radius 7 em and height24 cm. Find the area of the sheet required to make 10 such caps.0 holiow |
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| 27. |
id thie Tdulus of the ice cream cone.A vessel is in the form of a hemispherical bowl surmounted by a hollowcylinder. The diameter of the hemisphere is 21 cm and the total heightof the vessel is 14.5 cm. Find its capacity.17. |
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| 28. |
A ladder, leaning against a wall, makes an angle of 60° with the horizontalIf the foot of the ladder is 2.5 m away from the wall, find the length of theladder |
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| 29. |
A ladder, leaning against a wall, makes an angle of 60° with the horizontal.If the foot of the ladder is 2.5 m away from the wall, find the length of theladder |
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Answer» Length of ladder=AC=’x’m Here,cos 60o=BC/AC =>1/2=2.5/AC AC=2.5*2 x=5 Length of ladder=x=5m |
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| 30. |
7. If astv, then find the value of ut |
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| 31. |
ÂŽxTcoxl = |
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| 32. |
112°Xt(iv) Square |
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Answer» since the figue is square.. so diagonal will divide the angles in to 45° each. angle DXC= 112° so, 112° + angle(CXY) = 180° ...( linear pair) therefore angle CXY = 180°-112° = 68° so,. in ∆ CXY angle ACB = 45° and , sum of the angles will be 180° => y + angle ACB + CaY = 180° => y = 180-45-68 = 67° |
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| 33. |
किन हे ato:Y Aeng = 2= Nusoe o ७०७ = CeSe_ot % e S e i e० ७ २४ |
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| 34. |
25 x 52 xt10'xt |
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Answer» 5\ mein 2 ki power 3 multiply t ki power 3 |
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| 35. |
g. xtrt3 |
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Answer» g. x+2/3 = 4/3or, x = 4/3-2/3or, x = 2/3 (Ans) x=2 in this equation x+2/3=4/3x=4/3+2/3x =2/3 is the best answer x+2/3=4/3x=4/3-2/3x=2/3is the best answer X=2/3 is the correct answer |
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| 36. |
Ex. (4) Area of the base of a cone is 1386 sq.cm and its height is 28 cmFind its surface area. (Ď =-) |
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Answer» Area of the base of a cone = 1386sq.cm. Height,h= 28cm. Surface are = ?? Therefore by using the formula , Area of base of cone = pi*r^2 1386 = 22/7*r^2 1386*7/22 = r^2 63*7 = r^2 441 = r^2 r = 21cm. We got the radius. Now we find the slant height, We know that, l^2 = r^2 + h^2 l^2= (21)^2 + (28)^2 l^2 = 441 + 784 l^2 = 1225 l = 35cm. So we got the value of radius and slant height now we can easily find the surface area of cone. By using the formula, Surface are of a cone= pi * r*l = 22/7*21*35 =22*3*5 = 330sq.cm. |
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| 37. |
(नशे,xT जज |थे लि |
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Answer» 2x/(x - 4) + (2x-5)/(x - 3) = 25/3 [2x(x-3) + (2x-5)(x-4)]3 =(x-4)(x-3)*25 (2x^2 - 6x + 2x^2 - 8x - 5x + 20)3 = (x^2 - 3x - 4x + 12) 25 (4x^2 - 19x + 20)3 = (x^2 - 7x + 12)25 25x^2 - 12x^2 - 175x + 57x + 300 - 60 = 0 13x^2 - 118x + 240 = 0 13x^2 - 78x - 40x + 240 = 0 13x(x - 6) - 40(x - 6) = 0 (13x - 40)(x - 6) = 0 x = 40/13, 6 |
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| 38. |
Ex- 11.201Find the area of cach of the following faralelogramas: |
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| 39. |
EX:3.1=ben4 anun2x ole ftoh & th)218x ut ux ut 804)2(32 + 16 +32)80X2(60 cm2 |
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| 40. |
ut19290 7 |
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Answer» 100 must be multiplied with 192 to get 19200. |
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| 41. |
UT 22 tan 2 |
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| 42. |
enathu but |
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Answer» On folding it forms a cuboid with length, l = 48 – 16 = 32 cmBreadth, b = 36 – 16 = 20 cmHeight, h = 8 cmVolume of cuboid = lbh cubic units= 32 x 20 x 8= 5120 cu cm |
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| 43. |
12.Which of the following algebraic expressions are(ii)(iv)polynomials?(i) 2x2-5x +1Ó_3y5-r+3x2-1x3ori-3p + 1(iii)(2b+13-Vi |
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Answer» except (vi) all are polynomial as in (vi) we have 1/x^2 term i.e. a term x^(-2) having negitive powee so it is not a polynomial. All the exponents in the algebraicexpressionmust be non-negative integers in order for the algebraicexpressionto be apolynomial. ... Each x in the algebraicexpression appears in the numerator and the exponent is a positive (or zero) integer. Therefore this is apolynomial. so, polynomial are i, ii, iii, iv, v |
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| 44. |
JIU3.Which of the following contains maximum numberof oxygen atoms?(1) 1 g of o(2) 1 g of O,(3) 1 g of Og(4) all have the same number of atoms |
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Answer» 2 second option is the answer option 3is correct answer Option 1st is correct answer........... 1g of O.. Mole of 1st is greater. So it also contain maximum no. Of oxygen atom. the third option is correct last answered is correct 1st option is correct I think it is 3...'''''°•••~~~~` I think it is 3...''''' |
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| 45. |
Board Questions17. Ifthe 2nd term of an AP is 8 and the 5thterm is 17, find its 19th term. [CBSE 2016] |
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Answer» tq |
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| 46. |
Explain why 13233343563715 is a compositenumber ? [Board Term-1, 2016 Set LGRKEGO] |
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Answer» 13233343563715 , this number can divided evenly by 5 ( as well as 1 or itself) thats why its become composite number. |
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| 47. |
A Q. 9. In the figure, I n. Prove that<1 + 2-23 = 180°.2леBoard Term I, 2016, |
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| 48. |
If A + B90° and sec A-5 , then find the valueof cosec B.[Board Term-1, 2016, Set-ORDAWEZ |
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| 49. |
R Q. 1. How many faces does a right circular cylinderhave? Board Term II, Set-RQTZFBW, 2016] |
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Answer» It has three faces. 1. Top flat face 2. Bottom flat face 3. Curved face |
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| 50. |
Indentify the constant torn in thefollowing algebraic expressions,(a) sab+40+5 |
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Answer» 8'4'5 are constant. plz like the constant answer of algebraic expression is 5 As there is no variable like a,b or c with 5 , so 5 is a constant term here 5 is the constant because it's not change in any condition but 8ab and 4c depend on the value of a and b 8 4 5 are constant term constant term is that term whose degree is 0 ( on the variable term like as x to power 0 which gives out the ans 1 ). so in this expression 5 is constant the constant of this algebraic expressions is 5 here constant will be the number which is in the equationas 8 4 and 5 8,4,5 are constant and ab, c are variable in this question only we can find constant term As there is no variable like a,b,or,c with5,so5 hoga answer constant term is 5 in expression new question answer 8 and 4 are coefficients of ab and where as 5 is the constant term 5 in the constant because it's not change in any condition but 8ab and 4c depend on the value of a and b 8, 4 , 5 are the constant term the constant in the following equation is 5. |
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