112°Xt(iv) Square

1.	112°Xt(iv) Square
Answer» since the figue is square.. so diagonal will divide the angles in to 45° each. angle DXC= 112° so, 112° + angle(CXY) = 180° ...( linear pair) therefore angle CXY = 180°-112° = 68° so,. in ∆ CXY angle ACB = 45° and , sum of the angles will be 180° => y + angle ACB + CaY = 180° => y = 180-45-68 = 67°

Answer»

since the figue is square.. so diagonal will divide the angles in to 45° each. angle DXC= 112° so, 112° + angle(CXY) = 180° ...( linear pair)

therefore angle CXY = 180°-112° = 68°

so,. in ∆ CXY angle ACB = 45° and , sum of the angles will be 180° => y + angle ACB + CaY = 180° => y = 180-45-68 = 67°

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