(नशे,xT जज |थे लि

1.	(नशे,xT जज \|थे लि
Answer» 2x/(x - 4) + (2x-5)/(x - 3) = 25/3 [2x(x-3) + (2x-5)(x-4)]3 =(x-4)(x-3)*25 (2x^2 - 6x + 2x^2 - 8x - 5x + 20)3 = (x^2 - 3x - 4x + 12) 25 (4x^2 - 19x + 20)3 = (x^2 - 7x + 12)25 25x^2 - 12x^2 - 175x + 57x + 300 - 60 = 0 13x^2 - 118x + 240 = 0 13x^2 - 78x - 40x + 240 = 0 13x(x - 6) - 40(x - 6) = 0 (13x - 40)(x - 6) = 0 x = 40/13, 6

Answer»

2x/(x - 4) + (2x-5)/(x - 3) = 25/3

[2x(x-3) + (2x-5)(x-4)]3 =(x-4)(x-3)*25

(2x^2 - 6x + 2x^2 - 8x - 5x + 20)3 = (x^2 - 3x - 4x + 12) 25

(4x^2 - 19x + 20)3 = (x^2 - 7x + 12)25

25x^2 - 12x^2 - 175x + 57x + 300 - 60 = 0

13x^2 - 118x + 240 = 0

13x^2 - 78x - 40x + 240 = 0

13x(x - 6) - 40(x - 6) = 0

(13x - 40)(x - 6) = 0

x = 40/13, 6

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