2. A toy is made in the form of hemisphere surmounted by a right cone

1.	2. A toy is made in the form of hemisphere surmounted by a right cone whose circular base isjoined with the plane surface of the hemisphere. The radius of the base of the cone is37 em. and its volume isof the hemisphere. Calculate the height of the cone and the2
Answer» Radius of cone and hemisphere = 7 cm Height of cone be h cm Now, volume of hemisphere = (2/3)πr³ Volume of cone = (1/3)πr²h A/q (1/3)πr²h = (3/2)×[(2/3)πr³]⇒h = 3r = 3×7 = 21 cm Now, surface areaSlant height, l =√[(21)² +(7)²] = 7√10 cm = 22.13 Total surface area = (curvedsurface area of cone + hemisphere) = (πrl + 2πr²) =[(22/7)×7×22.13) + 2(22/7)×(7)²] = 486.86 +308 =794.86 cm²

2. A toy is made in the form of hemisphere surmounted by a right cone whose circular base isjoined with the plane surface of the hemisphere. The radius of the base of the cone is37 em. and its volume isof the hemisphere. Calculate the height of the cone and the2

Answer»

Radius of cone and hemisphere = 7 cm

Height of cone be h cm

Now, volume of hemisphere = (2/3)πr³

Volume of cone = (1/3)πr²h

A/q

(1/3)πr²h = (3/2)×[(2/3)πr³]⇒h = 3r = 3×7 = 21 cm

Now, surface areaSlant height, l =√[(21)² +(7)²] = 7√10 cm = 22.13

Total surface area = (curvedsurface area of cone + hemisphere) = (πrl + 2πr²) =[(22/7)×7×22.13) + 2(22/7)×(7)²] = 486.86 +308 =794.86 cm²