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addition subtraction and multiplication

addition subtraction and multiplication

Addition Subtraction and multiplication

Let shortest side of right triangle be xThen, hypotenuse h = 2x + 1Third side y = x + 7

Using pythagoras theoram,h^2 = x^2 + y^2Put value of h and y(2x + 1)^2 = x^2 + (x + 7)^24x^2 + 1 + 4x = x^2 + x^2 + 49 + 14x4x^2 - 2x^2 + 4x - 14x + 1 - 49 = 02x^2 - 10x - 48 = 0x^2 - 5x - 24 = 0x^2 + 8x - 3x - 24 = 0x(x + 8) - 3(x + 8) = 0(x - 3)(x + 8) = 0x = 3, - 8

Negative value not possible

Therefore,Sides of grassy land areShortest side = x = 3 mHypotenuse = 2x + 1 = 2*3 + 1 = 7 mThird side = x + 7 = 10 m

3^-5 * 10^-5 * 125/ 5^-7 * 6^-5= 3^-5 * (2*5)^-5 * (5)^3 / 5^-7 * (2*3)^-5= 3^-[5+5]* (2)^[-5+5]*(5)^[3-5 +7]= 3^0*2^0*5^5= 1*1*3125= 3125

Let a be a positive integer.

According to Euclid division lemma, a = bq + r where 0 ≤ r < b.

Let b = 8 ,then, a = 8q + r

r can be 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 .

Let's consider r = 0 them a = 8q

Cubing on both sides we get,

a³ = (8q)³ = 512q³ = 8(64q³) = 8m where m = 64q³

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If r = 1 , then a = 8q +1

a³ = (8q + 1)³ a³ = 512q³ + 1 + 3(8q)(8q+1) = 512q³ + 1 + 24q(8q+1) = 512q³ + 1 + 192q² + 24q = 8( 64q³ + 24q² + 3q) + 1 = 8m + 1 where m = 64q³ + 24q² + 3q

===========================

If r = 2 ,

a = 8q + 2 a³ = (8q+2)³ = 512q³ + 8 + 48q(8q+2)= 512q³ + 8 + 384q²+ 96q= 512q³ + 384q²+ 96q + 8= 8 ( 64q³ + 48q² + 12q + 1 )= 8m where m = 64q³ + 48q² + 12q+ 1

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if r = 3

then a = 8q + 3 a = (8q+3)³= 512q³+27+72q(8q+3)= 8(64q³+ 3 + 72q²+ 27q ) + 3 = 8m+ 3 where m = 64q³ + 72q² + 27q+3)

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If r = 4 a = 8q + 4 a³ = 512q³+ 64 + 768q² + 384q a³ = 8( 64q³ + 8 + 96q² + 48q)

a³ = 8m where m = 64q³ + 8 + 96q² + 48q

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when r = 5 a = 8q + 5 a³ = (8q+5)³ = 512q³ + 960q² + 600q + 125= 8 ( 64q³ + 120q² + 75q + 15) + 5 = 8m + 5

where m = 64q³ + 120q² + 75q + 15===========================

if r = 6 .

then a = 8q + 6 a³ = ( 8q + 6)^3 = 512q³ + 1152q² + 864q + 216 = 8 ( 64q³ + 144q² + 108q + 27 )= 8m

where m = 64q³ + 144q² + 108q + 27

===========================

if r = 7 a = 8q + 7a³ = (8q + 7)³ = 512q³ + 343 + 1344q² + 1176 q = 8( 64q³ + 168q² + 147q + 42) + 7 = 8m + 7

where m = 64q³ + 168q² + 147q + 42===========================

Therefore, We proved that cube of a positive integer will be of the form 8m , 8m+ 1 , 8m+3 , 8m+5 , 8m+ 7 where m is a whole number.

Let length of room be xThen breadth = (x+5)/3

Area1 = length * breadth = x*(x+5)/3

If length and breadth increase by 1Area2 = (x+1)(x+8)/3

As per given condition

Area2 - Area1 = 12(x^2 + 9x + 8) - (x^2 + 5x) = 364x = 36-84x = 28x = 7

Dimension of roomLength = x = 7 mBreadth = (x +5)/3 = 12/3 = 4 m

Let the number be x.

Thus the statement can be expressed as an algebraic expression in the following way:

2x+3

1. x-2=8 x=8-2=6.2. 5p=35 p=35/5=7.

nahi galat hai

answer i-10. ii-7

Given : y = x + 4 , So any (a,b) satisfies this means putting x = a and y = b must satisfied given Equation.B) (7,19)x + 4 = 7 + 4 = 11 which is not equal to 19

ok thanks

which of the following is not a quadratic equation

Total outcomes (no.) :1002ndfavourable : 50probability = 50/100 =1/21stfavourable : 12probability = 12/100 = 3/25

LHS = x^log base 5 (x)at x= 5 it LHS is 5 so the least Integral value will be 6. so x = 6

1

2

Convert in single unitshence converting in kghence 30kg 360gm=30.360kgShe lost 3.485kghence subtract30.360-3.485=26.875kgthat is 26kg 875gm

CP for vas = a

SP for vas = CP of Radha

= a x 120/100 = 1.2a

SP of Radha = CP of man

1.2a x 104/100 = 624

124.8a = 62400

a = 62400/124.8 = 500

CP of the article = Rs.500

Let cost price of article for vas = CP SP for vas = CP(1 + 20/100) = CP(6/5)

cost price of article for Radha = CP(6/5)SP for Radha = CP(6/5)(1 + 4/100) = CP(6/5)(26/25) = CP(156/125)

Given

CP(156/125) = 624CP = (624*125)/156 = 4*125CP = 500

Article cost vas for Rs 500

The “curl up” is also known as a crunch. Thistestmeasures abdominal strength and endurance.

Thistestfocuses predominantly on the main abdominal muscle, the rectus abdominus, and may not evaluate the core as a whole.

The partial curl-up has been recommended as a better test of abdominal muscular endurance, replacing the one- minute speed sit-up

thanx bt I have already done it

Euclid’s Division Lemma:

According to Euclid’s Division Lemma if we have two positive integers a and b, then there exists unique integersqandrwhich satisfies the conditiona = bq + rwhere 0≤ r ≤ b.

The basis of Euclidean division algorithm is Euclid’s division lemma. To calculate the Highest Common Factor (HCF) of two positive integersaandbwe use Euclid’s division algorithm. HCF is the largest number which exactly divides two or more positive integers. By exactly we mean that on dividing both the

Area of lawn = 50*36 = 1800 sq m.Area of lawn plus path = (50+4)(36+4)= 54*40= 2160 sq mArea of path = Area of lawn plus path - Area of lawn= 2160 - 1800= 360 sq m

A lawn 10m by 8m is surrounded by a path 1m wide. Find the area of the path

length(l) of lawn = 50m breadth(b)of lawn = 36m width of path = 2m so the, length(L) of outer rectangle = 50+2+2 = 54m breadth(B) of outer rectangle = 36+2+2 = 40m Area of path =Area of outer rectangle - Area of inner lawn = L×B - l×b = 54×40 - 50×36 = 2160 - 1800 =360m^2 Cost of levelling path = 360×3.25 =Rs.1170

length(l) of lawn = 50m breadth(b)of lawn = 36m width of path = 2m so the, length(L) of outer rectangle = 50+2+2 = 54m breadth(B) of outer rectangle = 36+2+2 = 40m Area of path =Area of outer rectangle - Area of inner lawn = L×B - l×b = 54×40 - 50×36 = 2160 - 1800 =360m^2 Cost of levelling path = 360×16 =Rs.5760

Thanks

length(l) of lawn = 50m breadth(b)of lawn = 36m width of path = 2m so the, length(L) of outer rectangle = 50+2+2 = 54m breadth(B) of outer rectangle = 36+2+2 = 40m Area of path =Area of outer rectangle - Area of inner lawn = L×B - l×b = 54×40 - 50×36 = 2160 - 1800 =360m^2 Cost of levelling path = 360×3.25 =Rs.1170

It will be 1' o clock pm

it will be ,1 pm please find in your mathematics books non ANCRT

Answer is 470 approx

Large bird house in 1 week = 78In 6 week = 6*78= 468So best estimate is H 480

Large bird house in 1 week = 78In 6 week = 6x78 = 468so best estimate is H 480

Total number of balls= 5 blue + 4 red = 9 balls

Probability = possible outcomes / total outcomes

(i) Probability that ball drawn is blue = 5/9

(ii) Probability that ball drawn is not blue =1 - 5/9 = (9 - 5)/9 = 4/9

d=12 a=2.8 n12=a+11d =2.8+11(0.2) =2.8+2.2 =5

ball need to be not blue but can be red and green so probability=17C1/22C1=17/22