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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A bag contains 5 red balls and some blue balls. If the probability ofdrawing a blue ball from the bag is thrice that of a red ball, find thenumber of blue balls in the bagCBSE 2007 |
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| 2. |
(d) 4.5%10. Kruti took some loan at 6%interest during the first year with a0.5% for each year. After 4 y*3375 as interest. How much wasper annum simpler with an increase offter 4 years she paidy much was the loan?(a)(b)1250033250 |
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Answer» 12500 Let the loan taken be Rs. X , then X × 6/100 × 1 + X × 6.5/100 × 1 + X × 7/100 × 1 + X × 7.5/100 × 1 = 3375 => (6+ 6.5 +7 +7.5) × X/100 = 3375 => X = (3375 × 100/27) = 12500 |
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| 3. |
n ith term ofan A.P. is (2n+1), what is the sum of its first three terms?5. In figure if AD-6cm, DB-9cm, AE- 8em and EC 12cm and ZADE 48°. Find ZABC488A fter hoU |
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| 4. |
The coach of a cricket team buys 3 bats and 6 balls for 3900. Later, she buys anotherbat and 3 more balls of the same kind for 1300, Represent this situation algebraicallyand geometrically.2.fouun d to be 5 160 A fter a |
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| 5. |
“Powe . डाँठि ने धो 10*-. L + SRS eAan Rt iy |
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| 6. |
33UUid=5 तथा s = 75 दिया है तो तथा a का मान निकालिए।ne.--AN |
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Answer» let 1st term =as9=759/2{2a+(9-1)×5}=7518a+360=15018a= 150-360= -210a= -210/18= -35/3a9= a+(n-1)d = -35/3+(9-1)×5 = -35/3+40 = -35+120/3= 85/3a9=a+(n-1)d = -11/3+(9-1) |
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| 7. |
The general solution of the equation sin x + cos N - V2 cos A is6(Where ne ID) |
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Answer» multiply and divide L H.S , by √2 sinx+cosx = √2(sinx/√2 +cosx/√2) = √2cos(x-π/4) now √2cos(x-π/4) = √2cos(A) => x-π/4= 2nπ ±A => x = 2nπ+π/4 ±A option A |
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| 8. |
\frac 81 4 \cdot 5 \text ant 417 |
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Answer» 81/4.5 =810/45 =18 |
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| 9. |
LET'S EVALUATE+35* 602525idin all?in the1. Fill in the blanks(a) 6 =(c) 715 p = ?2. Add.(a) 96, 242.34(c) 78.75, 94.32 and 7 631.60ave aMake |
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Answer» a)rs6=600pc)715p=0.715rd2)a)338.34 a)600pb)0.715rs2)a)338.4 a. ₹6 = 600p. 1₹ = 100 pc. 715p = 715/100 = 7.15₹2a. 96+242.34 =338.34 2b. 8.75+94.32+631.60 =734.67 1 (a) Rs6= 600p1(c) 715p=Rs 0.75 1A) 600pC)7rs 15 paisa 2a)338.34 rsC) 734.67rs 1.a) ₹ 6 = 600 pc) 715p = 7₹ 15 p2.a) 96.00 +242.34____________ 338.34 b) 8.75 + 94.32 +631.60 ___________ 734.67 a) 600pc) 0.715rd2)a)338.34answer. q.1a. 600pc.7rupees 15 paise |
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| 10. |
6.Find the smallest number which when multiplied with 3600 will make nea perfect cube. Further, find the cube root of the product. |
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Answer» using prime factorisation, 3600 = 2x2x2x2x3x3x5x5=2^3 *2*3*3*5*5So this number should be multiplied by 2*2*3*5=60 |
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| 11. |
4.5.Pinu the largest 3-uyit Humvel wit WAY MINI My wIn a parade, the soldiers are arranged in 14 rows. If the number of soldiers is504, find the number of soldiers in each row. |
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Answer» SinceNo. Of rows X no. Of soldier in one row= total no. Of soldiersLet the no. Of soldier in each row be x14x X=504X=504/14X=36 |
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| 12. |
A box contains 42 blue and 22 black pens. A student wants to buy a blue pen. He picks up apen at random and found it to be black. Holding the pen in his hand, he picks up anotherone at random without looking inside the box. What is the probability that the second pen isblue one? |
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Answer» probablity of blue=42+21=63 64 probably total 64 pen |
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| 13. |
5. A student reaches her school in 20 minuteswith an average speed of 12 km/h. If shewants to reach her school 8 minute earlier,her speed should be(A) 8 km/hr(C) 20 km/hr(B) 12 km/hr15 km/hr |
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Answer» Distance to be travelled= Speed*Time= 12*(20/60)= 4 kmsIf he needs to reach 8 minutes earlier, time = 20-8 = 12 minutes = (12/60) hoursSpeed= Distance/Time= 4/(12/60)= 4*5= 20 km/hr Please hit the like button if this helped you but i ticked 15km/ hr |
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| 14. |
Q.9. A student wants to project the image of acnmirror bing the flame at a distance of 15 cm froma candeflame on a screen 60 cm in front of a minpole.(i) Write the type of mirror he should use.(i) Find the linear magnification of the imugii) What is the distance between the object and isiv) Draw a ray diagram to show the image formationBoard Term II, Outside Delhi Set I, 2014e imageproduced.image ?in this case. |
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Answer» (i) Concave mirror (ii) m = -v/u = -(-60)/(-15) = -4 (iii) Distance between object and image = (-15) - (-60) = 45 cm |
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| 15. |
The auditorium of a school can seat 417 people at a time. The principal of thatschool wants all the 9591 students of all the local schools to see a special film onsaving wild life for free. How many times must the film be shown, so that everstudent sees the film once? What value does the principal want to inculcate inthe children?O 8.Value Based Questio |
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| 16. |
AVERAGEThe average of the marks obtained in anexamination by 8 student was 51 and byother student was 68. The average marksof the 17 student is:(a) 59(b) 59.5(c) 60(d) 60.5 |
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Answer» The average of mark obtained in an examination by 8 students was 51 Let total marks of 8 students be x Let total marks of other 9 students be y Then, x/8 = 51x = 51*8x = 408 the average of other 9 = 68y/9 = 68y = 68*9y = 612 Therefore, average marks of all 17 students = (x + y) /17= 1020 / 1= 60 Average marks of all 17 students = 60 marks (c) is correct option |
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| 17. |
product of two rational numbers is 8. If one of thtowhat number should be divided to get 0?1613HOTS QUESTIONS |
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| 18. |
ON C. HOTS QUESTIONSpole of telephone line is in the middle of a pond. One-sixth of the length of the pole isCTIunderground, one-fourth is in the water and the remaining 14 m is above the water. Howlong is the pole?157 |
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Answer» x = x/6 + x/4 + 14 x = 4x+6x+336/24 24x-10x = 336 14x = 336 x = 24 m |
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| 19. |
dx7 कब: ली. |
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Answer» y = x³ dy---- = 3x²dx d²y----- = 6xdx² |
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| 20. |
dx1 2x² – 5x+7 |
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| 21. |
man is thrice as old as his son. Five years ago the man was four times as old as his son.Find their present ages. |
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| 22. |
A man is thrice as old as his son. Five years ago the man was four times as old as his son.Find their present ages.16. |
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| 23. |
I paid 15. I bought three things. What did I buy?I bought a ..and a |
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Answer» a pen , a pencil and a shopner |
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| 24. |
16. A man is thrice as old as his son. Five years ago the man was four times as old as his son.Find their present ages. |
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| 25. |
B. Answer the following questions.(a) What per cent of numbers from 1 to 20 are divisible by 4? |
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Answer» Total numbers between 1 to 20 = 20Divisible by :- 4 = 4, 8, 12, 16, 20Total Factors = 5So, 5/20 × 100 = 25% |
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| 26. |
\begin{array}{l}{\text { V. Evaluate the following: }} \\ {\text { 1. } \int \frac{2 x+7}{(x-4)^{2}} d x}\end{array} |
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| 27. |
If sec θx +prove that sec θ + tan θ2x4xor[Board Term-1, 2011, Set-55]2x |
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| 28. |
(क) हल कीजिए :37x + 43 V=12343x + 37y =117 |
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Answer» thanks |
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| 29. |
3.If the zeros of the polynomíalf(x)2x3-15% +37x-30 are in A.P., find them. |
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| 30. |
3. If the zeros of the polynomial f(x)-2-15x2 +37x -30 are in A.P, find the |
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| 31. |
Question-5A bag contains 5 red balls and some blue balls. If the probability of drawinga blue ball is double that of a red ball, find the number of blue balls in thebag. |
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Answer» Red balls=5; let blue balls=x; p(B)=x /x+5;p(R)=5/x+5;p(B)=2(p(r));x/x+5=2(5/ x+5); x=10 |
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| 32. |
3¡The squares ofwhich ofthe following would be odd numbers?0 431(ii) 2826(ii) 7779 |
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Answer» The square of i) and iii) are odd numbers. |
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| 33. |
3. निम्नलिखित संख्याओं में से किस संख्या का वर्ग विषम संख्या होगा?(1) 431(ii) 2826 (iii) 7779|(iv)।fermam |
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Answer» IV ) is the correct answer last one is correct 4) is the right answet The correct answer is last one option 4 is the correct answer of the given question |
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| 34. |
प्रत्येक #.2. के लिए प्रथम पद तथा सार्व अंतर लिखिए ६.B 51376 v) - 0:6,1.7.,2.8,3.9588 ]«.a0 PR g & |
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| 35. |
EzamplesvEvaluate:1.pr, dr. |
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| 36. |
MathDate:PageTest whether the following numbersare divisibile by 3018.327 )8253 (1) 433.99(D5637V 767646 (11) 9659666 |
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Answer» 8253,5697,767646,96596664 are divisible by 3&9 all the no. are divisible by 3and 8253,5697,767646,96596664 are. divisible by both 3 and 9 8253,5697,767656,96596664 are divisible by 3&9 i) 327/3=109, ii)8253/3=2751/3=917/3=305.66. iii)43399/3=14466.33 iv)5697/3=1899/3=633/3=211/3=70.333, v)767646=255882/3=85294/3=28431.333, vi)9659664/3=3219888/3=1073296/3=357765.333 all is divisible by 3...... all are divisible by 3 all no are divisble by 3and 2,4,5,6 are divisible by both 3 and 9 |
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| 37. |
(v) 64000(i)89722The squares of which of the following would be odd numbers?1) 4313.(im) 7779nd findthe missing digits.â 2826 |
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Answer» squares of 1st and 3rd optiOn will be odd because their end digit is odd. |
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| 38. |
The perimeter of a rhombus is 52 cm. One ofthe diagonals is 24 cm. Find the area of therhombus.Board Term 1, 2012, Set-431 |
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Answer» perimeter of rhombus = 4a (with side a)4a=52 then a=13,lets length of one diagonal p=24cm,lenght of other diagonal is q;area of rhombus = pq/2using pythogorus theorem a^2= (p/2)^2 + (q/2)^2we will get q=10.then area=10*24/2=120 sq.cm |
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| 39. |
solve by the method of elimination37x+29y=45; 29x+37y=21 |
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| 40. |
Find the product and verify the result, when x = 8 y(a)(c)5.2, z =-4;(-3x) (-4xyz)(8x'yZ2 ) (Sy)(b) (9z2) (4y)(d) (7xyz) (9yz2)(f) (6xy) (7xz)2,2-22 ,,2,2 |
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| 41. |
6-431 × 6.431 × 6.431 +-569 × .569 × .56916.431 × 6-431-6.431x .569 +-569 ×-569 ) |
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| 42. |
0) 10S(V) 6400089722following would be odd numbers?(vi)3.The squares of which of the(i)431(a) 2826(n) 7779Tvh Oserve the following patterm and find the missing digits |
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Answer» i..431iii. 7779 please full explain 431 sq of 431=185761& 7779=60512841 which is odd number |
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| 43. |
pansebectcreatebothandfunction.emplismreducedsoftwareascrultipledifinationmittedto theuperatororMatrix1-122 10 2.43 |
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| 44. |
0=5+431— .46 |
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| 45. |
PrDateV)362. |
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| 46. |
Find change in vDate2. |
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| 47. |
431 |
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Answer» option (1),(3) is the correct answer of the given question option 1) 431 and option 3) 7779 square of option 1 and 2. |
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| 48. |
Check whether the st puheidimăe |
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| 49. |
paltieseghents(2) From the figure, decide whether line i130°is parallel to line m or not. Give reason.509nt |
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Answer» x=130°(vertically opposite angle)x+50°=130°+50°=180°so the sum of adjacent pair is 180° that means line l is parallel to the line my=50°(vertically opposite angle) |
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| 50. |
Is the square of 431 a odd no. or even no.? |
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Answer» 431 * 431 = 185761 odd no. |
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