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The perimeter of a rhombus is 52 cm. One ofthe diagonals is 24 cm. Find the area of therhombus.Board Term 1, 2012, Set-431 |
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Answer» perimeter of rhombus = 4a (with side a)4a=52 then a=13,lets length of one diagonal p=24cm,lenght of other diagonal is q;area of rhombus = pq/2using pythogorus theorem a^2= (p/2)^2 + (q/2)^2we will get q=10.then area=10*24/2=120 sq.cm |
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