Three times the width of a room exceeds the length by 5 m. If the leng

1.	Three times the width of a room exceeds the length by 5 m. If the length and breadtheach are increased by 1 m, then the area is increased by 12 sqm. Find the dimensionsof the room.
Answer» Let length of room be xThen breadth = (x+5)/3 Area1 = length * breadth = x*(x+5)/3 If length and breadth increase by 1Area2 = (x+1)(x+8)/3 As per given condition Area2 - Area1 = 12(x^2 + 9x + 8) - (x^2 + 5x) = 364x = 36-84x = 28x = 7 Dimension of roomLength = x = 7 mBreadth = (x +5)/3 = 12/3 = 4 m

Three times the width of a room exceeds the length by 5 m. If the length and breadtheach are increased by 1 m, then the area is increased by 12 sqm. Find the dimensionsof the room.

Answer»

Let length of room be xThen breadth = (x+5)/3

Area1 = length * breadth = x*(x+5)/3

If length and breadth increase by 1Area2 = (x+1)(x+8)/3

As per given condition

Area2 - Area1 = 12(x^2 + 9x + 8) - (x^2 + 5x) = 364x = 36-84x = 28x = 7

Dimension of roomLength = x = 7 mBreadth = (x +5)/3 = 12/3 = 4 m