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relation and function of class 12.

i) (0.6254)² = 0.39112516ii) (0.6254)³ = 0.244609675064

1

f(3) = (3)² = 9 at x = 3 ..and at x = 3+ , f(x) = 3*3 = 9

so, f(x) is continuous and it is a function

but g(2) at x = 2 is (2)² = 4... and at x=2+ , it is 3*2 = 6

so, 6≠4... so, it is not a function..

∠PQR= ∠PRQ

To prove:∠PQS= ∠PRTProof:∠PQR+∠PQS =180° (by LinearPair axiom)∠PQS=180°– ∠PQR— (i)

∠PRQ+∠PRT= 180° (by Linear Pair axiom)

∠PRT= 180° – ∠PRQ

∠PRQ=180°– ∠PQR — (ii)

[∠PQR = ∠PRQ]

From (i) and (ii)∠PQS= ∠PRT= 180°– ∠PQR

∠PQS= ∠PRTHence, ∠PQS = ∠PRT

AU ∅i= {6.9.11}A∩∅= null

Total area of rectangle-3(area of circle )160*80 - 3(π20²)12800-2(3.14)20²12800-2512=10288cm²

L' hopital. lawdiffrentiation of denominator and numeratore^x-0/1-0now put limitso Answer = e^5

Area of Reactangular sheet= length * breadth= 160*80= 12800 cm^2

Area of circular sheet= pi*r*r= 22/7*21*21= 22*3*21

Area of 3 circular sheet= 9*21*22= 4158 cm^2

Therefore,Area of remaining sheet= 12800 - 4158= 8642 cm^2

Given sequence forms a pattern

Firsr term = 7Second term = 7*2 + 1 = 15Third term = 15*2 + 1 = 31

Therefore,Fourth term = 31*2 + 1x = 62 + 1 = 63

thanks

The coefficient of variation (CV) is a measure of relative variability. It is the ratio of the standard deviation to the mean (average). For example, the expression “The standard deviation is 15% of the mean” is a CV.

The CV is particularly useful when you want to compare results from two different surveys or tests that have different measures or values. For example, if you are comparing the results from two tests that have different scoring mechanisms. If sample A has a CV of 12% and sample B has a CV of 25%, you would say that sample B has more variation, relative to its mean.

Formula

The formula for the coefficient of variation is:

Coefficient of Variation = (Standard Deviation / Mean) * 100.In symbols: CV = (SD/xbar) * 100.

Multiplying the coefficient by 100 is an optional step to get a percentage, as opposed to a decimal.

1answer 600. 2answer1500000.3answer9507.4answet2000955.3answer9507,4answer2000955,

i) 20x255x50x6=1,530,000 ii)79×4319+4319×11=341,201+47,509=389, 710

1991 x 1005 = 2 0 0 0, 9 5 5

1991 x 1005 = 2000,955

As the highest capacity of the smallese drum is 25 itres, both drum can be filled for 25 liters for maximum.

If it runs 5 liter petrol = 220Then it run in 1 liter petrol = 220/5so, it travel = 44so., it will run 66. Km in 1.5 liter petrol

Diameter is given 4.2cm

Therefore Radius=Diameter\2

So, 4.2\2

= 2.1cmSo, the spherical shape of the solid will be

=(4\3 x pie x r3)=(4\3 x 22\2 x 2.1 x 2.1 x 2.1) cm^3=(814.968\21) cm^3=38.808 cm^3

(x-V-y)(x+V-y)=(x)^2 - (V-y)^2=x^2-y; ; ( x)^2=y

9i is right answer.....

x/y +y/x = -1

=> (x²+y²)/xy = -1=> x²+y² = -xy. => x²+y²+xy = 0

so, x³-y³ = (x-y)(x²+y²+xy) => x³-y³ = (x-y)(0) = 0

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please like my answer if you find it useful

thank u so much

5005 shhets of the same paper weight 16 2/3 kilograms

5005 sheet of same paper weight16 2/3 kilogram

5005 sheet of sa.e paper weight16 2/3 kilogram.

we take lower side as cuboid and upper side as half cylinder FORMULA=L×B×H+pie×r2×h/2volume =133,000

First find weight of one sheetthat is 30/9=3.33gmhence for 1 1/4 kg=5/4kg=5/4*1000=1250gmHenceNo of sheets will be 1250/3.33=375.375sheets

Weight of one sheet=x12x=40 gx=40/12=3.33 gtotal weight=5/2 kg=2.5 kg=2500 gnumber of sheets=2500/3.33=750 full sheets

option d is the right answer

Ans :- 3x - 14 = x 3x - x = 14 2x = 14 x = 14/2 x = 7

∆ABC ∼ ∆PQRAB/PQ = 1/3Area(∆ABC)/Area(∆PQR) = (AB/PQ)² = (1/3)² = 1/9

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3x-x= 14-82x= 6x= 3

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