1.

If 즈+보=-1, where x关0 and y丈0 find (xa_y®

Answer»

x/y +y/x = -1

=> (x²+y²)/xy = -1=> x²+y² = -xy. => x²+y²+xy = 0

so, x³-y³ = (x-y)(x²+y²+xy) => x³-y³ = (x-y)(0) = 0



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