2-Answer the following questions ssIQuestion 27 to 34-3 marks each)Cha

1.	2-Answer the following questions ssIQuestion 27 to 34-3 marks each)Chapter 6 (From First Test SytlabIn the given rePOR-PROthen prove thatPOs-pMATHEMATICS
Answer» ∠PQR= ∠PRQ To prove:∠PQS= ∠PRTProof:∠PQR+∠PQS =180° (by LinearPair axiom)∠PQS=180°– ∠PQR— (i) ∠PRQ+∠PRT= 180° (by Linear Pair axiom) ∠PRT= 180° – ∠PRQ ∠PRQ=180°– ∠PQR — (ii) [∠PQR = ∠PRQ] From (i) and (ii)∠PQS= ∠PRT= 180°– ∠PQR ∠PQS= ∠PRTHence, ∠PQS = ∠PRT

2-Answer the following questions ssIQuestion 27 to 34-3 marks each)Chapter 6 (From First Test SytlabIn the given rePOR-PROthen prove thatPOs-pMATHEMATICS

Answer»

∠PQR= ∠PRQ

To prove:∠PQS= ∠PRTProof:∠PQR+∠PQS =180° (by LinearPair axiom)∠PQS=180°– ∠PQR— (i)

∠PRQ+∠PRT= 180° (by Linear Pair axiom)

∠PRT= 180° – ∠PRQ

∠PRQ=180°– ∠PQR — (ii)

[∠PQR = ∠PRQ]

From (i) and (ii)∠PQS= ∠PRT= 180°– ∠PQR

∠PQS= ∠PRTHence, ∠PQS = ∠PRT