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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(A)289. Subbof R3. In the following APs, find the missing terms in the boxeso. Ra02 26Rs 1Sumus coen in SeRs 100: when150 o1(i0), 13,(im) 5,(iv) -4,(v), 381so200 oninue iney will, -22 |
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| 2. |
If (26)3 = 1 7576 and (36)3 = 46656, then 30000017576 x 30000046656- |
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Answer» ³√0.000017576 × ³√0.000046656= 26/1000 × 36/1000= 936/1000000= 0.000936 |
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| 3. |
variable. Let us revise it.Ex. (1) Solve the following simultaneou5 x-3 y=8 ; 3 x+y=2 |
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| 4. |
ハ(.. " | 2 ), (2x ㊥13") and (3x +10) . Find all angles as well as value of x.6. One of the angles of a parallelogram is 80°. Find the measure of all the remaining three7. The perimeter of a parallelogram is 180 cm. One of its sides is greater than the other by 30 cmFind the length of the sides of a parallelogram |
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Answer» P=2(a+b) then,Let us a=x and b=(x+30)180cm= 2(x+x+30)cm180=2(2x+30)90=2x+3060=2xx=30.Then a=30cm, b=60cm |
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| 5. |
ALGORITHMobtain the ouedraticequatio , lettlequadr''icegution he ax2 + bK4câăMake the coef aent of x unity by dividing tiroughout by il afit s not uri2c33.(x-5)(x-6)34.7x+--35 |
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Answer» Take the LCM of the denominators = (x-1)(x-2)(x-3)(x-4)Divide the LCM by the denominator of each term and multiply the result with thenumerator of the respective term. (x-3)(x-4) + (x-1)(x-4) + (x-1)(x-2)------------------------------------ = 1/6(x-1)(x-2)(x-3)(x-4) Use formula (x-a)(x-b) = x^2 - (a+b)x + ab x^2 - 7x + 12 + x^2 - 5x + 4 + x^2 - 3x + 2-------------------------------------------- = 1/6(x-1)(x-2)(x-3)(x-4) 3x^2 - 15x + 18--------------------- = 1/6(x-1)(x-2)(x-3)(x-4) 3(x^2 -5x + 6)------------------- = 1/6(x-1)(x-2)(x-3)(x-4) 3(x - 2)(x - 3)-------------------- = 1/6(x-1)(x-2)(x-3)(x-4) 3------------ = 1/6(x-1)(x-4) 18 = (x-1)(x-4)18 = x^2 - 5x + 4x^2 - 5x - 14 = 0(x - 7 )(x +2 ) = 0x = 7 OR x = -2 Like my answer if you find it useful! |
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| 6. |
26,-, (x-1) =x-334 |
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| 7. |
10,40MATHEMATICS-EXAMPLE5 Along a road lie an odd number of stones placed at intervals of 10 metres. These stones heto be assembled around the middie stone. A person can carry only one stone at a time. A man carried theihwith one of the end stones by carrying them in succession. In carrying all the stones he covered a distanaof 3 km. Find the number of stonesho (u t 1 stones Clearly, one stone lies in the middle and n stones on |
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| 8. |
EXAMPLE 39 Along a road lie an odd number of stones placed at intervals of 10 metres. Thesestones have to be assembled around the middle stone. A person can carry only one stone at a time. Aman carried the job with one of the end stones by carrying them in succession. In carrying all the stoneshe covered a distance of 3 km. Find the number of stones. |
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Answer» Like if you find it useful |
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| 9. |
She atergt two terne of the sequence , are zriIr a, denotes the general term, then write the next five termse) a1 = 2 and α" =a,.. 1 + 4 for n 2.w) (% *), when n is even and a,,--, when n is odd.210Find the value of YC |
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| 10. |
N |Ut | लल्नIW =बच | नि |
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| 11. |
) In figure, seg xyll seg BC, then which of the following statementis true?A.AX AYBX YCAB ACYC XBa)b)AC AYAX AYYC XBc) _ =d) |
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Answer» B option is right By the property of the BPT |
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| 12. |
9f. are zeros of polynomial p() = 5x + 5x+1, then find the value ofWa+p 00'+ |
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| 13. |
Construct the following angles whose measures are(i) 90° (ii) 60° (iii) 30° (iv) 45° |
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| 14. |
The surface area of a cube is 1734 cm2. Its volume1S |
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Answer» Surface area = 6a^2= 1734a^2= 1734/6a= 17 cmvolume= a^3= 17*17*174913cm^3 |
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| 15. |
Two angles whose measures are a & b are suchthat 2a - 3b = 60° then 5b =?, if they form a linearpair(1) 120°(2) 300°(3) 60°(4) of these |
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Answer» 2a - 3b = 60. (given)..............ia + b = 180. (linear pair)..........ii multiplying equation ii by 2 and substracting the equations we get -5b = -120 Multiplying by (-1) 5b = 120°🏆🏆🏆 (1) 120° is the best answer 120 multiple efyhgfxdyjh dogfighting ffyijjcdyijxx cgjkjcv it's answer is 120 this is a right answer |
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| 16. |
The Surface of area of a cube1S 216 Squarecm what s itsvolum2 |
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| 17. |
Using the measures of the anglesgiven in the figure alongside, findthe measures of the remaining threeangles. |
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Answer» 120° is the measure pf remaining three angle utfggdxbju guigrdguuvf5 120 can be right answer 120° is the measure of the angle. 120 degree is remaining three angles angle FOE=40° , angle COP=60°, angle AOB=80° |
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| 18. |
100In figure 3.9, measures of some anglesare given. Using the measures find thevalues of x, y, z5.Fig. 3.9 |
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Answer» y = 180° - 100° = 80° ( linear pair)z = 180° - 140° = 40° ( linear pair)x+y+z = 180° ( sum of angles in ∆)x = 180° - 120°x = 60° tq sir |
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| 19. |
Show that the tangents at the extrêmities of anychord make equal angles with the chord. |
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| 20. |
3627. If the polynomial 6x8 5x + ax b isexactly divisible by the polynomial 25,) 1Sthen find the values of a and b(Foreign 2009) |
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| 21. |
. Find the number of digits in the square root of each of the following numbers (withoutany calculation).1 64(i) 144(ii) 4489(iv) 27225 |
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Answer» 😀 |
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| 22. |
IL LaPPy 2 marks each.Prove that the tangents at the extermities of any chord make equal angles withthe chord. |
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Answer» Let PQ be the chord of a circle with center O. Let AP and AQ be the tangents at points P and Q respectively.Let us assume that both the tangents meet at point Join points O, P. Let OA meets PQ at R.Here we have to prove that ∠APR = ∠AQRConsider, ΔAPR and ΔAQRAP = AQ [Tangents drawn from an internal point to a circle are equal]∠PAR = ∠QARAR = AR [Common side]∴ ΔAPR ≅ ΔAQR [SAS congruence criterion]Hence ∠APR = ∠AQR [CPCT] |
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| 23. |
21. If each edge of a cube is increased by 50%, the percentage increase in its surface area1S(a) 50%(b) 75%(c) 100%(d) 12590 |
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| 24. |
2.3 If n. 2 is a reso of the poly. 2434 mp, thenfind the value of P. |
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Answer» p =22 is the correct answer p=22...............ce p=22 is the correct answer |
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| 25. |
Find the equations of the lines which pass through (4, 5) and make equal angles ithe lines ax-12y + 6-0 and 3x4y + 7 |
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| 26. |
square root of 64 |
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Answer» 8 is the right answer To find:square root of 64 Solution:√64=8Since8×8=64 |
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| 27. |
9. The lerngth and the breadih of a reelallg128 m. Find the area of the park.wo plots of land have the same perirneter. One is a square of side 64 m and the other is arectangle of length 70 a. Find the breadth of the rectangular plot. Which plot has thegreater area and by how much?t Z 35 per square metre is71 400. If the width of |
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Answer» thanks |
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| 28. |
5. Find the equations of the lines which pass through (4, 5) and make equal angles withe lines 5x-12y + 6 = 0 and 3x = 4y + 7ind the equation of the straight line passing through the point (1, 1) and pthe line 4x +4y +7 0arallel |
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| 29. |
find the square root 64 |
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| 30. |
Find the equations of the lines which pass through the point (4,5) and makeequal angles with the lines 5x-12y +6 0 and 3x 4y+ 7? |
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| 31. |
30. A point equidistant from the linesand4x +3y+10 07x +24y-50 0 1s5x -12y 26 0[EAMCET 1994] |
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| 32. |
If 5 parallel straight lines are intersected by4 parallel straight lines, then the number ofparallelograms thus formed isa) 20c) 101b) 60d) 126 |
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| 33. |
5 y - 2 ( y - 5 ) = 19 |
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| 34. |
sqrt(sqrt(sqrt(sqrt(7 %2B 29) %2B 19) %2B 11) %2B 5) |
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Answer» the answer to this question is 3 |
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| 35. |
14*y^2 %2B 19*y - 3 |
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Answer» 14y^2+19y-3=0; 14y^2+21y-2y-3=0; 7y(2y+3)-1(2y+3)=0; (2y+3)(7y-1)=0; 7y=1; y=1/7; 2y+3=0; 2y=-3; y=-3/2 14y*+21y-2y-37y(2y+3) -1(2+3) (7y-1) (2y+3) 7y-1=07y=1y=1/7and2y+3=02y=-3y=-3/2 14y^2+19y-3=14y^2+(21-2)y-3= 14y^2+21y-2y-3=7y(2y+3)-1(2y+3)= (2y+3)(7y-1) |
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| 36. |
1. Iff is a real function defined by f(x) = x² + 7, find :f(t)-f(5)where t + 5 |
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Answer» Given,f(x) = x^2 + 7 f(t) = t^2 + 7f(5) = 5^2 + 7 = 32 Therefore,f(t) - f(5)/t - 5= t^2 + 7 - 32/t - 5= t^2 - 25/t - 5= (t - 5)(t + 5)/t - 5= (t + 5) by definition f'(a)=f(x)-f(a)/x-a therefore we need the value of f'(a) f'(x)=2xf'(a)=2×5=10 |
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| 37. |
x +5=19 |
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Answer» x + 5 = 19 x = 19 - 5 x = 14 |
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| 38. |
Dur(x) is a real function defined by f (x)=x+1, then prove thatx-1f(2x)-3x tl↑ (x) +3 |
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Answer» thx but answer kasa diya knowledge or copy from net |
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| 39. |
(c) 8-5 = 19 |
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Answer» s = 24 is your answer S - 5 = 19S = 19 - 5 S = 24 Therefore S = 24 s=24 is your answer be happy☺😊☺😊 s-5=19s=19+5s=24 perfect answer s=24 is the correct answer s=24 is right answer s=24 is your answer...... s=24 is correct answer.... s - 5 = 19 s = 19 + 5 s = 24is right answer |
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| 40. |
REAL VALUED FUNCTllLet f:((1.1.2.3.(0.-.1.-3)) be a functionfrom z to z defined by fx)artb,for someintegers a,b then (a.b)-D1.2) 2)2-1) 3)3-2) 4(0.3) |
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Answer» 2) you check that when a= 2 , b = -1we get f(x)= 2a-1 which satisfies all relation. |
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| 41. |
Find the domain and range of the real function f defined by |
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Answer» Domain is where 9 - x² > 0 9 > x² √9 > x Therefore, -3 < x < 3 is domain. Range is y = 1/√(9-x²) y² = 1/(9 - x²) 9 - x² = 1/y² √(9 - 1/y²) = x so range is 9 - 1/y² > 0 y² > 1/9 y > √1/9 range is { y belongs R | y > = 1/3} |
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| 42. |
. Find the domain and the range of the real function f defined by f(x) =(√x-1) |
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| 43. |
1 A rectangular yard is 20 rodslonger than it is wide. Its area is 2400 squarerods. Find the dimensions of the yard. |
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Answer» Area=l*bArea=X(X+20)=2400x^2+20x=2400x^2+20x+100=2400+100(x+10)^2=2500x+10=+-50hencex=40so X+20=60hence dimensions40rods,60rods |
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| 44. |
A rectangular garage is 8 yards long and 7 yards wide. It costs $6.64 per square yard to out in a new concrete floor. How much would it cost to put a new concrete floor in the garage? |
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Answer» Area of the garage is l*b as it is a rectangle.A=l*b=8*7=56 sq.yardsNow cost to make a concrete floor=56*6.64=371.84$ |
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| 45. |
77(xi)3 = 2=2m= 62. Check whether the value given in the brackets is a solution to the given queor not:(a) n + 5 = 19 (n = 1) (b) 7n + 5 = 19 (n=-2) (c) in +5 = 19 (n=2)(d) 4p - 3 = 13 (p = 1) (e) 4p - 3 = 13 (p = -4) (1) 4p - 3 = 13 (p = 0)ution by trial and error method: |
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Answer» only c is the correct solution to the given equation |
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| 46. |
n + 5 = 19 ( n = 1 ) |
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Answer» n+5 = 19 => n = 19-5 = 14 but when n = 1 then L.H.S ≠ R.H.S |
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| 47. |
卜しFind aiso the valuss f a and bフ71 |
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Answer» Galti hy oh sry... division me galti ho gyi thi Haa Ek bar bhir say baana kar bhej do Tum mujhe a or b ka maan baata do |
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| 48. |
3*n %2B 19*n=54 |
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Answer» 19n + 3n = 54 22n = 54 n = 54/22 = 27/11 the correct answer of the given question is |
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| 49. |
(a) n +5 19 (n 1) |
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Answer» n + 5 = put n = 1, So, n + 1 = 6 , not satisfied |
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| 50. |
Distance between tivo placis A and 8is 350 Km. Tuwo cays start simultaneousfrom-ft, and, Bㅡ towards __ each-cthet --dand the distance betuween them adteCay is B kmlh less than the Speedof cther car, find the seed of eachCar |
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Answer» where is the answere not found answere |
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