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Find the domain and range of the real function f defined by |
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Answer» Domain is where 9 - x² > 0 9 > x² √9 > x Therefore, -3 < x < 3 is domain. Range is y = 1/√(9-x²) y² = 1/(9 - x²) 9 - x² = 1/y² √(9 - 1/y²) = x so range is 9 - 1/y² > 0 y² > 1/9 y > √1/9 range is { y belongs R | y > = 1/3} |
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