This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
19.x3-8),3-36xy-216虱丽而喊ボx=2y + 6. |
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| 2. |
(०5 (५9०१-७9) - Sim(So+e) |
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Answer» cos(40 - A) = sin[ 90 - (40 - A)] = sin(50 + A) cos(40 - A) - sin (50 +A)= sin(50 + A) - sin (50 + A) = 0 PLEASE HIT THE LIKE BUTTON |
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| 3. |
-43Divide the sum ofandby the product of 1 and3IVI |
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Answer» Sum of 2/7 and 3/11=22+21/77=43/77product of 1/7and -43/2=-43/14divide 43/77÷(-43/14)=43/77*14/(-43)=-2/11 |
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| 4. |
(iii)Name two regions rich in natural gas resources |
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Answer» The regions whicharerichinreserves of Natural Gas Resourcesare: (a) Russia, U.K.andNorway in Europe. (b) Jaisalmer, Krishna-Godavari basinandDigboiRegionin India. |
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| 5. |
Mr. A sells a bicylce to Mr. B at a profit of 20% and Mr. B sells it to Mr. C at a profit25%. If Mr. C pays1500, what did Mr. A pay tor it? |
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Answer» suppose CP for A=x so CP for B=1.2x so CP for C=(1.25)(1.2)x so (1.25)(1.2)x=1500 so x=1000 A pays 1000 for it. thanks |
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| 6. |
8" Mr. A sells a bicylce to Mr. B at a profit of 20% and Mr. B sells it to Mr. C at a profit of25%. If Mr. C pays? 1500, what did Mr. A pay for it? |
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Answer» The CP is 125 for C, when CP for B is 100.So, CP is 1500 for C, when CP for B = 100*1500/125 = Rs 1200 SimilarlyThe CP is 120 for B, when CP for A is 100.So, CP is 1200 for B, when CP for A = 100*1200/12 = Rs 1000 Therefore CP for A = Rs 1000. Galat hai |
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| 7. |
4.6 Mathematical inductionany ways a committee of six persons from 10 persons can be chosen along with a chaitw mrerson and a secretary? |
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Answer» So from 10 persons, one is chair person and the other is a secretary, and they both have to be included in the committee. Thus now we have to select remaining 4 members from the other 8 persons. therefore, 8C4 => |
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| 8. |
(9) Mrs Sharma's income is 20% less than Mr Khan'sincome. By what per cent is Mr Khan's incomemore than Mrs Sharma's income?0)) Mr Pun's income is 20% more than Mr Kumar'sincome. By what per cent is Mr Kumar's incomeless than Mr Puri's income? |
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Answer» sorry your answer is wrong |
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| 9. |
9) Mrs Sharma's income is 20% less than Mr Khan'sincome. By what per cent is Mr Khan's incomemore than Mrs Sharma's income?10) Mr Puri's income is 20% more than Mr Kumarincome. By what per cent is Mr Kumar's incomeless than Mr Puri's income? |
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| 10. |
Simplify: (64) 6 x(216) 3 x(81)4(512)3x(16)#Ń (9)?2. |
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| 11. |
8. How IS Chket deren9. How have advances in technology affected the game of cricketed with changing times and |
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Answer» Technology has used affected sports of the sports includes cricket cricket is now the most popular sports in our country it is very much affected by technology as the newly introduced the DRS system is helping players to challenge the decision of the umpire as even the umpire sometimes make wrong decision the task of the umpire has also been very easy due to the introduction of new systems likes sneco or hotspot Like my answer if you find it useful! |
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| 12. |
(64)6x(216)-x(81)4Simplify:-1-1-(512)3x(16#x (97 |
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Answer» (2)^6×-1/6×(6)^3×-1/3×(3)^4×1/4]/ [(8)^3×-1/3×(2)^4×1/4×(3)^2×-1/2] =[1/2×1/6×3] / [1/4×2×1/3]=[1/4]/[1/12]=12/4=3Please like the solution 👍 ✔️ This is the answer |
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| 13. |
z.Find the value of:m (512)40(10.83(216) 327x167(v) (16)m-3252Ivi 27 3 XA1a(viii)642 (642 +1)36-362367-1 13(x) 4x812 (812 + 812) |
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| 14. |
\frac{(64)^{\frac{-1}{6}} \times(216)^{\frac{-1}{3}} \times(81)^{\frac{1}{4}}}{(512)^{\frac{-1}{3}} \times(16)^{\frac{1}{4}} \times(9)^{\frac{-1}{2}}} |
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| 15. |
& Write cube root of 10648.9 Write the formula to calculate compound interest.10cuboid of plasticine of sides 5 cm, 2 cm, 5 cm. How many such cuboids willf roller skates at a shop was Rs 450, The sales tax charged was 5%. Find thehe need to form a cube? |
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Answer» For some cuboids to become a cube, all the dimensions should be equal in such a way that every original dimension is multiplied by an integral value to make it equal to other values. LCM of 5,2,5 is 10. So, we have to make every dimension equal to 10cm. cuboids required = (10*10*10)/(5*2*5)= 2*5*2= 20. Please hit the like button |
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| 16. |
\left. \begin{array} { l } { \operatorname { log } _ { 2 } x + \operatorname { log } _ { 2 } y > 6 , \text { then the } 1 } \\ { 32 \quad ( b ) 64 } \end{array} \right. |
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Answer» log2X + log2Y ≥ 6 => log2(XY)≥6 => XY ≥ 64 |
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| 17. |
19. In a class there 40 boys and their averageage is 16 years. On one day aged, 17 yearsleaving the class and another joining theaverage age becomes 15.875 years. The ageof the new boy isA. 12 yearsC. 15 yearsB. 14.5 yearsD. 18 years |
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| 18. |
4) 4If the ฼" term of an AP, la 5-13a than the common ennene. ofthe A.P. is1)-82)-213)-134) 5 |
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| 19. |
"8" - + 8g हु: ©&y |
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| 20. |
, DiscUSS AND WRITETHINK1. If 1cm represents 5m, what would be an area of 6 square cm. represent?2. Rajni says 1 sq.m-100' sq.cm. Do you agree? Explainar |
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Answer» 1 cm ------> 5m6 cm² -------> 25× 6 m² = 150 m² 1cm=5m6cm²=5×6cm²=30cm²=30×30=900m |
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| 21. |
1. Express the following numbers in index form.134(1) Fifth root of 13 (2) Sixth root of 9(4) Cube root of 17 (5) Eighth root of 1 |
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Answer» First option is The right answer Fifth root of 13 is correct answer |
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| 22. |
Find the cube root of ci) 8000 .) 175616nd the Square root of d) 3249 c) 39068 |
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Answer» cube of 8000=8000x8000x8000=512000000000cube of 175616=541616944814 |
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| 23. |
write cube n cube root up-to 15 |
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| 24. |
Page NoPrthe lthe resliinheuinal |
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Answer» Let us assume, the x is the tenth place digit and y is the unit place digit of the two-digit number. Also assume x > y Therefore, the two-digit number is 10x + y and reversed number is 10y + xGiven: x - y = 3 ---------------1 Also given: 10x + y + 10y + x = 14311x + 11y = 143x + y = 13 ---------------2 Adding equation 1 and equation 2 2x = 16x = 8 Therefore, y = x - 3 = 8 - 3 = 5 Therefore, the two-digit number = 10x + y = 10 * 8 + 5 = 85 |
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| 25. |
b) 132651Q.4 Which of the following are perfect cubes?a) 1050b) 2025Q.5 The symbol 'V denotes cube root. Thus, /273Calculate the cube root of the following numbers by the PFactorisation method.a. 642 x 32 |
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Answer» thanks |
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| 26. |
प्रश्नावली 1,1. निम्नलिखित संख्याओं का HCF ज्ञात करने के लिए यूक्लिड विभाजन एल्गोरिथ्म का प्रयोगकौजिए:fii) 1965 और 38220 (iii) 867 और 255 - |
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Answer» 38220 = 196 x 195 + 0 H.C.F = 196 (i) 135 and 225 Since 225 > 135, हमने यह अप्लाई कियाwe apply the division lemma to 225 and 135 to obtain प्राप्त करने के लिए225 = 135 × 1 + 90 क्योंकि हमें ज्ञात है कि 90 ,0 के बराबर नहीं हैSince remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain 135 = 90 × 1 + 45 We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain 90 = 2 × 45 + 0 Since the remainder is zero, the process stops. Since the divisor at this stage is 45, Therefore, the HCF of 135 and 225 is 45. |
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| 27. |
1. Find the area of the triangle whose vertices arefii) |
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| 28. |
Juinall!2. Renu took 2 hours to paint a table and 1 hours to paint a chair. How much time did she take inal21 La of onions 3 kg of tomatoes and 11 kenneas Whatiul |
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Answer» Total time = 11/4+4/3 hours 2(3/4) + 1(1/3) = 11/4 + 4/3 = 11(3) + 4(4)/12 = 33 + 16/12 = 49/ 12 hours |
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| 29. |
Linear Equatlions in One Variablehe digits of a two-digit number is9. When we interchange the digits,it is found that the resulting new number is greater thaninal number by 27. What isthe two-digit number?8.17 |
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Answer» Let’s say x is the unit digit and y is the tenth digit. y+x = 9 -> y=9-x 10x+y = 10y+x+27 10x+9-x = 10(9-x)+x+27 10x+9-x = 90–10x+x+27 18x = 108 x = 6 so y = 3 let’s check 63 - 39 =27 27 = 27 (correct) sorry your is not right |
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| 30. |
Example 7 The marks obtained by a student of Class XI in first and second termexamination are 62 and 48, respectively. Find the minimum marks he should get in theannual examination to have an average of at least 60 marks.inal |
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| 31. |
0.1. HAC : 'lv तै _| H Prioye Hhov AACF |
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| 32. |
(lv) 8 g in kilograms |
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Answer» 1g = 0.001kg=> 8g = 0.008kg 8/1000 kilograms hoga kyoki 1kilogram =1000gram to 8gramKa 8/1000kilogram divide krne pr 0.008 |
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| 33. |
1.6ii) 1253(iii)164(iv)lV112(iv)1141 |
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| 34. |
1. Evaluate:(i) 10P(ii) P(iv) Po62(ii) P3lV |
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| 35. |
Two complementary angles differ by 20°. Find the measure of each angle. |
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| 36. |
ig)( i LV"’/MIW हा b का हि.g 1SS eA हा पूरा ही Ti जि हा (4. ! ( |
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| 37. |
two complementary angles are such that one angle is more than 30 |
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| 38. |
A.P.Theorem. If'W and âd, be the first term and corn mion difference of an, then prove that the sum of first n terms of this A.P. is given by |
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| 39. |
Example 2.6Find the perimeter and area of the shaded portio |
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Answer» kindly provide figure also |
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| 40. |
15. The volume of a sphere is 100cm. Determine its diameter? |
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Answer» v=4/3πr³d=2rd=(6×v/π)⅓ thereforediameter=(6×100/π)⅓=5.7(approx) |
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| 41. |
The difference in the measures of two complementaryof the angelsm the measures of two complementary engels is 13.50. Find the measures |
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Answer» we know that sum of complementary angles = 90 let one angle which is greater = x other angle = 90 - xA/Q x - (90-x) = 13.50x - 90 + x = 13.502x = 13.50 +90x = 103.50x = 51.75 hence one angle = x= 51.75other angle = 90 - x = 90 - 51.75 = 38.25 |
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| 42. |
38. Jyoti is 18 years old. Her brother is twice as old as she is. How old is her brother |
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Answer» Twice as old as Jyotihence2*18=36years 18 year double for her brothers 36 |
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| 43. |
| 18. A is four times as old as B. Ten years ago, A was 10 times as old as B. Find the present ageof B. |
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Answer» Let present age of B be X year's. Present age of A = 4 × Present age of B = 4X year's. Before 10 year's age of A = Present age of A - 10 = ( 4X - 10) year's. Before 10 year's age of B = Present age of B - 10 = ( X - 10 ) year's . According to question, Before 10 year's age of A = 10 ( Before 10 year's age of B ). 4X - 10 = 10 ( X - 10) 4X - 10 = 10X - 100 10X - 4X = -10 + 100 6X = 90 X = 90/6 X = 15 year's. Present age of B = X = 15 year's. Let B be x years old. . Now: B = x A = 4x . Ten years ago,: B = x - 10 A = 4x - 10 . Ten years ago, A was 10 times as old as B: 4x - 10 = 10 (x - 10) . Solve x: 4x - 10 = 10 (x - 10) 4x - 10 = 10x - 100 10x - 4x = 100 - 10 6x = 90 x = 15 . Find their present age: B = x = 15 A = 4x = 4(15) = 60 . Answer: B is 15 years old. present age of B = 15 years old Let present age of B be 'x' yrspresent age of A is 4x yrsTen years agoA's age= 4x-10B's age= x-10According to question4x-10=10(x-10)4x-10=10x-10010x-4x=100-106x=90x=90/6x=15therefore age of B=15 years age of the B= 15 yrs is the correct answer of the given question  1 Secondary School Math 5 points A is four times as old as B. Ten years ago, A was 10 time as old as B. find the present age of B Ask for details Follow Report byAyanhusain04.08.2018 Answers  Panzer786 Genius Heya !! Let present age of B be X year's. Present age of A = 4 × Present age of B = 4X year's. Before 10 year's age of A = Present age of A - 10 = ( 4X - 10) year's. Before 10 year's age of B = Present age of B - 10 = ( X - 10 ) year's . According to question, Before 10 year's age of A = 10 ( Before 10 year's age of B ). 4X - 10 = 10 ( X - 10) 4X - 10 = 10X - 100 10X - 4X = -10 + 100 6X = 90 X = 90/6 X = 15 year's. Present age of B = X = 15 year's. present age of B=15 years answer. |
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| 44. |
hemispherical depression is cut out from one face of' a cubical wooden block such. bat the diameter / of the hemisphere is equal to the edge of the cube. Determine theihportiodiameter the hemisphere can have? Find the surtace area of the solduppose the maupies a totalsurface area of the remaining solid |
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| 45. |
what is the HCF of smallest prime number and the smallest and the smallest composite number |
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| 46. |
Write the HCF ofthe smallest prime number and the smallest composite number. |
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Answer» 2 |
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| 47. |
What is the HCF of smallest prime number and the smallest composite number ? |
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Answer» hello friend hcf meaning is highest common fractions the smallest prime number is 2 and the smallest composite number is 4 so the hcf will be 2 |
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| 48. |
s the HCF of the smallest composite number and the smallest prime number |
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Answer» thx |
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| 49. |
What is the HCF of smallest prime number and the smallest composite number? |
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Answer» 4 is composite num and 2 is prime num |
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| 50. |
1.(i) ax + ay - bx - by |
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