14*y^2 %2B 19*y - 3 – InterviewSolution

1.

14y^2 %2B 19y - 3

Answer»

14y^2+19y-3=0; 14y^2+21y-2y-3=0; 7y(2y+3)-1(2y+3)=0; (2y+3)(7y-1)=0; 7y=1; y=1/7; 2y+3=0; 2y=-3; y=-3/2

14y*+21y-2y-37y(2y+3) -1(2+3) (7y-1) (2y+3) 7y-1=07y=1y=1/7and2y+3=02y=-3y=-3/2

14y^2+19y-3=14y^2+(21-2)y-3= 14y^2+21y-2y-3=7y(2y+3)-1(2y+3)= (2y+3)(7y-1)

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