Explore topic-wise InterviewSolutions in Current Affairs.

Let us three consecutive integers be, x, x + 1 and x + 2 respectively.

[• Whenever a number is divided by 3 the remainder obtained is either 0 or 1 or 2. ( it's proved )]

Let x = 3p ........................(i)where p belongs to an integer and does not equal to zero ( 0 ).

=> x is divisible by 3.

If x = 3p + 1 where p belongs to an integer and does not equal to zero ( 0 ).

then x + 2 = 3p + 1 + 2 = 3p + 3 = 3(p + 1)which is divisible by 3.

If x = 3p + 2where p belongs to an integer and does not equal to zero ( 0 ).

then x + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1)which is divisible by 3.

So that x, x + 1 and x + 2 is always divisible by 3.=> x (x + 1) (x + 2) is divisible by 3.

Similarly, whenever a number is divided 2 we will get the remainder is 0 or 1.

Let x = 2qwhere q belongs to an integer and does not equal to zero ( 0 ).

=> x is divisible by 2

If x = 2q + 1 where q belongs to an integer and does not equal to zero ( 0 ).

then x + 1 = 2q + 1 + 1 = 2q + 2 = 2 (q + 1) which is divisible by 2.

So that x, x + 1 and x + 2 is always divisible by 2.⇒ x (x + 1) (x + 2) is divisible by 2.

Since x (x + 1) (x + 2) is divisible by 2 and 3.∴ x (x + 1) (x + 2) is divisible by 6.

Like if you find it useful

thanks but this answer is wrong you try your best for me thank you again answer is 361.43 cm2

ax-3a=-12a(x-3)=-12a=-12/(x-3)

मुझ कुछ समझ में नहीं आया है

Here, 27th March 1995 was Monday. Now for calculating total number of odd days. First, we calculate total number of days till 1 Number 1994∴ Number of days in March 1995 = 27Number of days in February 1995 = 28Number of days in January 1995 = 31Number of days in December 1994 = 31Number of days in November 1994 = 29/146∴ Number of odd days = 146/7 = 20 6/7So, 6 odd days.∴ On November 1, 1994 = Monday - 6= Tuesday

tq

You can like answers, if they are helpful.

thanks you

use a phythagores therom because radius is perpendicular to tangent

If you find this solution helpful, Please give it a 👍

1) total no. 20 No. divisible by 4 are 4,8,12,16,20 Percent of no. divisible by 4 = (5/20)*100 = 25%

2) Let no. Of chocolates be n (65/100)*n = 13 n = (1/5)*100 n = 20

999-999=0 is the best answer

0 is the answer of the following

0 is the right answer.

0 is the correct answer

o is the right answer

999-999=0because, x-x=0meanswhen something is subtracted by same thing, answer will be zero.

thank u

258 * 2 + (-98) * (-258)

= 258 * [2 + (-98*-1)]

= 258 * (2 + 98)

= 258 * 100

= 25800

258 * 2 + (-98) * (-258)= 258 * 2 + 98 * 258 [Since -1 * -1 = 1]= 258 * [ 2 + 98 ]= 258 * 100= 25800

Pr-pq=1PR=1+pqqr=9

by Pythagoras theorem,pq²+qr²=pr²pq²+81=(1+pq)²=1+pq²+2pq80=2pqpq=40PR=41sin r+ cos rpq/PR+qr/PR40/41+9/4149/41

thanka

Sir By Which theorem you solve this question

1)5.2385 - 2.8031=2.4354,; 2)1.6512+1 7351-2.4376=0.9587; ; 3)0.7308+1 .6721=2.4029

Here we are given nCr-1 = nC3rThe formula relating combinations isnCr = nCn-r Using this formula in the given statement we can write nC(r-1) as nCn-(r-1)

So substituting we getnCn-(r-1) = nC3r nCn-r+1 = nC3r

Comparing we get n - r + 1 = 3r n + 1 = 4r r = (n + 1)/4

25/6+67/12117/12 answer

117/12 is the right answer

25/6+67/12117/12 answer

25/6+67/12(50+67)/12117/129.7

4(1/6) + 5(7/12)= = 25/6 + 67/12 = =2(25)+67/12= =50+ 67/12= =117/12

4&1/6 + 5&7/12=(4+5)(1/6 + 7/12)LCM of 6 & 12 is 12.= 9 (1×2/6×2 + 7/12)= 9 (2/12/7/12)= 9 (2+7/12)= 9 (9/12)= 9&9/12your answer is 9&9/12

117/12 is right answer.

9.7 is a correct answer

9.7 is the right answerbCoZexample, 25/6+67/12(50+67)/12117/129.7

117/12 is the correct answer