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In the given APQR, right-angled at ocm and PR-PI cm. Determine th ORsin R cos R.cm. Determine the val |
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Answer» Pr-pq=1PR=1+pqqr=9 by Pythagoras theorem,pq²+qr²=pr²pq²+81=(1+pq)²=1+pq²+2pq80=2pqpq=40PR=41sin r+ cos rpq/PR+qr/PR40/41+9/4149/41 |
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