81279 + Interview Questions in Mathematics QA in Mathematics

1.	66m13. A circular flower bed is surrounded by a path 4 m wide. Thewide. The diameter of the flowerbed is 66 m. What is the area of this path? (11 = 3.14)A circular flower garden has an area of 314 m. A sprinkler at the centre of the14.garden can cover an area that has a radius of 12 m. Will the sprinkler water the entiregarden? (Take it = 3.14)15. Find the circumference of the inner and the outer circles, shown in the adjoining figure?(Take it = 3.14)10 mT9m10. How many times a wheel of radius 28 cm must rotate to go 352 m2 (Take T
Answer»

Discussion

2.	The radius of a wheel is 21 cm. Ho11.88 m?äşw many times will this wheel rotate to cover a distance of
Answer»

Discussion

3.	how many times a whell of radius 28cm must rotate to go 352m
Answer» Path covered in one revolution is 2πr=222/728=2224=176cmHence for 352m=35200cmno of rotations is 35200/176=200rotations.

Discussion

4.	how many times a wheel of radius 28cm must rotate to go 352m?
Answer» Radius of the wheel = 28 cmDistance covered by the wheel in one rotation = 2πr= 2 × 22/7 × 28= 176 cmDistance to be covered = 352 m = 35200 cm Number of rotations of the wheel to cover 35200 cm = 35200/176 = 200

4.

how many times a wheel of radius 28cm must rotate to go 352m?

Answer»

Radius of the wheel = 28 cmDistance covered by the wheel in one rotation = 2πr= 2 × 22/7 × 28= 176 cmDistance to be covered = 352 m = 35200 cm

Number of rotations of the wheel to cover 35200 cm = 35200/176 = 200

Discussion

5.	Marbles of diameter 1.4cm are dropped into a cylindrical beaker ofradius 7 cm containing some water. How many marbles must bedropped so that water in the beaker rises by 28 cm?
Answer»

Discussion

6.	How many times will a wheel of radius 14cm have to rotate to cover a distance of.
Answer» The distance that a wheel travels in one rotation is simply the circumference of the circle. Circumference of wheel= 2* pi* radius. 2* (22/7)*14= 88 cm So wheel can travel 88 cm in 1 rotation. And it has to cover 22 metres (2200 cm) So 2200/88=25 So wheel rotates 25 times to travel 22 meters. Like my answer if you find it useful!

6.

How many times will a wheel of radius 14cm have to rotate to cover a distance of.

Answer»

The distance that a wheel travels in one rotation is simply the circumference of the circle.

Circumference of wheel= 2* pi* radius.

2* (22/7)*14= 88 cm

So wheel can travel 88 cm in 1 rotation.

And it has to cover 22 metres (2200 cm)

So 2200/88=25

So wheel rotates 25 times to travel 22 meters.

Like my answer if you find it useful!

Discussion

7.	. In Fig. 10.13, XY and X'Y' are two parallel tangents to a circle with centreanother tangent AB with point of contact C intersecting XY at A and X'Y'al B.that < AOB = 90°.
Answer» where is fig.10.13😂😂😂😂😂

Discussion

8.	Fig. 10.12Fig. 10.13In Fig. 10.13, XY and X'Y' are two parallel tangents to a circle with centreanother tangent AB with point of contact C intersecting XY at A and X'Y' at Bthat AOB = 90°
Answer»

Discussion

9.	F1g. 10.13n Fig. 10.13, XY and X'Y' are two parallel tangents to a circle with centre 0 adanother tangent AB with point of contact C intersecting XY at A and XY' at B. Pruethat AOB = 900.
Answer»

Discussion

10.	AO B0 1OC OD 2In the fig., Find AB when CD :-12cm.-
Answer» In ΔAOB and ΔCOD, ∠ AOB = ∠COD (Vertically opposite angles) AO/OC = DO/OB (Given) Therefore according to SAS similarity criterion, ΔAOB ~ ΔCOD AO/OC = BO/OD = AB/DC [corresponding sides of similar triangles are proportional] ⇒ 1/2 = AB/12 ⇒ AB = 12/2 = 6 cm Like my answer if you find it useful!

10.

AO B0 1OC OD 2In the fig., Find AB when CD :-12cm.-

Answer»

In ΔAOB and ΔCOD,

∠ AOB = ∠COD (Vertically opposite angles)

AO/OC = DO/OB (Given)

Therefore according to SAS similarity criterion,

ΔAOB ~ ΔCOD

AO/OC = BO/OD = AB/DC [corresponding sides of similar triangles are proportional]

⇒ 1/2 = AB/12

⇒ AB = 12/2 = 6 cm

Like my answer if you find it useful!

Discussion

11.	चक्रवृद्धि ब्याज पर धन की एक निश्चित राशि 2 वर्ष में रुपए 7396 की रुपए7950.70 हो जाती है। ब्याज की दर ज्ञात कीजिए
Answer»

Discussion

12.	Find the root of7396
Answer» 86 is right answer for your question 86 is right answer for this question 86 is the correct answer of the given question

12.

Find the root of7396

Answer»

86 is right answer for your question

86 is right answer for this question

86 is the correct answer of the given question

Discussion

13.	a 6 kg to 10 kg
Answer»

Discussion

14.	1. The square root of 7396 a(d) of these
Answer» Answer:8.6Explanation

Discussion

15.	A certain amount of money on compound interest is rupees 7396 in 2 years rupees 7950.70. Find the rate of interest
Answer»

Discussion

16.	Prove that the diameter of a circle perpendicular to one of the twoparallel chords of a circle is perpendicular to the other and bisects it.
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Discussion

17.	96 a b c ( 3 a - 12 ) ( 5 b - 30 ) \div 144 ( a - 4 ) ( b - 6 )
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Discussion

18.	The first and last term of ar A.P. area and i respectively. If S is the sum of all the terms ofthen k =the A.P. and the common difference is given byk - (1 + a)(a) S(b) 25(3 35(d) none of these
Answer»

Discussion

19.	EXERCISE 7.2In an isosceles triangle ABC, with AB = AC, the bisectors orz B and 2 C intersecteach other at O. Join A to O. Show that:(i) OB = OC(İİ) AO bisects<A
Answer»

Discussion

20.	10. Prove that the diameter of a circle perpendicular to one of the twoparallel chords of a circle is perpendicular to the other and bisects it.
Answer»

Discussion

21.	the arcThe radii of two cylinders are in ratio 3 : 4 and their height is 10 cmsurface areaeir height is 10 cm each. Find ratio of theit cunel16. The radii of
Answer» If you find this solution helpful, Please give it a 👍

Discussion

22.	A rectangular piece of paper having length 28 cm and breadth 20 cm is rolled along with the lengthform a cylinder. Find the curved surface area of the cylinder thus formed.6.
Answer» length =28cm it will be circumferencebreadth =20cm so it will be the height.circumference=2πrhence28=222/7r28*7/44=rr=49/11CSA=2πrh=560cm^2

Discussion

23.	(a) 4 cmABCD is a trapezium such that BC \|\| AD and AB 4 cm. If the diagonals AC and BLintersect at O such that-=-=-, then BC =AO DO 1OC OB 2
Answer»

Discussion

24.	6. In fig.,=12and AB = 5 cm then theBOOC ODvalue of DC is :5 cmB
Answer» the answer is 10 cm...... 10 cm is right answer 10cm................ 10 cm Bhai yeh property hi h bhai as per Tales∆AOB ~∆DOCAO/OC= AB/DC1/2= 5/DCDC= 10 cm

24.

6. In fig.,=12and AB = 5 cm then theBOOC ODvalue of DC is :5 cmB

Answer»

the answer is 10 cm......

10 cm is right answer

10cm................

10 cm Bhai yeh property hi h bhai

as per Tales∆AOB ~∆DOCAO/OC= AB/DC1/2= 5/DCDC= 10 cm

Discussion

25.	tind inveje
Answer» f(x) = 5^(lnx) taking natural log at both sides. ln(f(x)) = (lnx)*ln5 so, lnx = ln(f(x))/ln5or lnx = ln₅(f(x)) so, x = e^(ln₅(f(x))) f-¹(x) = e^ln₅(x)

25.

tind inveje

Answer»

f(x) = 5^(lnx)

taking natural log at both sides.

ln(f(x)) = (lnx)*ln5 so, lnx = ln(f(x))/ln5or lnx = ln₅(f(x))

so, x = e^(ln₅(f(x)))

f-¹(x) = e^ln₅(x)

Discussion

26.	The weight of 30 boxes is 6 kg. What is the weight of 1080 such boxes ?
Answer» 30 boxes are of 6 kg so 1080 boxes are of 1080×6/30 = 216 kg

Discussion

27.	20.26QR-9cm and PR-PQİcrn. Determine the valse ofgiven ΔΡ0R, right-anRAPOR, right-angled atsin R cos R.27
Answer» Pr-pq=1PR=1+pqqr=9 by Pythagoras theorem,pq²+qr²=pr²pq²+81=(1+pq)²=1+pq²+2pq80=2pqpq=40PR=41sin r+ cos rpq/PR+qr/PR40/41+9/4149/41

27.

20.26QR-9cm and PR-PQİcrn. Determine the valse ofgiven ΔΡ0R, right-anRAPOR, right-angled atsin R cos R.27

Answer»

Pr-pq=1PR=1+pqqr=9

by Pythagoras theorem,pq²+qr²=pr²pq²+81=(1+pq)²=1+pq²+2pq80=2pqpq=40PR=41sin r+ cos rpq/PR+qr/PR40/41+9/4149/41

Discussion

28.	, 1000 apples are stored in 25 boxes. How many apples are contained in 92 suchboxes?eat9 35
Answer» 1000 apples in 25 boxesso, in 1 box 1000/25 apples = 40 applesSo, in 92 boxes there are 92×40 = 3680 apples

Discussion

29.	Hhen tind Tn tesum
Answer» what is T4 terms?

Discussion

30.	Tind ans andalienalLS
Answer»

Discussion

31.	tind the root of1896 ?V 7396
Answer» 86 is right answer for this

Discussion

32.	96abc(3a - 12) (5b -30)+ 144(a 4) (b-6)
Answer»

Discussion

33.	96abc(3a-12)(5b-30) ÷144(a-4)(b-6)
Answer» 96abc(3a-12)(5b-30)÷(144(a-4)(b-6)) = 16×6abc×3(a-4)×5(b-6)÷16×9(a-4)(b-6) = 2abc×5 = 10abc If you find this answer helpful then like it. thanku but can u suggest me an easy way?

33.

96abc(3a-12)(5b-30) ÷144(a-4)(b-6)

Answer»

96abc(3a-12)(5b-30)÷(144(a-4)(b-6)) = 16×6abc×3(a-4)×5(b-6)÷16×9(a-4)(b-6) = 2abc×5 = 10abc

If you find this answer helpful then like it.

thanku but can u suggest me an easy way?

Discussion

34.	2) Determine the sum of first 35 terms of an AP if its secondterm is 2 and seventh term is 22.
Answer» we have given that the second term of AP = 2 and seventh term =22we have to findthe sum of first 30 terms of an A.P.=?solution:-using formula:An = a+(n-1) d here ;given thata2 = 2 => a+d = 2 ....................(1)&a7= 22 => a+6d = 22....................(2) solving (1)&(2) we get(2-d) +6d = 22=> 5d = 22-2= 20=> d= 4now put the value of d in (1) we geta+4= 2=> a= -2 now ,using formula:Sn = n/2{2a +(n-1) d} the sum of first 30 terms of an A.P.=here n= 30 =30/2 {2×(-2) +(30-1)×4}= 15 {-4 +120 - 4}= 15 × 112= 1680 hence ;the sum of first 30 terms of an A.P.=1680 answer

34.

2) Determine the sum of first 35 terms of an AP if its secondterm is 2 and seventh term is 22.

Answer»

we have given that the second term of AP = 2 and seventh term =22we have to findthe sum of first 30 terms of an A.P.=?solution:-using formula:An = a+(n-1) d

here ;given thata2 = 2 => a+d = 2 ....................(1)&a7= 22 => a+6d = 22....................(2)

solving (1)&(2) we get(2-d) +6d = 22=> 5d = 22-2= 20=> d= 4now put the value of d in (1) we geta+4= 2=> a= -2

now ,using formula:Sn = n/2{2a +(n-1) d}

the sum of first 30 terms of an A.P.=here n= 30

=30/2 {2×(-2) +(30-1)×4}= 15 {-4 +120 - 4}= 15 × 112= 1680

hence ;the sum of first 30 terms of an A.P.=1680 answer

Discussion

35.	96abc(3a 12) (5b-30)144(a -4) (b -6)
Answer» 96abc(3a-12)(5b-30)/144(a-4)(b-6)=96abc3(a-4)5(b-6)/144(a-4)(b-6)=9635abc/144=1440abc/144=10abc

Discussion

36.	sector if the region between an arc and two radii
Answer»

Discussion

37.	9xy0z 2A)3a - 12) (5b-30)+ 144Ca - 4) (b- 6)
Answer» 96abc (3a-12)(5b-30)÷144 (a-4)(b-6)=96abc×3×5 (a-4)(b-6)÷144 (a-4)(b-6)=1440abc (a-4)(b-6)÷144 (a-4)(b-6)=10abc

Discussion

38.	1. 24 chocolates cost 840. Find the cost of 36 such chocolates.
Answer» 24 chocolates cost rupees 840hence cost of one chocolate =840/24=35rupeeshence cost of 36 =36*35=1260rupees

Discussion

39.	(d) 8 cm17. ABCD is a trapezium such that BC II AD and AB4 cm. If the diagonals AC and BDAO DO 1OC OB 2intersect at O such that--=-=-, then BC =
Answer»

Discussion

40.	96abc (3a-12) (5b-30) ÷144 (a-4) (b-6) ans......…......
Answer» ggdrtyyuffgtttyyytdddd 96abc(3a-12)(5b-30)÷144(a-4)(b-6)= 9635abc(a-4)(b-5)/144(a-4)(b-6)= 835abc(b-5)/12(b-6)= 10abc(b-5)/(b-6)

40.

96abc (3a-12) (5b-30) ÷144 (a-4) (b-6) ans......…......

Answer»

ggdrtyyuffgtttyyytdddd

96abc*(3a-12)*(5b-30)÷144(a-4)(b-6)= 96*3*5abc(a-4)(b-5)/144(a-4)(b-6)= 8*3*5abc(b-5)/12(b-6)= 10abc(b-5)/(b-6)

Discussion

41.	In the figure, O is the centre of the circle, OC= 5 cm and A B=B C=2 \sqrt{5} \mathrm{cm}Find the length of AC
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Discussion

42.	Q. 7. In the figure given below, PTX is atangent and PAB is a secant to the circle. If PT-6 cm, AB = 5 cm and PA = x cm, and PA =oc cm,then the value of x is:
Answer» Please post the figure of the question

Discussion

43.	A box of chocolates cost Rs. 89.75. What is the cost of 8 such boxes?
Answer» the answer is 71 8.00 Cost of 1 box=₹ 89.75Cost of 8 boxes= ₹ 89.75 * 8 = ₹ 718Ans.-Cost of 8 chocolate boxes is ₹718 Cost of 1 box=₹ 89.75so Cost of 8 boxes= ₹ 89.75 * 8 = ₹ 718

43.

A box of chocolates cost Rs. 89.75. What is the cost of 8 such boxes?

Answer»

the answer is 71 8.00

Cost of 1 box=₹ 89.75Cost of 8 boxes= ₹ 89.75 * 8 = ₹ 718Ans.-Cost of 8 chocolate boxes is ₹718

Cost of 1 box=₹ 89.75so Cost of 8 boxes= ₹ 89.75 * 8 = ₹ 718

Discussion

44.	A toy is in the form of a cone of radius 3.5cm mounted on a hheight of the toy is 15.5cm. Find the total surface area of the toy. xof a cone of radius 3.5cm mounted on a hemisphere of same radiusst
Answer» how is l= 12 l is the slant height not height

Discussion

45.	(5) इनमें से कोई नहीं [ए.0.0. 1995]0.2 0.2+ 0.8 >६ 0.8+ 2 > 01622. “व का मान होगा--2 (1) 0.2 (2) 0.8(3) 1.0 (4) शून्य(5) इनमें से कोई नहीं [Asstt. Grade 1995१94]
Answer»

Discussion

46.	12. How much is o greater than -ab + 3a - 4b?
Answer» 3a-4b-c+6-(2a-5b+2c-9) =3a-4b-c+6-2a+5b-2c+9 =a+b-3c+15 3a-4b-c+6-(2a-5b+2c-9)=3a-4b-c+6-2a+5b-2c+9=a+b-3c+15 is the right answer option (2) is the right answer this

46.

12. How much is o greater than -ab + 3a - 4b?

Answer»

3a-4b-c+6-(2a-5b+2c-9)

=3a-4b-c+6-2a+5b-2c+9

=a+b-3c+15

3a-4b-c+6-(2a-5b+2c-9)=3a-4b-c+6-2a+5b-2c+9=a+b-3c+15 is the right answer

option (2) is the right answer this

Discussion

47.	35. How many terms are there in the AP 7,11,15139?
Answer»

Discussion

48.	Find the sum of n terms of the series.3+ 15+ 35+ 63+ ......
Answer»

Discussion

49.	71. The radius of a circle with centre is 6cm. Two radii OA and OB are diawn atright angles to each other. Find the areas of the minor and major segments.
Answer»

Discussion

50.	lhe anea呿triangle is 5 89, unit. Two iverfices ae C2,) and C3,-2). If the Thirdvertex ù ( , y) .Find the valiue呿
Answer» thx

Discussion

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The radius of a wheel is 21 cm. Ho11.88 m?äşw many times will this wheel rotate to cover a distance of

how many times a whell of radius 28cm must rotate to go 352m

how many times a wheel of radius 28cm must rotate to go 352m?

Marbles of diameter 1.4cm are dropped into a cylindrical beaker ofradius 7 cm containing some water. How many marbles must bedropped so that water in the beaker rises by 28 cm?

How many times will a wheel of radius 14cm have to rotate to cover a distance of.

. In Fig. 10.13, XY and X'Y' are two parallel tangents to a circle with centreanother tangent AB with point of contact C intersecting XY at A and X'Y'al B.that &lt; AOB = 90°.

Fig. 10.12Fig. 10.13In Fig. 10.13, XY and X'Y' are two parallel tangents to a circle with centreanother tangent AB with point of contact C intersecting XY at A and X'Y' at Bthat AOB = 90°

F1g. 10.13n Fig. 10.13, XY and X'Y' are two parallel tangents to a circle with centre 0 adanother tangent AB with point of contact C intersecting XY at A and XY' at B. Pruethat AOB = 900.

AO B0 1OC OD 2In the fig., Find AB when CD :-12cm.-

चक्रवृद्धि ब्याज पर धन की एक निश्चित राशि 2 वर्ष में रुपए 7396 की रुपए7950.70 हो जाती है। ब्याज की दर ज्ञात कीजिए

Find the root of7396

a 6 kg to 10 kg

1. The square root of 7396 a(d) of these

A certain amount of money on compound interest is rupees 7396 in 2 years rupees 7950.70. Find the rate of interest

Prove that the diameter of a circle perpendicular to one of the twoparallel chords of a circle is perpendicular to the other and bisects it.

96 a b c ( 3 a - 12 ) ( 5 b - 30 ) \div 144 ( a - 4 ) ( b - 6 )

The first and last term of ar A.P. area and i respectively. If S is the sum of all the terms ofthen k =the A.P. and the common difference is given byk - (1 + a)(a) S(b) 25(3 35(d) none of these

EXERCISE 7.2In an isosceles triangle ABC, with AB = AC, the bisectors orz B and 2 C intersecteach other at O. Join A to O. Show that:(i) OB = OC(İİ) AO bisects&lt;A

10. Prove that the diameter of a circle perpendicular to one of the twoparallel chords of a circle is perpendicular to the other and bisects it.

the arcThe radii of two cylinders are in ratio 3 : 4 and their height is 10 cmsurface areaeir height is 10 cm each. Find ratio of theit cunel16. The radii of

A rectangular piece of paper having length 28 cm and breadth 20 cm is rolled along with the lengthform a cylinder. Find the curved surface area of the cylinder thus formed.6.

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6. In fig.,=12and AB = 5 cm then theBOOC ODvalue of DC is :5 cmB

tind inveje

The weight of 30 boxes is 6 kg. What is the weight of 1080 such boxes ?

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, 1000 apples are stored in 25 boxes. How many apples are contained in 92 suchboxes?eat9 35

Hhen tind Tn tesum

Tind ans andalienalLS

tind the root of1896 ?V 7396

96abc(3a - 12) (5b -30)+ 144(a 4) (b-6)

96abc(3a-12)(5b-30) ÷144(a-4)(b-6)

2) Determine the sum of first 35 terms of an AP if its secondterm is 2 and seventh term is 22.

96abc(3a 12) (5b-30)144(a -4) (b -6)

sector if the region between an arc and two radii

9xy0z 2A)3a - 12) (5b-30)+ 144Ca - 4) (b- 6)

1. 24 chocolates cost 840. Find the cost of 36 such chocolates.

(d) 8 cm17. ABCD is a trapezium such that BC II AD and AB4 cm. If the diagonals AC and BDAO DO 1OC OB 2intersect at O such that--=-=-, then BC =

96abc (3a-12) (5b-30) ÷144 (a-4) (b-6) ans......…......

In the figure, O is the centre of the circle, OC= 5 cm and A B=B C=2 \sqrt{5} \mathrm{cm}Find the length of AC

Q. 7. In the figure given below, PTX is atangent and PAB is a secant to the circle. If PT-6 cm, AB = 5 cm and PA = x cm, and PA =oc cm,then the value of x is:

A box of chocolates cost Rs. 89.75. What is the cost of 8 such boxes?

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