DAY 107-258nc rC3

1.	DAY 107-258nc rC3
Answer» Here we are given nCr-1 = nC3rThe formula relating combinations isnCr = nCn-r Using this formula in the given statement we can write nC(r-1) as nCn-(r-1) So substituting we getnCn-(r-1) = nC3r nCn-r+1 = nC3r Comparing we get n - r + 1 = 3r n + 1 = 4r r = (n + 1)/4

Answer»

Here we are given nCr-1 = nC3rThe formula relating combinations isnCr = nCn-r Using this formula in the given statement we can write nC(r-1) as nCn-(r-1)

So substituting we getnCn-(r-1) = nC3r nCn-r+1 = nC3r

Comparing we get n - r + 1 = 3r n + 1 = 4r r = (n + 1)/4

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DAY 107-258nc rC3

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