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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
a rectangular gardan is surrounded by on its outside 2m broad path. if area of the path is 464 squares metre,then find what is perimeter of garden |
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Answer» PLEASE LIKE IT, IF YOU FIND THE ANSWER HELPFUL. please write in mobile and give |
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| 2. |
86. The area of a sector with radius 28 cm, and thelength of the are 'r 32 cm, is __1 484 cm2 |
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Answer» 448cm^2 is the correct answer |
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| 3. |
A pole 81 m high broke at a point but did notseparate. Its top touched the ground 27 m fromits base. At what height above the ground didthe pole break?9. |
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Answer» Suppose the point from which the pole broke is x meters above the ground. then the length of AC will be (81 - x)m.ABC is right angled triangle by applying Pythagoras theorem. AC2 = AB2 + BC2= (81 - x)2 = x2 + 27 2 = 6561+ x2 - 162x = x2 + 729= 5832 = 162x= x = 36Height from which the pole broke is 36 meters above the ground. |
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| 4. |
9.A pole S1 m high broke at a point but did notseparate. Its top touched the ground 27 m fromits base. At what height above the ground didthe pole break? |
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Answer» Suppose the point from which the pole broke is x meters above the ground. then the length of AC will be (81 - x)m.ABC is right angled triangle by applying Pythagoras theorem. AC2 = AB2 + BC2= (81 - x)2 = x2 + 27 2 = 6561 + x2 - 162x = x2 + 729= 5832 = 162x= x = 36Height from which the pole broke is 36 meters above the ground. |
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| 5. |
. 4. Solve the following questions : (Any Three)() A tree is broken by the wind. The top touched the ground making an eat a distance of 30 m from the foot of the tree. Whatwas the height |
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Answer» given : distance between the foot of the tree and the broken part of the tree that touches the ground = 30 mlet ,the height ofstanding part of the tree be = htheheight of fallen part (forms hypotenuse) be = xthen height of the tree will be = h + xnow,tan 30 = h/30 m 1/√3 = h/30 m 30/√3 = h ⇒ h= 30/√3 m ..... 1similarly,cos30 = 30 m/ x √3/2 = 30/ x√3x = (30)2√3x = 60 m⇒x = 60 /√3 m ......2 (we now have both value of h and x ) on adding equation1 & 2 :⇒h + x = 30 /√3 +60 /√3 =90 /√3 m = 60√3 mso , the total height of the tree is 60√3 m . |
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| 6. |
(1) A tree is broken by the wind. The top touched the ground making an angle of 309 andat a distance of 30 m from the foot of the tree. What was the height of the tree?(3-1.73) |
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| 7. |
(1) A tree is broken by the wind. The top touched the ground making an angle of 30 degree andat a distance of 30 m from the foot of the tree. What was the height of the tree?(3-1.73) |
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| 8. |
length of each of its legs?9. A pole 81 m high broke at a point but did not separate. Its top touched the ground 27 mfrom its base. At what height above the ground did the pole break?6 I TRIANGLE AND ITS PROPERTIES |
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Answer» Let at point C, the pole break down and touches the ground. Let BC = x, So AB = BC = 81-x Given base is 21m. So CD = 21 Now from Pythagoras Theorem BD2= CD2+ BC2 => (81-x)2= 212+ x2 => 6561 + x2- 162x = 729 + x2 => 6561 - 729 = 162x => 5832 = 162x => x = 5832/162 => x =36 So the pole break down at height 36 m from the ground. |
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| 9. |
22. Aplant which was 90 cm high broke at a point in a storm but did not separate.Itstoptouchedthegroundat a distance of 27 cm from its base. Find the height of the point from the ground at which the plantbroke |
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| 10. |
थक. 5 “६ हनन डइन (0)1+sp=2p ॥४४ fuelx dge 280० 86 bl |
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| 11. |
27A book consists of 264 pages. Parul had read3 of the book till yesterday. How many morepages does she have to read? |
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Answer» plz fast No. of pages = 264No. of pages read by Parul = 3/4*264 = 198No. of pages yet to read is 264-198=66Hence Parul has to read 66 more pages fast Total Pages=264Then,3/4*264=198Pages for read now-264-198=66 Ans. |
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| 12. |
26. If FINE is coded as IFFI, TASTE is coded asAETTE, then the code for TEACHER is(1) EHAREER(3) EHEREER(2) EHERERR(4) EHERRER |
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Answer» Teacher can be written as Eherrer thanks |
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| 13. |
4. The perimeter of a square garden is 36 cm. What is its area? |
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Answer» Let the side of the square is a. Perimeter of square =4a=36 a=9Area=a^2 =9×9 =81 cm^2 |
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| 14. |
a rectangular gardan is surrounded on its outside by 2m broad path if area of the path is 464 square metre. then what is the perimeter of the garden. |
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Answer» PLEASE LIKE IT, IF YOU FIND THE ANSWER HELPFUL. |
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| 15. |
a rectangular gardan is surrounded by its outside by 2m broad path. if area of the path is 464 square metre , then what is the perimeter of the garden |
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| 16. |
The annual rate of growth in population of a certain city is 8%. If its present population is 1,96,830what was the population 3 years ago10.st bocome7396 in 2 years and Rs 7950.70 in 3 |
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| 17. |
[2011]22. In a square ABCD, its diagonals AC and BDintersect each other at point O. The bisectorof angle DAO meets BD at point M and thebisector of angle ABD meets AC at N and AMat L. Show that:(i) <ONL + 20ML = 180°(ii) LBAMテ<BMA(iii) ALOB is a cyclic quadrilateral |
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Answer» 1 2 |
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| 18. |
6. Evaluate: |
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| 19. |
6. Evaluate (i)- |
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Answer» If you like the solution, Please give it a 👍 Thanks 😇😇 |
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| 20. |
6 Evaluate: 81x5-42 |
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Answer» 8^-1 * 5³/2^-4 = 5³*2⁴/8 = 5³*2 = 125*2 = 250 Like my answer if you find it useful! |
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| 21. |
dion findsinte-troj"Ń Đ° 3 |
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Answer» So, sinⁿx + cosⁿx = 2 |
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| 22. |
The annual rate of growth in population of a town is 10%. If its present population is 33275,what was it 3 years ago?11. |
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Answer» thank you |
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| 23. |
3.In a library, there are 27 book shelves. If there are 479 books on each bookshelf, find the total number of books in the library. |
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Answer» 12933 books are there in the library 12933 books are there in library |
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| 24. |
2017Test whether the matix d=10 30Lio2in diagonalisable by meansof orthogonal trane formation. |
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Answer» Irish x ccht cc you can find a way to the UK and Ireland destinations only one of the best day of research and development and implementation of state weather the following quadratic equation have own distinct axis. state weather the following quadractic |
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| 25. |
p ( x ) = 3 x + 1 , \quad x = - \frac { 1 } { 3 } |
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| 26. |
Evaluate x \rightarrow 2 \quad x^{2}-5 x+6 |
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| 27. |
quad*x %2B 1/x=8 |
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Answer» x + 1/x = 8..................(1) (x + 1/x)^2 = x^2 + 1/x^2 + 2*x*1/x 8^2 = x^2 + 1/x^2 + 2 x^2 + 1/x^2 = 64 - 2 = 62 Now, (x - 1/x)^2 = x^2 + 1/x^2 - 2 (x - 1/x)^2 = 62 - 2 = 60 x - 1/x = 2root(15)......... (2) Therefore, Value of x^2 - 1/x^2 = (x + 1/x)(x - 1/x)= 8 * 2root(15)= 16 root(15) |
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| 28. |
Find the point of intersection of the line 2 x+4 y=6 \quad 2 \quad x-4 y+3=0 |
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Answer» given 2x+4y=6 and x_4y+3=0 consider them as equations 1 &2 by solving 1&2 x y. 1 4. - 6. 2. 4 -4. 3. 1. -4 X/12-24=y/-6-6=1/-8-4 X=-12/-12=1. y=-12/-12= 1 therefore poi (1,1) |
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| 29. |
"71xx8.(x)=\frac{x}{\sqrt{1-x^{2}}}, \quad x(x)=\frac{x}{\sqrt{1+x^{2}}} |
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| 30. |
\frac { d } { d x } ( \operatorname { sech } ( \operatorname { log } x ) ) , \quad ( x > 0 ) |
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| 31. |
कट हे (XE) oy :l*’ (¥ =3 A 2 e (;) |
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| 32. |
(a) Show that the matrix\left[ \begin{array}{cc}{\cos \theta} & {\sin \theta} \\ {-\sin \theta} & {\cos \theta}\end{array}\right]is orthogonal. |
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Answer» orthogonal means the determinant is 1 or -1hence determinant of this matrix iscos^2thwta+sin^2thwta=1 |
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| 33. |
What is the utility of Neslar Reagent? |
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Answer» Named after Julius Nessler, this pale solution becomes deeper yellow in the presence of ammonia. Nessler's reagent is an aqueous solution of potassium iodide, mercuric chloride, and potassium hydroxide used as a test for the presence of ammonia. |
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| 34. |
xeIntegrate 7703)2 with respect to 'x. |
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Answer» use ilate in this by consider e as 1st function and remaining 2nd |
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| 35. |
1.The value of x, yand z in the givenmatrix is |
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Answer» 1 is the correct answer of the given question 1 is the answer of the following |
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| 36. |
16. Find the cu4cm. (Take n 3.14)rved surface area of the right circular cone whose radius is 3cm and the height is |
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Answer» radius = 3 cm height = 4 cm The formula for finding curved surface area of right circualr cone = pi×r×L Where L = √h²+r² = √4²+3² = √16+9 = √25 = 5 cm So curved surface area = 22/7×5×3 = 330/7 cm² Like my answer if you find it useful! |
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| 37. |
Find the inverse of the matrix given below: |
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| 38. |
( i i ) \quad \left( \frac { - 7 } { 3 } \right) ^ { 11 } \times \left( \frac { - 7 } { 3 } \right) ^ { 13 } |
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| 39. |
\left. \begin{array} { l } { x ^ { 3 } - 2 x ^ { 2 } - x + 2 } \\ { ( 11 ) \quad x ^ { 3 } + 13 x ^ { 2 } + 32 x + 20 } \end{array} \right. |
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Answer» (1) x^3-2x^2-x+2=x^2(x-2)-1(x-2)=(x^2-1)(x-2)=(x+1)(x-1)(x-2) (2) x^3+13x^2+32x+20=x^3+x^2+12x^2+12x+20x+20=x^2(x+1)+12x(x+1)+20(x+1)=(x^2+ 12x+20)(x+1)=(x+1)(x+2)(x+10) |
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| 40. |
o76 का मात्र ज्ञात्त करें।(B) 14n%D) ८०५6Cosec O X tan 0 + cos(A) sine(C) 1/cos?p - |
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Answer» cosecA×tanA÷cosA1/sinA × sinA/cosA × 1/cosA1/cosA × 1/cosA1/ cos²A wrong ans ,👍 |
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| 41. |
6, In how many years will a sum of money double itself at 12% simple interest?i De 120 more than |
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| 42. |
1.For the given orthogonal matrix Q.The inverse is |
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| 43. |
tor plastering4. Into a circular drum of radius 4.2 m and height 3.5 m, how many full bags of wheat can be emptied, if the space required for thewheat in each bag is 2.1 cu. m? (3.14) |
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Answer» thanks bhai |
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| 44. |
Also, find the cost of plastering the Ihner cu veu16. In to a circular drum of radius 4.2m & heiht 3.5m, how many full bags of wheat can be emptiedif the space of wheat can be emptied if the space required for wheat in each bag is 2.1 cubic m |
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| 45. |
PART-A3. (Write True/False)1.156 can be written as a product of prime factors as 22 × 3 × 1OrITuito Tnie/False) 1 |
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Answer» 156=2*2*3*13=2^2*3*13 hence this is true |
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| 46. |
hIClalttmiiniumsheetofareaoSThe shape of a garden is rectangular in the middleThe shape of a garden is rectangular in the midl 14nFind the area and the perimeter of this garden. athe ends8.4 m21 m |
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| 47. |
TILe and the simple eventx de is tassed once.bability that the number that comes upis 9bability that ihe number cones up is less than 9Whai is thethatatandy Wlui is theWlut is the |
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| 48. |
\square , \quad 13 , \square |
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| 49. |
51*(quad*(quad*square)) - 231 %2B 79 - 399 %2B 159 %2B 81 |
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Answer» LHS: - 231 + 79 + 51= - 231 + 130 = - 101 RHS: - 399 + 159 + 81= - 399 + 240= - 159 Therefore,(-231 + 79 + 51) > (-399 + 159 + 81) |
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| 50. |
7. Define negative of a vector. |
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Answer» Two vectors are said to be negative if they have same magnitude, but opposite direction. We know that a vector's sign indicates its direction. ... In short, if the direction of one vector is exactly opposite to the other and their magnitude is equal, then they are known as negative vectors for each other. |
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