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Find the point of intersection of the line 2 x+4 y=6 \quad 2 \quad x-4 y+3=0 |
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Answer» given 2x+4y=6 and x_4y+3=0 consider them as equations 1 &2 by solving 1&2 x y. 1 4. - 6. 2. 4 -4. 3. 1. -4 X/12-24=y/-6-6=1/-8-4 X=-12/-12=1. y=-12/-12= 1 therefore poi (1,1) |
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