1.

quad*x %2B 1/x=8

Answer»

x + 1/x = 8..................(1)

(x + 1/x)^2 = x^2 + 1/x^2 + 2*x*1/x

8^2 = x^2 + 1/x^2 + 2

x^2 + 1/x^2 = 64 - 2 = 62

Now,

(x - 1/x)^2 = x^2 + 1/x^2 - 2

(x - 1/x)^2 = 62 - 2 = 60

x - 1/x = 2root(15)......... (2)

Therefore, Value of x^2 - 1/x^2 = (x + 1/x)(x - 1/x)= 8 * 2root(15)= 16 root(15)


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