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9.A pole S1 m high broke at a point but did notseparate. Its top touched the ground 27 m fromits base. At what height above the ground didthe pole break?

Answer»

Suppose the point from which the pole broke is x meters above the ground. then the length of AC will be (81 - x)m.ABC is right angled triangle by applying Pythagoras theorem.

AC2 = AB2 + BC2= (81 - x)2 = x2 + 27 2 = 6561 + x2 - 162x = x2 + 729= 5832 = 162x= x = 36Height from which the pole broke is 36 meters above the ground.



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