Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

. Find the angle between two vectors a and b with magnitudes v3 and 2,respectively having \vec{a} \cdot \vec{b}=\sqrt{6}

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2.

25^{1 / 2} \times(625)^{-1 / 4}

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3.

9/ Mr. Sinha sold two tape-recorders for990each; gaining 10% on one and losing 10% onthe other. Find his total loss or gain, aspercent, on the whole transaction

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4.

\begin { equation } \frac{2^{-5} \times 10^{-5} \times 625}{5^{-2} \times 6^{-3}} \end { equation }

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you have to simplify

5.

Simplify \left(\frac{64}{125}\right)^{-\frac{2}{3}} \div \frac{1}{\left(\frac{256}{625}\right)^{\frac{1}{4}}} \times\left(\frac{\sqrt{25}}{\sqrt[3]{81}}\right)^{0}

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thank u soo much

6.

12 The upper part of a tree breaks due towindstorm and it makes an angle of 60° with theground. The distance from the bottom of the treeto the point where the top touches the ground is10 m. Find the original height of the tree (V3 =1.732)

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7.

Ech in the triangleingles of a quadrilateral in the ratio 8:7:7:6, find the value of each angle and also percentage ofh angle in the quadrilateral.

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8x+7x+7x+6x=36028x=360X=90/7°

8x+7x+7x+6x=36028x=360x=360/28x=90/7

8.

041 Find the value of:7+65)

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= 3please like the solution 👍 ✔️

√(3+√(27+√(73+8))√(3+√27+9√(3+6= 3

9.

find the value of m if the HCFof 65 and 117

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According to Euclid’s division algorithm,b = a × q + r, 0 ≤ r < a [using, dividend = divisor × quotient + remainder]⇒117 = 65 × 1 + 52⇒65 = 52 × 1 + 13⇒52 = 13 × 4 + 0∴HCF (65, 117) = 13 (i)Also given that, HCF (65, 117) = 65 m – 117⇒65 m – 117 = 13 [from (i)]⇒65 m = 130⇒m = 2

answer of this question is m =2

m=2 is the right answer of following questions

m=2 is the answer of following question

10.

2. Three angles of a quadrilateral are 60° 110° and 86°. The fourth angle of the quadrilateralIS

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360°-(60°+110°+86°)360°-256°104°

hence the fourth angle of quadrilateral is 104°

11.

in a quadrilateral ABCD,AO and OB are bisector of angle A and angle B respectively.prove that angle AOB =1/2 (angle C+angle D)?

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figure is wrong

12.

I three angle of quadrilateral are 75 9. 90quadrilateral?and 110. Find the fourth and

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In quarilateralsum of all angles are 360°so75+110+90+x= 360x= 360-275= 85°

If you don't know the answer of this question then please you contact a student of class 6.... You are not going to pass 12 class....

13.

In a spinning wheel. there are3 white and 5 green sectors.it is spinned: what is theProbability of getting agreen Sector?

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what are the sensors

14.

L A uee breaks due to stomm and the broken part bends so thar the top of the ireeteuches the ground making an angle 30 with it. The distance between the foot of thetree to the poiet where the top touches the ground is S m. Find the height of the tree

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15.

6、26% ofa number is 65-Find the number.

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16.

6²x 6 = 65 find value of m'

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17.

\left(\frac{6 t}{125}\right)^{-2 / 9} \div \frac{1}{(256 / 625)^{1 / 4}}+\left(\frac{(\sqrt{25})}{\sqrt[3]{64}}\right)^{0}=

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9/4 is the answerx^0= 1

18.

In a AABC, the internal bisectors of 4B and ZC meet at P and the external bisectors of Band 2C meet at Q, prove that LBPC + &lt;BQC = 180°.tor of an isosceles triangle is

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19.

OAThe sum of a number and its reciprocal is 65. Find the number.

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20.

OrProve that the quardrilateral formed (if possible) by the internal bisectors of any quadrilateral iscyclic.

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If you like the solution, Please give it a 👍

21.

(ix)The measure of an angle x between the internal bisectors of any two adjacent angles of parallelogram is:(a) 60°(c) 100°(b) 80°(d) 90°

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hence, option (d) is correct.

22.

(2016-TYATHEMD, VSLMICE4BC of the figure, BD and CD are internal bisectors of 4B and LC reapectively.Prove that 180° +y=2x.

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23.

12. कुछ समीकरण किसी प्रणाली के आधार पर हल किए।गए हैं। उस आधार पर हल न किए गए समीकरण कासही उत्तर ज्ञात कीजिए।6 * 3 = 216, 5 * 4 = 625, 2 * 7 = ?

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2 * 7 = 128

6 * 3 = 216 => 6³ = 2165 * 4 = 625 => 5⁴= 6252 * 7 => 2⁷ = 128

128. =2^7

8 is the right answer

2*7= 128 hoga because 6*3=216 & 5*4= 625

2*7 will be solved as per series that means 2*2*2*2*2*2*2=128

128 is the correct answer

128 is correct answer

128 is correct ans

answer is 128

24.

eentWo consecutive angles is 10,hd the uee agres8. Ais a triangle in which 7, the internal bisectors of angles B and CeO. Find the magnitude of 4BOC

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25.

(ii)2CH3-CH-CH3 ary etherCl

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R-X + 2Na +X-R ——-> R - R + 2NaX.

Example:-

2CH3 -CH-CH3 -Cl + 2Na —-> CH3-CH2-CH2--CH3 +2 NaCl.

26.

In the adjoining figure, it is given that 4CE/BA and &lt;ECD = 65°. Find ZACB3.60°65°

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angle B = 65° ( corresponding angle)In ∆ABCA+B+C = 180°60+65 + C = 180C = 180 - 65 -60C = 55°

27.

Na(ii) 2CH3-CH-CH3 dry etherCl

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R-X + 2Na +X-R ——-> R - R + 2NaX.

Example:-

2CH3 -CH-CH3 -Cl + 2Na —-> CH3-CH2-CH2--CH3 +2 NaCl.

28.

7. The sum of a natural number and its reciprocal is 65.. Find them658

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Let number is x x+1/x=65/8

x²+1=65x/8

8x²+8=65x

8x²-65x+8=0

8x²-64x-x+8=0

8x(x-8)-1(x-8)=0

(x-8)(8x-1)=0

x=8,1/8

So number is 8

29.

2. Find the HCF of 65 and 117 and expressit as a linear combination of 65 and 117.

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Euclid's Division Lemma :-a = bq +r

117 > 65

117 = 65 × 1 + 52 ----> [ 2 ]

65 = 52 x 1 + 13 -----> [1]

52 = 13 x 4 + 0

HCF = 13

13 = 65m + 117n

From [ 1] ,13 = 65 - 52 x 1

From [2] ,52 = 117 - 65 x 1 ----> [3] ,

13 = 65 - [ 117 - 65 x 1 ] ------> from [3]

= 65 x 2 - 117

= 65 x 2 + 117 x [-1 ]

m = 2n = -1

30.

He take to make 15 rounds?weighs 35 kg. His sister Kavita's weightKavita weigh?of Amit's weight. How much doesa's weight isare there in

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31.

In figure, if PQ丄PS, PQ || SR,SQR=28" andQRT-65。then find the values of X andy.28965°

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32.

1.In Fig. 9.40, if AB II CD, EF ll BC, &lt;BAC = 65° and &lt;DHF = 35°, find LAGH.65°359 FFig. 9.40

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33.

Prove that: (sin A + cosec A)2 + (cos A + seua)tanding on the bank of a river observes that the angle of elevationconservation of29. Aperson sAof the top of a building of an organisation working forwild life, standing on theaway from the bank, he finds the angle of elevation to be 30°. Find theopposite bank is 60°. When he moves 40 metresheight of the building and the width of the river.fiwhere ABCD is a square

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34.

9.The angle of elevation of the top of a building from the foot of the tower is 30° and theangle of elevation of the top of the tower from the foot of the building is 60°. If the toweris 50 m high, find the height of the building.9.310. Two poles of equal heights are standing opposite each other on either side of the roadIn twhich is 80 m wide. From a point between them on the road, the angles of elevation dfthe top of the poles are 60° and 30°, respectively. Find the height of the poles and thedistances of the point from the poles.

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35.

he bunuing is 80.If the tower is 50 mhigh.NCERT, CBSE 2012From a point on a bridge across a river the angles of depression of the banks on oppositeside of the river are 30° and 45° respectively. If bridge is at the height of 30 m from thel the BuildingNCERTbanks, find the width of the river.

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36.

A person standing on the bank olarof the top of a building of an organisatiowild life, standing on the opposite bank is 60°. When he moves 40 metresaway from the bank, he finds the angle of elevation to be 30°. Find theheight of the building and the width of the rivern working for conservation of30. Find the area of the shaded design of Fig. 3, where ABCD is a squareof side 10 cm and semicircles are drawn with each side of the square as Ddiameter. (Use π = 3.14)omFig 3

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Like if you find it useful

37.

15. A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same timea tower casts a shadow 28 m long. Find the height of the tower.nC and POR resnectively where

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38.

Solve the following questions: (Any threeObserve the measures of pots infigures. How many jugs of watercan the cylindrical pot hold09i)10 enconical water jugcylindricei water pot

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n* volume of cup = volume of cylindern * 1/3πr^2h= πr^2hn= 3.8~4

39.

Ja18) म (x + 2) स,(च) (x + y') में (x + y) से,

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( x^2 + y^2)=( x+y)^2= ( x^2+ y^2 +2xy);

x⁴ + y⁴ the answer is correct

are u a teacher. and you don't solve this question.y are a pagal teacher.ha ha ha 📂📁📂

40.

de lake to make 15 rounds?11. Amit weighs 35 kg. His sister Kavita's weight isKavita weigh?ght isof Amof Amit's weight. How much doese are there in

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thanks

41.

rom a point Q, the length of the tangent to a circle is 24 cm and the distanhe centre is 25 cm. The radius of the circle iscm(B) 12 cmC)15 cm(D) 24.5 cm

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42.

b) 829 106+244 121

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1300 is the right answer

43.

547527827.5270082(b) 10x= 0.2689贰市ー. I180.0003718689(b) 2.689

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547.527/(0.0082) = 547527*10^4/82×10³ = 5475270/82 = x

so, 547527/82 = x/10

44.

Find the perimeter of a semi-circularshaped disc with a radius of 14 cm

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45.

(-554601 %2B 829^2)/((8.29*80))

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square of 829 is 687241and 669*829 is 554601 and 8.29*80 is 663.2 so, according to question687241-554601/663.2=132640/663.2=200 so, 200 is correct answer

200 is the correct answer

46.

689=r+2

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47.

() 237, 106 94, 689 nd 29.5

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Kindly upload the image having proper details of the query.

48.

nmof the A.P. is zero.e resnectively. Show that

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49.

angle of elelevation of the top of the pedestalthe tower is 30ilding is 60 If the te. The angle f elevation of the top of a building from the foot ofand ranple of elevation of the top of the tower from the foot of the building is 60 1is 50 m high, find the height of the buildingtanding opposite each other on either side of the

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1

2

3

50.

ants to keep 92 pins in 4 boxes so that all the boxesn equal number of pins. How many pins can he keep inox?7

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No. of pins that he can keep in each box=92/4=23