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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Section13 A ladder 25m long reaches a window of a building 20m above the ground. Find the distancebetween foot of the ladder and the building. |
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Answer» Applying Pythagoras theorem...AC^2=AB^2+BC^225^2-20^2=BC^2sqrt(625-400)=BCsqrt(225)=BC15 m=BC |
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| 2. |
(-4)power 5× (5/3) power 5 |
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| 3. |
Find the angle between the lines-'/3y= l and fix-y-4 |
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| 4. |
"(zfi+eX) Јоарелоу) puy.1. I= fix pueZT = fi+ x Jl'h |
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| 5. |
Write 3/2, 4/5, 8/5 in decimalnotation. |
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| 6. |
4 A ladder 17 m longdistance of the foot of the ladder from the building.eaches a window of a building 15 m above the ground. Finda |
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| 7. |
The angles of depression of the top and the bottom of an & m tall building from the top of amulti-storeyed building are 30° and 459, respectively, Find the height of the multi-storeyedbuilding and the distance between the two buildings. |
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| 8. |
6. From the top of a tall building of height 24 m, the angle of depression of the top of anotherbuilding is 45° whose height is 10 m. Find the distance between the two buildings. |
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Answer» thank uhh so much |
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| 9. |
5. The angles of depression of the top and bottom of 8 m tall building from the top of amultistoried building are 30° and 45° respectively. Find the height of the multistoriedINCERT, CBSE 2009]building and the distance between the two buildings. |
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| 10. |
25. The angles of depression of the top and the bottom of a 8 m tall building from the top of a multi-storeyed building are 309 and 45°, respectively. Find the height of the multi-storeyed buildingand the distance between the two buildings. |
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Answer» Angle of depression of top of the8m tall building from the top of thehm multi-story building isθ1=300 and angle of depression of bottom of the8m tall building from the top of thehm multi-story building isθ2=450 Let the difference of their heightx=h−8∴tan30=xdor d=x⋅√3;(1), wheredis the horizontal distance between two buildings. Alsohd=tan45orx+8d=tan45or (x+8)=d;(2)From equation (1) and equation (2) we get x+8=√3⋅xorx(√3−1)=8orx=8√3−1≈10.93m ∴h≈10.93+8=18.93m andd=x+8=18.93m The height of the multi-story building is18.93m and distance between the two buildings is also18.93m [Ans] |
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| 11. |
he angles of depression of the top and the bottom of a 8 m tall building from the top of amulti-storeyed building are 30° and 45° respectively. Find the height of the multi-storeyed building and the distance between the two buildings. |
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| 12. |
Example 6: The angles of depression of the top and the bottom of anfrom the top of a multi-storeyed building are 30° and 45°, respectively. Find the heighofthe multi-storeyed building and the distance between the two buildings.8 m tall buildin |
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| 13. |
10. A ladder 25 m long reaches a window which is 15 m above the ground on one side of a stresWhen the foot of ladder is not moved and the ladder is turned to other side of the street it reada window 20 m high. Find the width of the street.11 A richtuonldtui |
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| 14. |
Convert into power notation.(a) 125Simnlify the following |
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Answer» 5^3=125hence-1/(5)^3=-5^(-3) |
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| 15. |
1)亦sin A-게 sin 24.cos 3A avT tan 3.4市깨孤亦玑1 |
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Answer» right answer |
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| 16. |
(¥6) Hol CQCTL'%F |
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Answer» a square + 2ab + b square |
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| 17. |
1. Write each of the following in power notation5 5 5 5078777 |
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Answer» 625/2401 is the answer of this 5/7^4Is the answer of the question (5/7)^4 is the right answer (5/7)power4 is the right answer (5/7)⁴ is the correct answer of the given question (5/7)^4 is the right answer. |
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| 18. |
write the n-1 derivate of x^n |
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| 19. |
1.The value of χ Ε (0,90°) and satisfying cos x = sin61° + sin470-sings-sini, is(A) 7°IS -(C) 13°(D) 17° |
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Answer» (A) 7° |
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| 20. |
hol (M) ksl (D)b 0 hhi ()sAve g g O I |
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Answer» Answer will be 11+5= 16as 2+2= 4now 4+3= 7now 7+4= 11 |
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| 21. |
10. Walls of two buildings on either side of a streetare parallel to each other. A ladder 5.8 m longis placed on the street such that its top justreaches the window of a building at the heightof 4 m. On turning the ladder over to the otherside of the street, its top touches the window ofthe other building at a height 4.2 m. Find thewidth of the street. |
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| 22. |
Fig. 2.2210. Walls of two buildings on either side of a street are parellel to each othei.A ladder 5.8 m long is placed on the street such that its top just reaches thewindow of a building at the height of 4 m. On turning the lodder over to the otherside of the street, its top touches the window of the other building at a height 42m.Find the width of the street. |
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Answer» The width of street = x + y So, we apply Pythagoras theorem: 5.8² = x² + 4² x² = 5.8² - 4² x² = 33.64 - 16 x² = 17.64 x = 4.2 m [ we ignore negative values as x is length] now, 5.8² = y² + 4.2² y² = 5.8² - 4.2² y² = 33.64 - 17.64 y² = 16 y = 4 So, width of street is x+ y 4 + 4.2 = 8.2m |
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| 23. |
5A ladder 15 m long reaches a window which is 9 m above the ground on one side of a street keeping itsfoot at the same point, the ladder is turned to other side of the street to reach a windows 12 m highFind the width of the street. |
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Answer» Didi please send it again it is not visible Very very much thank you |
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| 24. |
T AR "वि xm PRe ’mw«. iy |
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Answer» -8/3 is the answer of this |
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| 25. |
A ladder 15 m iong reaches a window which is 9 m above the ground on one side of a street keeping itsfoot at the same point, the ladder is turned to otherside of the street to reach a winctows 12 m high.Find the width of the street. |
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| 26. |
112Express each of the following rational numbers in power notation.() 2166859 |
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| 27. |
diameter of a cylinder is 28 cm and its height is 40cm. Find thesurface area, total surface area and the volume of the cylinder. |
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Answer» Thnx |
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| 28. |
6 m high and 04 m thick4. The inside measurements of a cardhoard hos are Im10 em by 7.5 em each can be arranged in jse bes? |
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Answer» We have to find the volume of box and one book and then divide it.Volume of cuboidal box= l x bx h = 3/2 x 100 cm x 3/4 x 100 cm x 60 cm = 150 cm x 75 cm x 60 cm = 675000 cm^3Volume of book = l x b xh = 20 x 10 x 7.5 = 1500 cm^3 now, 675000 / 1500 = 450so 450 books can be arranged in the box. Read more on Brainly.in - https://brainly.in/question/261096#readmore Thank you so much |
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| 29. |
Find the oth derivate OctSince sings Ginse. |
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Answer» in my head is not working properly configured form notifications add-on configuration 1|1|1|1|1|1|1|1|files transmitted a= sinAd= sin2A-sinAnth term =a+(n-1)d= sinA+(n-1)(sin2A-sinA)= sinA+n(sin2A-sinA)-sin2A+sinA= 2sinA-sin2A+n(sin2A-sinA) |
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| 30. |
26. A floor of length 35.14 cm x 5 cm. Findone tile costs Rs. 2.th 35m and breadth 20 m has to be paved by the tiles measuringFind the number of tiles required and cost of doing the same if27 The cost of 25 computers is Rs. 6,20,000. How many such computers canbebought for Rs. 14,16,800 if the price is increased by Rs 500, further?SIN28. Draw a Column graphfor the following data:NinaName of a student: Anu Kabir Joe Krish5570 408090Marks scored : |
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Answer» 27.56 computer. for rupees 1416800 27.56 computer. for rupees 1416800 this is very tuff questions |
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| 31. |
A salesman mixes two varieties of tea,whose costs are Rs, 60 and Rs. 45 per kgrespectively. In preparation of the mixture 2%tea is wasted. In what proportion the twovarieties are to be mixed so as to make a profitof 25%, the sale price being Rs.62.50 per kg?Ans. 4: 11[WBCS (Main), 2000] |
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Answer» Wrong |
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| 32. |
person own?ains. The total number of consis 94 anvalue is Rs. 29.75. Find the number of 50 paisa and 25 paisa coinsA bag has 50 paisa and 25 paisa coins. The totbairrorinrocals is Find the7. |
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Answer» 50 paisa 29.7525 paisa 59.5 |
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| 33. |
( a ) 3125 ( b ) 625 ( c ) 125 ( d ) 50 d |
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Answer» aOb=a^2+b^2so 1O2=1^2+2^2=1+4=55O5=5^2+5^2=25+25=50 |
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| 34. |
In the fig, APB& CQD are semicircle BSD are semicircle of diameter 7cm each, while ARCand BSD are semicircles of diameter 14 cm each. Find the perimeter of the shaded region(H-227)(Ans :66 cm) |
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| 35. |
36. A semicircle is drawn on AB as diameter. Let X be a point onAB. From X, a perpendicular XM is drawn on AB cutting thesemicircle at M. Prove that AX-XB=MX2 |
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| 36. |
20 In figure, APB is a semicircle with O as centre and AQO is a semicircle with AOas diameter. If perimeter of the figure is 40 cm find the area of the shaded region.(use-22 / 7) |
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Answer» so for this figure, there are 2 semicircles APB and AQO as AO=OB=r( given)Perimeter of shaded region = circumference of semicircle APB + circumference of semicircle AQO40 =πr +πr/2 80 = 3πrr= 80/3π ...........1 Now Area of shaded region =πr^2 +π(r/2)^2 = (5πr^2)/4 Putting value of r from 1we get area of shaded region as 283.09cm^2 |
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| 37. |
Mr. Sinha sold two tape-recorders to 990each; gaining 10% on one and losing 10% onthe other. Find his total loss or gain, aspercent, on the whole transaction. |
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Answer» total selling price = 990×2 = 1980 c.p of 1st = 990/1.1 = 900 rsC p of 2nd = 990/90% = 1100 Rs so, total C.P = 1100+ 900 = 2000 so, total loss % = (2000-1980)*100/2000 = 1% |
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| 38. |
Mr. Sinha sold two tape-recorders for? 990each; gaining 10% on one and losing 10% onthe other. Find his total loss or gain, aspercent, on the whole transaction. |
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Answer» total selling price = 990×2 = 1980 c.p of 1st = 990/1.1 = 900 rsC p of 2nd = 990/90% = 1100 Rs so, total C.P = 1100+ 900 = 2000 so, total loss % = (2000-1980)*100/2000 = 1% |
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| 39. |
Mr. Sinha sold two tape-recorders for 990each; gaining 10% on one and losing 10% onthe other. Find his total loss or gain, aspercent, on the whole transaction. |
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| 40. |
find the perimeter of the adjoining figure , which is a semicircle including it's diameter 10 cm |
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| 41. |
twire that has been bent in the form of a semicircle indlusiny Hstraightened and then bent in the form oĂ a square. The diameter of the semicircle is 14cma larger area, the semi-circle or the square? Also find the difference between themis i4cm. Which p |
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| 42. |
: Draw a circle of radius 3 cm. Draw a tangent to the circle making anangle of 30° with a line passing through the centre.circle with centre O and |
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| 43. |
1t. A circle of rais 2cm is cut out from a square piece of an aluminium6m What is the area of the left over aluminium sheet? (Takearn sheet of siπ=3.14) |
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| 44. |
216*a^3 - 125*b^3 |
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Answer» (6a)^3-(5b)^3 =(6a-5b)(6a^2+6a•5b+5^2) =(6a-5b)(36a^2+30ab+25b^2) |
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| 45. |
\sqrt [ 3 ] { 125 } \times \sqrt [ 3 ] { 216 } = |
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Answer» 5^3=125hence 3√125=5and 3√216=65*6=30 |
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| 46. |
Three angle of a quadrilateral in the salie1:23. The za mean of three angles in 32°find the love angle. |
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Answer» ratio is 1+2+3 =6x=32 x=32/6 ratio of three angles are 1:2:3 = 6x=32x=32\6 |
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| 47. |
है 0e मेक) + dono .. 9 (0१९९७९८० - . अटप 041 |
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Answer» hit like if you find it useful |
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| 48. |
52 Let a, b and с are three vectors such thatperpendicular to b, c makes angle 0 and ф witha and b respectively, then cos 0 cosp44 |
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| 49. |
2 If the supplement of an angle is three timesits complement, find the angle. |
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| 50. |
Use Euclid's division algorithm to find the HCFof:0) 135 and 225(ii) 196 and 38220(iii) 867 and 255 |
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