1.

Section13 A ladder 25m long reaches a window of a building 20m above the ground. Find the distancebetween foot of the ladder and the building.

Answer»

Applying Pythagoras theorem...AC^2=AB^2+BC^225^2-20^2=BC^2sqrt(625-400)=BCsqrt(225)=BC15 m=BC



Discussion

No Comment Found